When Tana = 3, is the square of sina + sinacosa + 3cosa = 3 / 2

When Tana = 3, is the square of sina + sinacosa + 3cosa = 3 / 2

The denominator is 1, and the homogeneous expression (sina2 + sinacosa + 3cosa2) / (sina2 + cosa2) is obtained by dividing cosa2 up and down
（tana2+tana+3/(tana2+1)=3/2

If Sina + 2cosa = 1, the value of Tana is

A kind of three-fourths

Sina + 2cosa = - 5 ^ (1 / 2), Tana = ()

From sin a + 2cosa = 5, sin a = - √ 5-2cosa 1
The square of sina + the square of cosa = 1
① (2) simultaneous solution
cosA=-2/5(√5)
sinA=-1/5(√5)
So tan a = Sina / cosa = 2

The function y = √ 2Sin (2x - π) cos (x + π) is an odd function with a period of 4 π, an even function with period B of 4 π and an odd function with a period of π / 2 Even functions with D period π / 2

Your original title should be: √ 2Sin (2x - π) cos (2x + π)
=√2sin2x cos2x
=√2/2sin4x
So it's an odd function with the C option t = π / 2

Is the function y = 2Sin (π / 2-2x) an odd or even function with the smallest positive period

y=2sin(π/2-2x)=y=2cos(2x)
It's even function
The minimum positive period is 2 π / 2 = π

Is the function y = cos ^ 2 (x - π / 2) even or odd? What is the minimum positive period?

y=cos^2(x-π/2)=sin²x=(1-cos2x)/2
So it's even
T=2π/2=π

Is f (x) = 2x + cos (PI / 2 + x) odd or even

f(x)=2x+cos(π/2+x)=2x-sinx
f(-x)=-2x-sin(-x)=-2x+sinx=-(2x-sinx)=-f(x)
So f (x) is an odd function

Is y = - xsinx odd or even

Even function. F (x) = - xsinx, f (- x) = xsin (- x) = - xsinx. So f (x) = f (- x)

Is xsinx even? Why As the title Another question: is SiNx an even function? Why

f(x)=xsinx
f(-x)=-xsin(-x)=-x(-sinx)=xsinx
F (x) = f (- x), so it's even

It is proved that f (x) = xsinx is an unbounded function on (0, + ∞)

Let x = 2K π + π / 2, K ∈ Z
Then f (x) = xsinx = 2K π + π / 2, K ∈ Z
Then K --- > + ∞, then f (x) -- - > + ∞,
So f (x) = xsinx is an unbounded function on (0, + ∞)