Find the negative integer solution of inequality 3 (x + 1) less than or equal to 5x + 9

Find the negative integer solution of inequality 3 (x + 1) less than or equal to 5x + 9

Expand on the left, 3x + 3 ≤ 5x + 9
3x-5x ≤ 9-3
It is reduced to - 2x ≤ 6
Multiply both sides of the inequality sign by - 2 to get x ≥ - 3
And because of finding the solution of negative integer, X takes - 3, - 2, - 1
Read more textbooks and do more exercises. This problem is actually very simple
-3-2-1 question: is there a process?
If a is a rational number, the root of the quadratic equation x ^ 2 + 3 (A-1) x + (2A2 + A + b) = 0 is a rational number
Δ= 9(a-1)^2-4(2a^2+a+b)
= a^2-22a+9-4b
X1,2 = (- B plus minus √Δ) / 2A
Let the root of the equation be rational
The root sign Δ needs to be a rational number
Δ needs to be a perfect square
So Δ = 0 has two equal real roots
So Δ (Δ ') = 0 for Δ = 0
That is, Δ '= 22 ^ 2-4 (9-4b) = 0
So B = - 28
If the distance between point (4, a) and line 4x-3y-1 = 0 is not greater than 3, then the value range of a is ()
A. [0，10]B. [13，313]C. （0，10）D. （-∞，0]∪[10，+∞）
The distance d from point (4, a) to line 4x-3y-1 = 0 = | 16 − 3a − 1 | 42 + (− 3) 2 = | 15 − 3a | 5 ∵ D is not greater than 3, | 15 − 3a | 5 ≤ 3, which is reduced to | 15-3a | ≤ 15, - 15 ≤ 15-3a ≤ 15, 0 ≤ a ≤ 10, so a is selected
Ascending and descending permutations of algebraic expressions
The order of the cubic power of a simple power is - 0.0013
A.123 B.321 C.312 D.231
The cubic power of - 10x multiplied by the quadratic power of Y is - 10x & # 179; Y & # 178; the degree is 3 + 2 = 5
-The cubic power of 0.001x is - 0.001x & # 179; the number of times is 3
The cubic power of YX is (XY) &# 179; = x & # 179; · Y & # 179; the degree is 3 + 3 = 6
The order from small to large is 3 1 2 → C
Solving the system of inequalities x-3 (x-1) ≤ 7,1-2 / 3-5X
① In addition, X ≥ - 2
② So, X ＜ - 1 / 2
The solution set of inequality system: - 2 ≤ x < - 1 / 2
The integer x = - 2, - 1
The solution of quadratic equation of one variable: the square of 3x - 5x + 8 = the square of X - 4x + 4
3x^2-5x+8=x^2-4x+4
3x^2-5x+8-x^2+4x-4=0
2x^2-x+4=0
△=(-1)^2-4*2*4＜0
So the original equation has no solution
2x^2-x+4=0.△=1-4×2×4
If the distance between the point (a, 2) and the line 4x = 3Y + 2 = 0 is less than 4, then the value range of the real number a is
A-5
The distance from (a, 2) to the line 4x + 3Y + 2 = 0 is less than 4
According to the distance formula from point to line:
|4 * a + 3 * 2 + 2 | / radical (4 ^ 2 + 3 ^ 2) = 4
| 4a+8| = 20
| a+2| = 5
a+2 = ±5
A = - 2 ± 5 = - 7, or 3
-7
Rearrange the square of polynomial 7xy - 2x, the square of Y + cy - the cube of ax, 1 by the ascending power of X, 2 by the descending power of X
3 in descending order of Y 4 in ascending order of Y
1. Arrange CY & # 179; + 7xy & # 178; - 2x & # 178; y-ax & # 179 according to the ascending power of X;
2 in descending order of X - ax & # 179; - 2x & # 178; y + 7xy & # 178; + CY & # 179;
3. Arrange CY & # 179; + 7xy & # 178; - 2x & # 178; y-ax & # 179 according to the descending power of Y;
The ascending order of 4 y - ax & # 179; - 2x & # 178; y + 7xy & # 178; + CY & # 179;
In ascending order of X: y + Cy3 7xy2 - 2x2 - AX3
In descending order of X: opposite to above, slightly opposite
According to the descending power of Y: y + Cy3 7xy2 - AX3 - 2x2
Arranged by the ascending power of Y: opposite to above, slightly opposite
Solving the system of inequalities 5x + 5 < 35.5x + 5 < 8x-8
5x+5＜35
5x13/3
therefore
13/3
5x+5＜35
5x
1、 The length of the hypotenuse of a right triangle is 7cm, and one right side is 1cm longer than the other
Let a shorter right angle side length x, then x ^ 2 + (x + 1) ^ 2 = 49 x ^ 2 + x-24 = 0, X1 = (- 1 + root 97) / 2
X2 = (- 1-root 97) / 2 (rounding) the length of two right angle sides is (- 1 + root 97) / 2, (1 + root 97) / 2
Let a right edge be X
x^2+(x+1)^2=49
2*x^2+2*x-48=0
x^2+x-24=0
x=(√97-1)/2
So the two right angles are (√ 97-1) / 2 and (√ 97 + 1) / 2 respectively
Let the right angle sides be xcm, (x + 1) cm respectively,
Then x ^ 2 + (x + 1) ^ 2 = 49,
∴x^2+x-24=0,
∴x=(-1+√97）/2,
x+1=(1+√97）/2.
Let xcm + 1 be the length of the right angle
According to Pythagorean ideal x ^ 2 + (x + 1) ^ 2 = 7 ^ 2
(square of x) + (square of X + 1) = 49
The square of 2x + 2x-48 = 0
X = (- 1 + radical 95) / 2
It's the other side (2 + 1) / 95