If the root sign (a square - 3A + 1) + root sign b square + 2B + 1 = 0, find 1 - | B of a square + a square|=

If the root sign (a square - 3A + 1) + root sign b square + 2B + 1 = 0, find 1 - | B of a square + a square|=

solution
√a²-3a+1+√b²+2b+1=0
∴a²-3a+1=0
Divide both sides by a to get:
a-3+1/a=0
∴a+1/a=3
Square the two sides to get:
a²+2+1/a²=9
That is a 2 + 1 / a 2 = 7
And (B + 1) 2 = 0
∴b+1=0
∴b=-1
∴a²+1/a²-|b|
=7-|-1|
=7-1
=6

The square of a minus 2 root sign 3a, plus 3 △ a minus root sign 3 is equal to a²-2√3a+3÷（a-√3 (addition and subtraction of quadratic radical, division sign is fractional line)

Mark the questions clearly with a square root, or send them pictures, or you can't answer them
The original formula = (a - √ 3) 2 / (a - √ 3) = a - √ 3

Known: the square of root a + (B + 1) is equal to 0, find the value of 3A + 2B

The square root and square are greater than or equal to 0, and the sum equals 0
If one is greater than 0, the other is less than 0
So both are equal to zero
So a = 0, B + 1 = 0
a=0,b=-1
So 3A + 2B = 0-2 = - 2

The known number a satisfies | 2004 − a|+ A − 2005 = a, calculate the value of a-20042

According to the properties of quadratic radical, a-2005 ≥ 0, that is, a ≥ 2005,
From the original formula, a-2004+
a−2005=a
Qi
a−2005=2004
∴a-2005=20042
∴a-20042=2005．

The known number a satisfies | 2004 − a|+ A − 2005 = a, calculate the value of a-20042

According to the properties of quadratic radical, a-2005 ≥ 0, that is, a ≥ 2005,
From the original formula, a-2004+
a−2005=a
Qi
a−2005=2004
∴a-2005=20042
∴a-20042=2005．

|If 2004-A | + root sign (a-2005) = a, then the square of a-2004=

2004-a|+√(a-2005)=a
Because (a-2005) > = 0
So a > = 2005
So the formula is converted into:
(a-2004)+√(a-2005)=a
a-2004+√(a-2005)=a
√(a-2005)=2004
a-2005=2004^2
a-2004^2=2005

Under the square minus root sign of (a-2004), a-2005 = a, find the value of A

a=2049.343161

If the number a satisfies 2004-A + root a-2005 = a, find the square value of a-2004 (is "2004 square")

From the meaning of the title:
a-2005≥0
So a ≥ 2005
Therefore, the original formula can be transformed into:
A-2004 + Radix a-2005 = a
Radix a-2005 = 2004
a-2005=2004²
a=2004²+2005
therefore
The square of a-2004 = 2004? + 2005-2004? = 2005

Given the absolute value of the difference between 2400 and a, and the difference between a and 2005 under the root sign, the sum of the two is a. find a - "the quadratic of 2004" The answer is 2005,

2400 should be 2004
∵a-2005≥0
∴a>2004
Ψ a-2004 + root sign (a-2005) = a
Then a = 2004 ^ 2 + 2005
Then a-2004 ^ 2 = 2005

Given that the absolute value of 2004-x + root sign x-2005 is x, find the square value of x-2004

We know that x-2005 is x under the absolute value + root sign of 2004-x, find the square value of x-2004 | 2004-x | + √ (x-2005) = x, and find the value of (x-2004) 2. We can get x-2005 ≥ 0 ᙫ x ≥ 2005 ∣ 2004-x ∣ = - (2004-x) = x-2004