Find the value range of function y = (3-cos) / (2-cosx) RT

Find the value range of function y = (3-cos) / (2-cosx) RT

y=(3-cosx)/(2-cosx)
2y-cosxy=3-cosx
cosx(y-1)=2y-3
cosx=(2y-3)/(y-1)=2-1/(y-1)
-1

The function y = cosx The monotone increasing interval of 1 − SiNx is () A. （2kπ-3 2π，2kπ-π 2）（k∈Z） B. （2kπ-π 2，2kπ+π 2）（k∈Z） C. （2kπ-3π 2，2kπ+π 2）（k∈Z） D. （kπ-π 2，kπ+π 2）（k∈Z）

Since the function y = cosx1 − SiNx = cos2x2 − sin2x2cos2x2 + sin2x2 − 2sinx2cosx2 = 1 − tan2x21 + tan2x2 − 2tanx2 = (1 + tanx2) (1 − tanx2) (1 − tanx2) 2 = 1 + tanx21 − tanx2 = Tan (π 4 + x2), let K π - π 2 ＜ π 4 + x2 ＜ K π + π 2, K ∈ Z, X ∈ (2k

Find the single adjustment and subtraction interval of periodic maximum value of function y = SiNx ^ 4 + cosx ^ 4-3 / 4

y=(sinx^2+cosx^2)^2-2sinx^2cosx^2-3/4
=1/4-1/2sin2x^2
Y(max)=3/4
Y(min)=-1/4
Period = u
Simple decreasing interval (- U / 2 + K, U / 2 + k)

Monotone increasing interval of function y = SiNx / 2 (SiNx / 2 + cosx / 2)

Y = 1 / 2 (1-cosx) + 1 / 2 SiNx = 1 / 2 + 1 / 2 (SiNx cosx) = 1 / 2 + radical (2) / 2Sin (x-1 / 4 pie)
Monotone increasing interval: [- 1 / 4 + 2K, 3 / 4 + 2K] Thank you for your comments

The minimum positive period of the function y = (SiNx + cosx) 2 (x belongs to R)

y=(sinx+cosx)²
=sin²x+cos²x+2sinxcosx
=1+sin2x
The minimum positive period T = 2 π / w = 2 π / 2 = π

What are the minimum and minimum positive periods of the function y = SiNx cosx

y= sinx cosx = (1/2) sin(2x)
It is obvious from the properties of trigonometric functions that:
(when x belongs to all real numbers)
The minimum value is - 1 / 2; the maximum value is 1 / 2;
The minimum positive period is π

Find the period, maximum and minimum of the function y = SiNx + √ 3 * cosx

Y = 2 (1 / 2sinx + radical 3 / 2cosx)
=2(sinxcosπ/3+cosxsinπ/3)
=2Sin (x + π / 3) (sum difference product)
So the minimum period T = 2 π
When sin (x + π / 3) = 1, the maximum value is 2
When 2Sin (x + π / 3) = - 1, the maximum value is - 2
Hope to adopt, thank you! Do not understand can ask, online waiting

The minimum value of the function y = SiNx + cosx + 2 is______ .

Because the function y = SiNx + cosx + 2=
2sin（x+π
4）+2，
Sin (x + π)
4）≥-1，
So the minimum value of the function y = SiNx + cosx + 2 is: 2-
2．
So the answer is: 2-
2．

The maximum and minimum of the function f (x) = cos square x + root 3 SiNx times cos (need to solve the problem) is urgent

In this problem, the power is reduced first, and then the auxiliary angle is transformed into a trigonometric function of an angle
=Cos2x + 1 / 2 + radical 3 / 2 * sin2x
=Cos2x / 2 + radical 3 / 2 * sin2x + 1 / 2
=Sin (2x + 30 degrees) + 1 / 2
The problem is solved
The maximum is 3 / 2
The minimum is - 1 / 2

Let 0 | a | a | ≤ 2, and the function f (x) = cos | X - | a | SiNx - | B | is 0, the minimum is - 4, and the angle between a and B is 45 ° and | a + B |

Because (SiNx) ^ 2 + (cosx) ^ 2 = 1
So f (x) = 1 - (SiNx) ^ 2 - | a | SiNx - | B|
Let SiNx = M
Primitive functionalization - m ^ 2 - | a | m + 1 - | B | and - 1