When λ changes, what figure does the equation 3x + 4Y-2 + λ (2x + y + 2) = 0 represent? What are the characteristics of the figure?

When λ changes, what figure does the equation 3x + 4Y-2 + λ (2x + y + 2) = 0 represent? What are the characteristics of the figure?

When λ changes, the equation: 3x + 4Y-2 + λ (2x + y + 2) = 0 represents the intersection of the line 3x + 4Y-2 = 0 and the line 2x + y + 2 = 0, all lines except the line 2x + y + 2 = 0, including the line 3x + 4Y-2 = 0
Represents all lines passing through the intersection of the two lines. It's called the copoint linear system equation. You try.
3x + 4Y-2 + a (2x + y + 2) = 0 when a changes, what graph does the equation represent? What are the characteristics of the graph?
Represents the line cluster passing through the intersection (- 2,2) point of line 3x + 4Y-2 = 0 and line 2x + y + 2 = 0 (except line 2x + y + 2 = 0)
I agree with the answer from the first floor
When Z changes, what figure does the equation 3x + 4Y-2 + Z (2x + 2) = 0 represent? What are the characteristics of the figure?
This equation is a linear function equation
Simplify to
y=(2-x(2z+3)-2z)/4
k=-(2z+3)
Z increases, K decreases, Z is inversely proportional to the slope, 2Z = - 3, z = - 3 / 2, slope = 0
Vertical abscissa of straight line
How much is the solution of equation 5x minus 6 minus 4x + 1?
5/4 x – 6 – 4/5 x+1 = 0
5/4 x – 4/5 x = 5
(25x-16x)/20 = 5
9x= 100
X=100/9
-1/5
100 / 9 is right.
Factorization: 9x2-y2-4y-4=______ .
9x2-y2-4y-4，=9x2-（y2+4y+4），=9x2-（y+2）2，=（3x+y+2）（3x-y-2）．
Finding the minimum value of F (x) = x & # 178; - 2aX + 2 on [2,4]
Axis of symmetry x = a
When a ≤ 2, f (x) max = f (4) = 18-8a, f (x) min = f (2) = 6-4a
When 2
It is known that vectors E1 and E2 are not collinear. Vector a = 2E1 + E2, vector b = ke1-e2. When vector a is parallel to vector B, then K
Vector a = 2E1 + E2 vector b = ke1-e2
If vector a is parallel to vector B
Then a = TB
∴ 2e1+e2=t(ke1-e2)
∴ 2=tk,1=-t
∴ 2=(-1)*k
∴ k=-2
. vector a = 2E1 + E2 & nbsp; vector b = ke1-e2 & nbsp; when vector a is parallel, vector B & nbsp; K / 2 = - 1 / 1 & nbsp; & nbsp; k = - 2
When m changes, what figure does the equation 3x + 4Y-2 + m (2x + y + 2) = 0 represent? What are the characteristics of the figure?
This is a linear function, and the image is a straight line
When m changes, the slope will change, and the intercept on the axis will also change. Correspondingly, the straight line will also change. The law is very complex, and it is impossible to give the exact answer. What grade are you in? Do you really have such a problem to solve?
Figuratively speaking, like one of our screen savers, there is a straight line moving all the time
Note: / / is absolute value. Note: 4 * 3 is equal to four thirds
1、/1*3-1*2/+/1*4-1*3/+/1*5-1*4/+.+/1*2005-1*2004/=
2. If a and 3b are reciprocal to each other, - C and D * 2 are opposite to each other, and / X / = 1. Find the value of 3ab-2c + D + X
Man, I don't want to use * for semicolon, but I can't see the absolute value with / either. Let's live. Who told Bill Gates to build a keyboard?
On the first floor, I asked / X / = 1. Find the value of 3ab-2c + D + X.
If you write in more detail, it will be yours
1. The former term of each absolute value is less than the latter term, that is to say, the sign of absolute value should be removed and a negative sign should be added -（1/2005-1/2004）=1/2-1/3+1/3-1/4+1/4+1/5+…… +1/2004-1/2004+1/2005=1/2+1/2005=2003/...
1、=1*2-1*2005=2003*4010
2. When x = 1 = 2, when x = - 1 = 0
1. Original formula = - (1 / 3-1 / 2) - (1 / 4-1 / 3) - (1 / 5-1 / 4) -... - (1 / 2005-1 / 2004)
=-1/3+1/2-1/4+1/3-1/5+1/4-...-1/2005+1/2004
=1/2-1/2005
=2005/4010-2/4010
=2003/4010
2. ∵ a = 1 / 3B - C = - 2... Expansion
1. Original formula = - (1 / 3-1 / 2) - (1 / 4-1 / 3) - (1 / 5-1 / 4) -... - (1 / 2005-1 / 2004)
=-1/3+1/2-1/4+1/3-1/5+1/4-...-1/2005+1/2004
=1/2-1/2005
=2005/4010-2/4010
=2003/4010
2.∵a=1/3b -c=-2/d
Original formula = 3 × (1 / 3b) × b-2d / 2 + D + X
=1+1
=2
Original formula = 3 × (1 / 3b) × b-2d / 2 + D + X
=1-1
=0 ﹣ put away
Decomposition factor: x2-4y2 + 4y-1=______ .
X2-4y2 + 4y-1, = X2 - (4y2-4y + 1), = X2 - (2y-1) 2, = (x + 2y-1) (x-2y + 1), so the answer is: (x + 2y-1) (x-2y + 1)