The ratio of a base angle to a vertex degree of an isosceles triangle is 1:4. What is the top angle of this isosceles triangle?

The ratio of a base angle to a vertex degree of an isosceles triangle is 1:4. What is the top angle of this isosceles triangle?

180÷﹙1+1+4﹚×4
=180÷6×4
One hundred and twenty

Elementary school sixth grade mathematics: the degree of a base angle of an isosceles triangle is equal to 2 / 9 of the sum of internal angles, and its top angle Unit 3 and unit 4 test question 5 in volume A. It's better to have question 6 too. Ha ha, thank you!

One base angle is 2 / 9, two bottom angles are 4 / 9, and top angle is 5 / 9,
So the vertex angle is 180 × 5 / 9 = 100 °

An isosceles triangle, known that the top angle is three times of a base angle, find the degree of the top angle (need to have an equation)

180 △ (3 + 1 + 1) X3 = 108 degrees
So the degree of the vertex angle is 108 degrees

The top angle of an isosceles triangle is 96 degrees. How many degrees is its base angle

The sum of the interior angles of the triangle is 180 degrees, and the two base angles of the isosceles triangle are equal, so the base angle is 1 / 2 (180-96) = 42 degrees

In an isosceles triangle, the base angle is a ° and the degree of the top angle is expressed by the formula containing letters

180°-a°×2
=180°-2a°．
A: the degree of vertex angle is 180 ° to 2A °

The top angle of an isosceles triangle is 15 degrees more than the base angle of one side. What is the base angle of an isosceles triangle

Set the vertex angle X degree
x+2*（x-15）=180
x=70
Base angle 70-15 = 55 degrees

In the known diamond ABCD, ∠ a = 72 °, please design three different methods to divide the diamond ABCD into four triangles so that each triangle is an isosceles triangle (do not write the drawing method, indicate the degree of the vertex angle of the isosceles triangle)

As shown in the figure:

As shown in the figure, in the diamond ABCD, ∠ a = 72 °, please use three different methods to divide the diamond ABCD into four isosceles triangles, and mark the necessary number of angles

As shown in the figure:

Given that the line on the waist of an isosceles triangle is equal to half of the waist length, then the vertex angle of the isosceles triangle is equal to______ .

① As shown in the figure, △ ABC, ab = AC, CD ⊥ AB and CD = 1
2AB，
In ∵ ABC, CD ⊥ AB and CD = 1
2AB，AB=AC，
∴CD=1
2AC，
∴∠A=30°．
② As shown in the figure, △ ABC, the extension line of AB = AC, CD ⊥ Ba is at point D, and CD = 1
2AB，
∵∠CDA=90°，CD=1
2AB，AB=AC
,
∴CD=1
2AC，
∴∠DAC=30°，
∴∠A=150°．
So the answer is: 30 ° or 150 °

If the height of the base edge of an isosceles triangle is equal to half of the waist length, then the base angle of the isosceles triangle is equal to______ Degree

∵AD⊥BC，
∴∠ADB=90°，
∵AD=1
2AB，
∴∠B=30°，
∵AB=AC，
∴∠C=∠B=30°，
So the answer is: 30