If the values of the algebraic expressions 2x-5 / x + 3 and 3-4x / 5 + 2x are opposite to each other, what kind of equation should x satisfy?

If the values of the algebraic expressions 2x-5 / x + 3 and 3-4x / 5 + 2x are opposite to each other, what kind of equation should x satisfy?

The algebraic expressions 2x-5 / x + 3 and 3-4x / 5 + 2x have opposite values
(2x-5)/(x+3)+(3-4x)/(5+2x)=0
(2x-5)(2x+5)+(3-4x)(x+3)=0
4x²-25+3x+9-4x²-12x=0
3x-12x=25-9
-9x=16
x=-16/9

It is known that the equation (2x-a) / 3 minus (x-a) / 2 on X has the same solution as equation 3 (X-2) = 4x-5, so find the value of A It is known that the equation (2x-a) / 3 minus (x-a) / 2 = X-1 and equation 3 (X-2) = 4x-5 have the same solution. How to solve the value of a?

3 (X-2) = 4x-5 substitute x = - 1 into (2x-a) / 3 minus (x-a) / 2 = X-1
3x-6=4x-5 a=-11
-x=1
x=-1

Given the solution of equation 3 (X-2) = 4x-5, that is, the solution of equation (2x-a) / 3 - (x-4) / 2 = X-1, find the value of A

3(X-2)=4X-5
3X-6=4X-5
X=-1
（2X-A）/3-（X-4）/2=X-1
(-2-A)/3+5/2=-2
(-2-A)/3=-9/2
(-2-A)=-27/2
A=23/2

It is known that the equation 2x-a / 3-x-a / 3 = X-1 and equation 3 (X-2) = 4x-5 have the same solution. To solve, find the value of A

Solution 3 (X-2) = 4x-5,
3x-6=4x-5,
x=-1
Because 2x-a / 3-x-a / 3 = X-1 has the same solution as equation 3 (X-2) = 4x-5
-2-a/3+1-a/3=-1-1,
a=3/2

Given that the equation a (2x-3) = 4x + B for X, what is the value of a and B ① The equation has a unique solution ② The equation has countless solutions ③ The equation has no solution That's right. Add it to 100

(1) if the equation has a unique solution, then 2a-4 ≠ 0, so a ≠ 2, B is any real number; (2) if the equation has countless solutions, then 2a-4 = 0, and 3a + B = 0, the solution is a = 2, B = - 6; (3) if the equation has no solution, then 2a-4 = 0, and 3a + B ≠ 0, the solution is

If the solution of the equation 2x-a = 0 on X is 2 larger than that of 4x + 7 = 3x + 8, find the value of A

By solving 4x + 7 = 3x + 8
x=1，
The solution of 2x-a = 0 is x = 3,
Substituting x = 3 into 2x-a = 0 gives a = 6

If the solutions of the equations 4x-2m = 3x + 2 and x = 2x-3m for X are the same, then M=______ .

4x-2m = 3x + 2; when the same kind of items are merged, x = 2m + 2 is obtained;
When x = 2x-3m items are combined with similar items, x = 3M is obtained;
∵ the equations about X, 4x-2m = 3x + 2 and x = 2x-3m, have the same solution,
∴2m+2=3m，
The solution is: M = 2
Therefore, fill in: 2

If the solution of equation 4x-3 = 2x + 3 and equation 3x + 7 = 3 (2x-1) - 2m are the same, then M= One

From 4x-3 = 2x + 3, we can get 4x-2x = 3 + 3, x = 3. Substituting x = 3 into the equation 3x + 7 = 3 (2x-1) - 2m, we can get 9 + 7 = 15-2m, 16-15 = - 2m, M = - 1 / 2

7 (2x-1) - 3 (4x-1) - 5 (3x + 2) + 27 = 0, how to solve the equation? According to the correct format

7（2x-1）-3（4x-1）-5（3x+2）+27=0
-13 (x-1)=0
X=1

Why is the solution of the equation 2x-4x = 2x-2x = 2m

4x-2m=3x+1
x=2m+1
x=2x-3m
x=3m
Double relation
So 2m + 1 = 2 × 3M
2m+1=6m
m=1/4