How many degrees of Tan equals to the root of three thirds
If tanw = √ 3 / 3, then w = k π + π / 6, where k ∈ Z
-How many degrees is the root of three equal to tan?
150 degrees
How many schools is Tan negative radical 3 equal to? How many pies is Tan radical 3 equal to? How many degrees?
The problem should be that Tan's faction is equal to minus root 3
K π - (π / 3), K is an integer
What degree is Tan (- root 3 / 3) equal to,
It's arctan, - 30 degrees. This is the basic trigonometric value,
What is the third degree root of Tan equal to
The inverse trigonometric function is aectan √ 3 / 2
It's about 40 degrees and 54 minutes
How many degrees is Tan equal to root 2?
If it is an approximate calculation, the process is as follows:
tan45=1
tanx=√2
tan60=√3
So:
(x-45)/(60-x)=(√2-1)/(√3-√2)
The results are as follows: 1
2.3x=123
x=53.5°.
How many degrees is the root of Tan minus three
150 or - 30
The solution set of inequality Tan (x + π / 4) ≤ radical 3 is obtained I worked out and the teacher's is not the same, but calculated many times the result is still the same--
Then for the interval [- π / 2 + K π, π / 2 + K π]
tan(kπ+π/3)=√3
Then K π - π / 2 ≤ x + π / 4 ≤ K π + π / 3
That is, K π - 3 π / 4 ≤ x ≤ K π + π / 12
That is to say, the solution set of the inequality is [K π - 3 π / 4, K π + π / 12], K ∈ Z
The solution set of the inequality Tan α + radical 3 > 0 is
That is tan α > - radical 3
That is, Tan α > Tan (- π / 3)
So K π - π / 3 < α
Using image to solve inequality: Tan (x + π / 6) ≤ radical 3
Draw y = TaNx image
Y-tanx is an increasing function on (K π - π / 2, K π + π / 2)
Tan (x + π / 6) ≤ radical 3 = Tan π / 3
kπ-π/2