Given the quadratic function FX = ax + BX + C, F-2 = F0 = 0, the minimum value of FX is - 1, find the analytic formula of the function

Given the quadratic function FX = ax + BX + C, F-2 = F0 = 0, the minimum value of FX is - 1, find the analytic formula of the function

f（-2）=f（0）=0
So let f (x) = KX (x + 2)
fmin=-1
So f (- 1) = - 1
We get k = 1
So f (x) = x (x + 2)
The sum of two, the product of two, the minimum, the opening up
The quadratic function FX satisfies F0 = F1 = 0, and the minimum value of function FX is - 1
1. Find the analytic expression of FX 2. Find the area s 3 of the closed figure enclosed by the image of FX and x-axis. The line y = KX divides s 2 into two parts with equal area and finds the value of K
1, Let f (x) = a (X-H) ^ 2 - 1, from F (0) = 0, f (1) = 0, two equations and two unknowns can solve a = 4, H = 1 / 2, so f (x) = 4 (x-1 / 2) ^ 2 - 1 = 4x ^ 2 - 4x 2, integrate f (x) on [0,1], take the absolute value s = 2 / 33, substitute the linear equation into the solution to get x = 0, x = (4 + k) / 4, and then for KX - 4x ^ 2 + 4x from 0 to (...)
The analytic formula is y = 4x * 2-4x. Not the rest. Calculus. Question: process... thank you
Given the quadratic function f (x) = 2x & # 178; + ax + B (a, B are constants), for any x ∈ R, f (1-x) = f (x + 3)
And f (x) + 2 = 0 has two equal real roots
F (1-x) = f (x + 3) indicates that the axis of symmetry is x = (1-x + X + 3) / 2 = 2
Then a / (- 4) = 2, so a = - 8, let's solve it by ourselves
When x = A / | a | + B / | B | + C / | C |, try to find the value of - 92x + 2 to the power of 2003 of X
kuai
If the product of three rational numbers a, B and C is negative and the sum is positive, we can see that only one of a, B and C is negative, then x = A / | a | + B / | B | + C / | C = 1, so the 2003 power of X - 92x + 2 = - 89
2 (1-x) = 2x (detailed process) is the solution of one variable linear equation,
2(1-X)=2x
2-2x=2x
-2x-2x=-2
-4x=-2
x=1/2
Decomposition factor: (1-x2) (1-y2) - 4xy=______ .
(1-x2) (1-y2) - 4xy = 1-x2-y2 + x2y2-4xy = 1-2xy + x2y2-x2-y2-2xy = (XY-1) 2 - (x + y) 2 = (XY-1 + X + y) (xy-1-x-y)
What the image of quadratic function y = ax & # 178; + X + A & # 178; - 1 (a ≠ 0) may look like
As shown in the figure, the image change of the quadratic function is given when a changes from - 5 to 5
Let x = [| a | / (B + C)] + [| B | (/ A + C)] + [| C | (a + b)], find the value of x ^ 19-32x + 2004
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The solution of the first order equation of one variable - 3x + 2 = x
4x=2
x=1/2
Transfer: 4x = 2
Then: x = 1 / 2
The result is - 3x-x = - 2
Merge the similar items to get: - 4x = - 2
Divide both sides of the equation by - 4 to get x = 1 / 2
Math talent?
You're not a student of grade one. You still ask this kind of questions
-3X+2=X
-3X-X=-2
-4X=-2
X=1/2
Factorization of (2x + 2Y) (2x-2y)
I know the answer is why the common factor before 4 (x'2-y'2) is 4 but not 2
Original formula = [2 (x + y)] [2 (X-Y)]
=4(x+y)(x-y)
Because there is a 2 in each one, and the multiplication of two is 4
2(x+y)*2(x-y)=4(x+y)(x-y)
（2x+2y)(2x-2y)
=[2(x+y)][2(x-y)]
=4(x+y)(x-y)
Original formula = [2 (x + y)] [2 (X-Y)]
=4(x+y)(x-y)
=4(x²-y²)
There are two factors