It is known that a and B are real numbers and satisfy the following conditions: A is the cube root of - 8, B is the arithmetic square root of root number 81

It is known that a and B are real numbers and satisfy the following conditions: A is the cube root of - 8, B is the arithmetic square root of root number 81

-So the square root of - 8 is the square root of 9,
So a + 2B = - 2 + 2x9 = 16

The root sign 3 of 2a-b-1 is the cube root of 3. Find the value of a and B

√(a-2b+3)=√2,
a-2b+3=2
a-2b=-1.(1)
Similarly:
2a-b-1=3
2a-b=4...(2)
The result of (1) (2) is as follows
a=3,b=2

It is known that a = M-N root, M + N + 10 is the arithmetic square root of M + N + 10, and B = m-2n + the cube root of 4m + 6n-1, find the cube root of b-a It is known that a = M-N root, M + N + 10 is the arithmetic square root of M + N + 10, and B = m-2n + the cube root of 4m + 6n-1, find the cube root of b-a

From a = - N + m root sign m + N + 10 is the arithmetic square root of M + N + 10, we get: M-N = 2
From the cube root of B = - 2n + m + 3 root sign 4m + 6n-1, the cube root of B-A is obtained: m-2n + 3 = 3
The solution is: M = 4, n = 2
Then a = M-N root number m + N + 10 = 2 times root sign 16 = 4
B = m-2n + 3rd root 4m + 6n-1 = 3rd root 27 = 3

Known: B = 4 3a−2+2 2 − 3A + 2, find 1 A+1 The square root of B

According to the meaning of the title, 3a-2 ≥ 0 and 2-3a ≥ 0,
A ≥ 2 is obtained
3 and a ≤ 2
3，
∴a=2
3，
b=2，
One
A+1
B=3
2+1
2=2，
So, 1
A+1
The square root of B is ±
2．

Given that 1 / 5 of | 3a-b-7 | + root sign 2A + B-3 = 0, find the square root of a power of (B + a)

1 | 3a-b-7 | + radical 2A + B-3 = 0 3a-b = 72A + B = 3 a = 2 b = - 1 (B + a) the square root of a power = the square root of the second power of 1 = ± 1

Given the absolute value + radical 2A + B-3 = 0 of 3a-b-7, find the a power of the sum of B + a

3a-b-7=0
2a+b-3=0
∴a=2
b=-1
The a power of (B + a)
=(-1+2)²
=1

It is known that real numbers a and B satisfy the third power of (2a + 3b) = - 8, and the root number 3A + 5B = 2,

If 2A + 3B = - 2 3A + 5B = 2, then a = - 16, B = 10, then the square root of B-A = root 26

If the square root of 2a-1 is the square root of root B, then the square root of B to the power of a is

∵ (2a-1) = ± √ 3 (square on both sides)
∴2a-1=3
∴a=2
And ∵ B = ± 2
∴b=4
The a power of B = 4? = 16
The square root of it is ± 4

If the square root of the root a is equal to plus or minus 2, then a =? What is the square root of root 81? 16 and plus or minus 3

Only 4 with square root of ± 2 (can't be - 4, because negative number has no square root) because √ a = 4, so a = 16 (can't be - 16, the reason is the same)
First simplify √ 81 = 9, so the question actually asks you what is the square root of 9. So the answer is ± 3

Write all the numbers that meet the condition. (1) the number whose square root is equal to plus or minus 2 and sign 3 To process

(2√3)*(2√3)=4*3=12
(-2√3)*(-2√3)=4*3=12