Given that the acute angle of the line y = 2X-4 intersecting the X axis is a, find the four trigonometric function values of a?

Given that the acute angle of the line y = 2X-4 intersecting the X axis is a, find the four trigonometric function values of a?

tana=k=2
cota=1/2
sina=2/√5=2√5/5
cosa=√5/5

What is the relationship between the trigonometric function value of an acute angle and the trigonometric function value of its remainder? What is the relationship between the size of an acute angle and its trigonometric functions?

The trigonometric function value of an acute angle has the following relationship with the trigonometric function value of its remainder angle
sinA=cos(90°－∠A)
cosA=sin(90°－∠A)
tanA×tan(90°－∠A)=1
When the acute angle a increases, Sina increases,
When the acute angle a increases, Tana increases,
When the acute angle a increases, cosa decreases

How to find the trigonometric function of the largest angle in an acute triangle? Acute triangle, there is an angle to the side of the longest side of the triangle, known as the hypotenuse, so how to find this called trigonometric function?

In the triangle ABC, AB is the longest side, and the angle c is the largest angle. Through a, ad is perpendicular to BC and D sinc = ad / AC COSC = CD / AC Tanc = ad / DC COTC = 1 / Tanc

What is Tan 15 ° and what is Tan 2 θ equal to?

2-√3
2tanθ／1-tanθtanθ

Find the value of Tan 15 degrees I know there is a formula, but what does the formula mean

tan(A-B)=(tanA-tanB)/(1+tanAtanB)
Tan15 ° = Tan (45 ° - 30 °) = (tan45 ° - tan30 °) / (1 + tan45 ° tan30 °) = (1-1 / 3 under the root) / (1 + 1 / 3 under the root) = 2-under the root 3
This is the tangent formula derived from the sine cosine formula
sin(A+B)=sinAcosB+sinBcosA
cos(A+B)=cosAcosB-sinAsinB

tan15°=?

tan(15°) = 0.26794919243112

Read the following method to find the value of Tan 15 degrees, and follow this method to find the value of Tan 22.5 Make a right triangle with an angle of 30 degrees. In RT triangle, the angle B is equal to 90 degrees and the angle ACB is equal to 30 degrees Extend BC to d so that CD equals AC. if ad is connected, then angle D equals angle CAD equals 1 / 2 and angle ACB equals 15 degrees

According to the triangle constructed above, let the side length of a right triangle be: ab = 1, BC = sqrt (3), AC = 2, sqrt (3) denotes the root sign 3. B is a right angle

The process of Tan 15 value tan15=tan(45-30) =1-√3/3/1+-√3/3

(1 + √ 3 / 3) / (1 - √ 3 / 3) times (1 + √ 3 / 3), the result is: = (1 + √ 3 / 3) × [(1 - √ 3 / 3) × (1 + √ 3 / 3)] = (1 + √ 3 / 3) × [1 - (√ 3 / 3)] = (1 + √ 3 / 3) 2 × (2 / 3) = [3 × (1 + √ 3 / 3)] / 2 = [3 × (1 + 2

What is Tan 15 degrees equal to? How to prove it

If we use the geometric method to find: draw a right triangle ABC, such that ∠ C = 90 ° and ∠ ABC = 30 °, let AC = 1, then AB = 2, BC = √ 3
Extend CB to d so that BD = AB = 2, and connect ad, easy to obtain ∠ d = 15 °
In the right angle △ ADC, DC = 2 + √ 3
∴tanD＝AC/DC=1/(2+√3)=2-√3
That is, Tan 15 ° = 2 - √ 3

Evaluation: (tan15 ° - 1) / (1 + tan15 °)=

（tan15°-1）/(1+tan15°）
=-(1-tan15°)/(1+tan15°)
=-(tan45°-tan15°)/(1+tan15°tan45°)
=-tan(45°-15°)
=-tan30º
=-√3/3;
If there is anything you don't understand, you can ask,