The angle α is known to be acute and sin2 α - sin α cos α - 2cos2 α = 0 (I) find the value of Tan α; (II) find sin (α - π) 3)．

The angle α is known to be acute and sin2 α - sin α cos α - 2cos2 α = 0 (I) find the value of Tan α; (II) find sin (α - π) 3)．

(1) From sin2 α - sin α cos α - 2cos2 α = 0, (sin α - 2cos α) (sin α + cos α) = 0 ∵ angle α is acute angle,

The negative quadratic power of 5 × (the fourth power of root five) + root sign 3 Tan 30 degree - | 3-radical sign 3|

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The negative quadratic power of 5 × (the fourth power of root five) + root sign 3 Tan 30 degree - | 3-radical sign 3|
=1/25x25+√3x√3/2-(3-√3)
=1+3/2-3+√3
=√3-1/2
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The 2012 power of (- 1) + | - radical 2 | - (2-radical 3) to the power of 0-radical 18

=1+√2-1-3√2
=-2√2

What is the zero power of negative root three? What is the negative quadratic power of minus sin30 degrees Why is the second one equal to four? Tell me how to calculate it? Thank you

1,4

Calculate: - 2 to the 2nd power - (root 2) to the 0 power - (sin30 degree + 1 / 2) to the 2011 power + 8x (2 root sign 2) to the - 2 power

-The 2nd power of 2 - (the 0 power of root 2) - (sin30 degree + 1 / 2) 2011 power + 8x (2 root sign 2) - power 2
=4-1-1+8X（1/8）
=3

Root 8-radix 2 times (Radix 3-radix 2) to the power of 0 + 1 / 2

Original formula = 2 root sign 2-radical 2x1 + 2
=Radical 2 + 2

Calculate [sin30 ° / (sin60 ° - cos45 °)] - (under the root sign (1-tan 60 °))) - Tan 45 ° please help me. Thank you

That is [1 / 2 / (√ 3 / 2 - √ 2 / 2)] - (√ 3-1) - 1 = √ 3 + √ 2 - √ 3 + 1-1 = √ 2

[sin30 ° / (sin60 ° - cos45 °)] - (under root sign (1-tan 60 °))) - Tan 45 °

[sin30 ° / (sin60 ° - cos45 °)] - (under root sign (1-tan 60 °))) - Tan 45 °
=(1/2)/[√3/2-√2/2]-√(1-√3)²-1
=1/(√3-√2)-(√3-1)-1
=√3+√2-√3+1-1
=√2

Sin 30 ° · Tan 45 ° + Radix 2 · cos 45 ° + sin 60 ° · Tan 60 °

Sin 30 ° · Tan 45 ° + Radix 2 · cos 45 ° + sin 60 ° · Tan 60 °
=1/2x1+√3x√2/2+√3/2x√3
=1/2+√6/2+3/2
=2+√6/2

The - 2 power of (- sin30), (- radical 2) 0th power, and the cubic power of (- Radix 3) are less than the upper case

(- sin30) - 2 times = 4
(- radical 2) 0 power = 1
The third power of (- radical 3) = - 3 Radix 3 < 0
therefore
The third power of (- Radix 3) ＜ (- Radix 2) 0 ＜ (- sin30) - 2