X + 2 ≤ 2 / 3 (2x-1) to solve the inequality, X is greater than or equal to 8

X + 2 ≤ 2 / 3 (2x-1) to solve the inequality, X is greater than or equal to 8

x+2≤2/3(2x-1)
x+2≤4/3x-2/3
(1-4/3)x≤-2/3-2
-1/3x≤-8/3
X is greater than or equal to 8
x+2≤(2/3)(2x-1)
3 (x + 2) ≤ 2 (2x-1)
The result of removing brackets is: 3x + 6 ≤ 4x-2
6 + 2 ≤ 4x-3x
The reduction is: X ≥ 8
x+2≤(2/3)(2x-1)
3(x+2)≤2(2x-1)
2(2x-1)-3(x+2)≥0
x-8≥0
x≥8
x+2≤2(2x-1)/3;
x+2≤(4x-2)/3
3x+6≤4x-2;
x≥8
Knowing x ≠ 1 / 2 from the meaning of the title
2/3(2x-1)-x-2≥0
[2-3x(2x-1)-6(2x-1)]/3(2x-1)≥0
x-8≥0
x≥8
Write out the algorithm for solving the system of quadratic equations of one variable 3x-2y = 14 x + y = - 2?
3x-2y=14 (1)
x+y=-2 (2)
(1) + (2) * 2 gives 5x = 10
X=2
Substituting x = 2 into (2) yields
y=-4
∴x=2
y=-4
On the inequality X & # 178; - x + m ≤ 4 with only one solution, then the real number M =?
Please give me the detailed calculation process
X & # 178; - x + m ≤ 4 has and has only one solution
That is, X & # 178; - x + M-4 ≤ 0 has and has only one solution
(x-1/2)²+m-17/4≦0
M-17 / 4 = 0
M = 17 / 4, the solution is x = 1 / 2
According to the meaning (- 1) & # - 4 (M-4) = 0, M = 17 / 4
The sum of coefficients in the expansion of polynomial (2x ^ 2-5x ^ 2 + X + 1) * (2 / 3x-1) ^ 2 is
thank you
Let x = 1, the sum of the coefficients of the expansion is obtained
The sum of coefficients in the expansion = (2-5 + 1 + 1) * (2 / 3-1) ^ 2 = - 1 / 9
2 / 3x-1 I do it by (2 / 3x) - 1, which is the same as 2 / (3x-1)
What is the solution set of inequality | X-2 | 2x? Interval representation
(2 / 3, + ∞)
10> - 2. What about the process?
3x-2y = 8 ① 2Y + 3Z = 1 ② x + 5y-z = - 4 ③ solution
3x-2y=8① 2y+3z=1②x+5y-z=-4③
③×3-①：17y-3z=-20④
④+②：19y=-19,∴y=-1
Y = - 1 into ①: x = 2
Substituting y = - 1 into 2: z = 1
So x = 2, y = - 1, z = 1
Inequality for X (x-x & # 178; + 12) (x + a)
(x-x²+12)(x+a)0
(x+3)(x-4)(x+a)>0
① When a > 3, - A4};
③ When - 4
To find the sum of coefficients in the expansion of polynomial (2x ^ 3-5X ^ 2 + X + 1) ^ 3 * (2 / 3x-1) ^ 2, please write down the steps,
Let x = 1
Then the sum of the coefficients in the expansion of (2x ^ 3-5X ^ 2 + X + 1) ^ 3 * (2 / 3x-1) ^ 2 is
-1*（-1/3）^2=-1/9
If inequality | x-4 | + | 2x + 2|
This problem can be seen as finding the minimum distance between two points | x-4 | + | 2x + 2 | which can be seen as the sum of the distances to point 4 and point-1, so the answer is a less than or equal to 5. Please explain later
How to cancel the system of quadratic equations with one variable {3x-2y = 8 {y + 4x = 7} y
Do you mean to eliminate y
3X-2Y=8①
Y+4X=7②
Then put the form 2 variant: y = 7-4x
Substituting (1) into (1), we get:
3X-2（7-4X）=8
3X-14+8X=8
11X=22
X=2
Y=7-4X=7-4×2=-1
I don't know if this is the result you want
It's a solution
You can also multiply all the terms of formula (2) by 2 and add them to formula (1)
11x=22
X=2
The formula of 2 is 2Y + 8x = 14
1 + 2 is 3x-2y + 2Y + 8x = 8 + 14
The solution is 11x = 22
X=2
Y = - 1 that brings x = 2 into 1
So {x = 2}
{y=-1