Given the function f (x) = 2 √ 3sinx × sin (π / 2-x) - 2cos (π + x) × cosx + 2, find f (x) The known function f (x) = 2 √ 3sinx × sin (π / 2-x) - 2cos (π + x) × cosx + 2 Finding the minimum positive period of F (x) In the triangle ABC, ABC is the opposite side of ∠ a ∠ B ∠ C respectively. If f (a) = 4, B = 1, the area of triangle ABC is √ 3 / 2, calculate the value of A

Given the function f (x) = 2 √ 3sinx × sin (π / 2-x) - 2cos (π + x) × cosx + 2, find f (x) The known function f (x) = 2 √ 3sinx × sin (π / 2-x) - 2cos (π + x) × cosx + 2 Finding the minimum positive period of F (x) In the triangle ABC, ABC is the opposite side of ∠ a ∠ B ∠ C respectively. If f (a) = 4, B = 1, the area of triangle ABC is √ 3 / 2, calculate the value of A

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Given the function f (x) = 1 / 2Sin ^ 2x + √ 3sinx × cosx-1 / 2cos ^ 2x, find the minimum positive period of F (x)

f(x)=√3/2*(2sinxcosx)-1/2*(cos²x-sin²x)
=√3/2*sin2x-1/2*cos2x
=sin2xcosπ/6-cos2xsinπ/6
=sin(2x-π/6)
So t = 2 π / 2 = π

Given the function f (x) = sin Λ 2x + √ 3sinx cosx + 2cos Λ 2x (x ∈ R) (1), find f (x) The known function f (x) = sin Λ 2x + √ 3sinx cosx + 2cos Λ 2x (x ∈ R) (1) Finding the minimum positive period of F (x) (2) Finding monotone increasing interval of F (x) Ask for an answer

f(x)＝1/2*(1-cos2x)+√3/2*sin2x +1+cos2x=3/2+1/2cos2x+)+√3/2*sin2x=3/2+sin(2x+30*)
Minimum positive period T = 2 Pai / 2 = Pai
Monotone increasing interval: 2K * PAI - Pai / 2

The maximum value of the function f (x) = 2 √ 3sinx * cosx + 2cos ^ 2x + m on the interval [0, π / 2] is 2 In △ ABC, the sides of angles a, B and C are a, B, C, nof (a) = 1, SINB = 3sinc, and the area of triangle s is 3 √ 3 / 4. Find the side length a

M = - 1 a = 60 degree C = 1 b = 3 a = radical 7

Find the maximum value of the function f (x) = 2cos ^ 2x + 3sinx on [- π / 2, π / 2] RT It's the square of cosx. The square is written in it.

because:
f(x)=2cos^2(x)+3sinx
=2*[1-sin^2(x)]+3sinx
=-2sin^2(x)+3sinx+2
Let t = SiNx
Then: F (x) = - 2T ^ 2 + 3T + 2
=-2(T-3/4)^2+25/8
Because x belongs to [- π / 2, π / 2]
Then: T = SiNx belongs to [- 1,1]
When t = 3 / 4,
F (x) has a maximum value of 25 / 8
When t = - 1,
F (x) has a minimum value = - 3

Calculation of root 1 / 3x (2 roots 12-75)

Original formula = 1 / 3 * (2 √ 12 - √ 75)
=1/3*(4√3-5√3)
=-√3/3

Radix 12 * Radix 3-radix 3 * Radix 75

Root 12 * root 3 - root 3 * root 75
=6-15
=-9

The meaning of the root sign is the calculation method of the root sign and how to calculate it Please, but I don't know Who can tell me, please

The first one to put forward the root sign is to solve the Pythagorean theorem: at that time, someone found that when the isosceles right triangle, the two right sides are 1, and the hypotenuse is an irrational number

How to calculate (root 3 + root 6) + (root 6 - root 3)

(root 3 + root 6) + (root 6 - root 3)
=Root 3 + root 6 + root 6 - root 3
=(root 6 + root 6) + (root 3-root 3)
=Double root 6 + 0
=Double root 6

What is the root number?

The simplest way is to use a calculator
If you don't, you have to use an estimation method. For example, the root of 9.2 is 3. First, the integer part is 3. Then you try to find out whether 3.1 * 3.1 is appropriate or 3.2 * 3.2 is appropriate