Given the triangle ABC's three side lengths a, B, C, the absolute value of the root a minus B plus C square minus a square minus b square is equal to 0 What triangle is this triangle

Given the triangle ABC's three side lengths a, B, C, the absolute value of the root a minus B plus C square minus a square minus b square is equal to 0 What triangle is this triangle

A = B C square equals a square plus b square
isosceles right triangle

If a, B, C are the three sides of △ ABC, simplify the square absolute value of the root sign (a-b-c) b-c-a + the square of C-A-B under the root sign

Square of root sign (a-b-c) - absolute value b-c-a + square of C-A-B under root sign
=b+c-a-(c+a-b)+(a+b-c)
=b+c-a-c-a+b+a+b-c
=-a+3b-c

It is known that the three sides of the triangle ABC are a, B and C respectively, and the absolute value of c-1-2 under a square + B + root sign = 10A It is known that the three sides of the triangle ABC are a, B, C, which satisfies the absolute value of c-1-2 under a square + B + root sign = 10A + 2 and b-4-22 under the root sign. (1) judge the shape of triangle ABC. (2) use the hailun - --- Qin Jiushao formula s = P (P-A) (P-B) (P-C) where p = a + B + C / 2, the area of triangle ABC is obtained

(1) A? - 10A + 25 + (√ (B-4))? - 2 √ (B-4) + 1 + | (C-1) - 2 | = 0 (a-5) 2 + (√ (B-4) - 1) 2 + | (C-1) - 2 | = 0a-5 = 0, √ (B-4) - 1 = 0, √ (C-1) - 2 = 0A = 5b-4 = 1, B = 5c-1 = 2, 2 = 4, C = 5, so the triangle is an equilateral triangle (2) P = (5 + 5) / 2 =

if If 1 − 3a and | 8b-3 | are opposite to each other, then (1 ab)2−27=______ .

The meaning of the title is as follows:
1−3a+|8b-3|=0
∵1-3a≥0，|8b-3|≥0
∴1-3a=0，8b-3=0
∴a=1
3，b=3
Eight
∴(1
ab)2−27＝(1
One
3×3
8)2−27＝(1
One
8)2−27＝64−27＝37．
The result is: 37

Given that the absolute values of 1-3a and 8b-3 are opposite to each other under the root sign, find the value of (AB) - 2-27

∵ the absolute values of 1-3a and 8b-3 are opposite to each other
∴√(1-3a)+|8b-3|=0
∴1-3a=0
8b-3=0
∴a=1/3
b=3/8
The (- 2) power of (AB) - 27
=64-27
=37

It is known that 1-3a and | 8b-3 | are opposite to each other under the root sign. Find the value of AB of degree 3

That is, 1-3a + | 8b-3 | = 0
So 1-3a = 8b-3 = 0
a=1/3,b=3/8
So AB = 1 / 8 = (1 / 2) 3
So the third root sign AB = 1 / 2

Known 1 − 3a and B − 27 are opposite numbers to each other. Find the arithmetic square root of ab

According to the meaning of the title, 1-3a = 0, B-27 = 0,
The solution is a = 1
3，b=27，
So, ab = 1
3×27=9，
∵32=9，
The arithmetic square root of AB is 3

1) √ (1-3a) + (8b-3) square = 0, find the third root ab 2) The absolute value of X - √ 7 + (y + √ 1 / 7) square = 0, find the 2011 power of (XY) 3) The inverse of the reciprocal of 3 √ 2-2 √ 3 is All questions please add the complete process, thank you!

1, √ (1-3a) + (8b-3) 2 = 0, then 1-3a = 8b-3 = 0, a = 1 / 3, B = 3 / 8, 3 √ (AB) = 3 √ 1 / 8 = 1 / 2; 2, IX - √ 7I + (y + √ 1 / 7) 2 = 0, then x - √ 7 = y + √ (1 / 7) = 0, that is, x = √ 7, y = - √ 7 / 7, xy = - 1, (XY) ^ 2011 = (- 1) ^ 2011 = - 1

If the root number 1-3a + / 8b-3 / = 0, then the third root sign AB =? If the area of one face of a cube is 5, what is the volume of the cube? The square root of 27 and the arithmetic square root? Cube root of 0.0121? Third root 2.744= Root 6 * root 7 (the result is accurate to 0.01) 3 times root sign 8-3 times root sign 2 (keep 3 significant digits in the result) Radix 960000 / 12.56=

1. If root sign 1-3a + / 8b-3 / = 0, then 1-3a = 0 8b-3 = 0 a = 1 / 3 B = 3 / 8 cubic root AB = 1 / 2
2.5*6=30
3. Plus or minus 3 times root sign 3
Four
Five
6.6.48

The absolute values of (1-3a) and (8b-3) under the root sign are opposite numbers. It is necessary to find (AB) ^ - 2-27

1-3a=8b-3=0；
So a = 1 / 3;
b=3/8;
therefore
(ab)^-2-27
=(3/8×1/3)^(-2)-27
=64-27
=37;
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