How to calculate the third power of root 9 How to calculate between roots? For example, root 9 multiplies and divides root 3

How to calculate the third power of root 9 How to calculate between roots? For example, root 9 multiplies and divides root 3

The third power of root 9 is the multiplication of three Radix 9. The root 9 equals 3 and the result is 27
The root 9 multiplies and divides the root 3, that is, the root 3 equals the root 9 of the root 3. The root sign 27 equals to the 3 / 3 root sign 27. The root sign 27 equals to 3 times the root sign 3, that is, 3 / 3 times the root sign 3. The result is equal to the root 3 (this calculation problem is to rationalize the denominator, that is, to make the denominator with the root sign into a rational number)

Simplification: radical 169 × 196, Radix 6-radix 6 (Radix 6 + 1 / Radix 6) Simplification: Radical 169 × 196 Root 6 - root 6 (root 6 + 1 / root 6)

169 = 13*13 196 = 14*14
=Root 6 - 6 - 1 = root 6 - 7

Simplify [2 + root (2-root3)] under root sign and add [2-radical (2-root3)] under radical sign

Let a = √ [2 + √ (2 - √ 3)] > 0, B = √ [2 - √ (2 - √ 3)] > 0
a²＝2＋√﹙2－√3﹚,b²＝2－√﹙2－√3﹚
a²＋b²＝2＋√﹙2－√3﹚＋2－√﹙2－√3﹚＝4
a·b＝2²－﹙2－√3﹚＝2＋√3
The original formula = a + B = √ (a + b) 2 = √ (a ＋ B ＋ 2Ab)
＝√﹙4＋4＋2√3﹚
＝√﹙8＋2√3﹚.

Reducing radical ① 2A 3 B × root sign (a? B) × 3 × root sign (A / b) ② 3 / 10 × root sign (5ab in C) × 5 / 3 × root (2Ac in B)

=2a³b*a√b*3*√(a/b)=6a^4*b*√b
=(3/10)*√((5ab/c)*(2ac/b))*(5/3)=(√(10)/2)a²

1 / 2 of 3 Radical 2 Root 2 / 3

1 / 2 = 3 ×√ (1 / 2) = 3 ×√ 2 ×√ [(1 / 2) × 2] = 3 ×√ 2 ×√
Radical 2 can't be simplified any more
Two thirds of the root sign = √ (2 / 3) = √ [(3 × 2) / 3 × 3)] = √ (6 / 9) = (1 / 3) ×√ 6, or write = (√ 6) / 3

Reduction, evaluation: x2 − x x2−2x+1−x Where x + 1= 2．

Original formula = x (x − 1)
(x−1)2-x
X+1
=x(x+1)
(x−1)(x+1)-x(x−1)
(x−1)(x+1)
=2x
x2−1… (4 points)
When x=
At 2:00,
Original formula = 2
Two
22−1=2
2… (6 points)

Simplify and then evaluate: (1 + x ^ 2) / (1-x ^ 2) / (2x / 1-x - x), where x = radical 2

The original formula = (1 + x 2) / (1 + x) (1-x) / (2 x-x + x 2) / (1-x)
=(1+x²)/(1+x)(1-x)×(1-x)/x(x+1)
=(1+x²)/x(1+x)²
=(1+2)/[√2(1+√2)²]
=3/(3√2+4)
=(9√2-12)/2

First simplify and then evaluate: (2x + 1) (x-1) + X (radical 2 + 1-x), where x = - radical 2

Original formula = 2x? - X-1 + (Radix 2 + 1) x-x
=X? + root 2x-1
After substitution, the original formula = - 1

First simplify and then evaluate: (1 + X-1 / 2) / x-4 / x-2x + 1, where x equals root 2

=(x + 1 / 2) △ x-4 / X - 2x + 1
=(root 2 + 0.5) / 2-1-2 root sign 2 + 1
=0.5 root number 2 + 0.25-2 root number 2
=-(3 roots 2) / 2 + 0.25

(2x + 3) (2x-3) - 4x (4x-1) + (X-2) ^ 2, x = radical 3

(2x+3)(2x-3)-4x(4x-1)+(x-2)^2
=4x^2-9-16x^2+4x+x^2-4x+4
=-11x^2-5
X = radical 3
The above formula = - 11 * 3-5
=-38