5x+x+56=74

5x+x+56=74

5x+x+56=74
6x=18
X=3
X=3
6x=74-56
6x=18
X=3
The original formula can be reduced to 6x = 18, so x = 3
How to solve the equation with 5.5x + 4.5X = 100?
5.5X+4.5X=100
10X=100
X=10
1 / 5 + 5 / 6 x = 6 / 5 solution equation
1 / 5 + 5 / 6 x = 6 / 5
5 / 6 x = 6 / 5-1 / 5
5 / 6 x = 1
X = 5 / 6
x=6/5
1/5+5x/6=6/5
5x/6=1
x=6/5
1 / 5 + 5x / 6 = 6 / 5
1+5x=6
5x = 6-1
5x=5
x=5÷5
X=1
It's very simple. X = 6 out of 5, don't you
1/5+5/6x=6/5
5/6x=6/5-1/5
5/6x=1
x=6/5
5x = 6 to solve the equation
If the coefficient is 1, x = 6 / 5 (i.e. 1.2)
From 5x = 6
x=1.2
Except for the past, it becomes x = 1.2
x=6÷5
x=1.2
5x=6
x=6/5=1.2
X=6/5 X=1.2
The quadratic function y = - 1 / 2x & # 178; - x + 3 / 2 is known
(1) In the given rectangular coordinate system, draw the image of this function, and write the axis of symmetry and vertex coordinates
(2) When - 2 ≤ x ≤ 2, what are the maximum and minimum values
Just solve the second problem. Thank you
The opening is downward, the axis of symmetry is x = - 1, and the axis of symmetry is exactly at - 2 ≤ x ≤ 2;
When y = - 2, the maximum value is obtained;
-In the range of 2 ≤ x ≤ 2, the farthest from the axis of symmetry is 2,
So, when x = 2, y has a minimum value, y = - 5 / 2;
Therefore, the maximum value is 2 and the minimum value is - 5 / 2;
If you don't understand, please hi me,
a=-0.5 b=-1,c=1.5.
Axis of symmetry = - B / 2A = - 1
Vertex = (4ac-b Square) / 4A = 2
Opening direction downward
The maximum value is 2 when x = - 1
The minimum value is = - 2.5 when x = 2
If AB is not equal to 0, try to write all possible values of 2 LAL / A + 3 B / LBL
0 2 -2
When a is a value, the solution of equation 4 (x + 2) - 5 = 3A + 2 is smaller than that of equation (3a + 1) △ 3 × x = a (2x + 3) △ 2
When a is a value, the solution of equation 4 (x + 2) - 5 = 3A + 2 is smaller than that of equation [(3a + 1) / 3] x = a (2x + 3) / 9A / 22
From 4 (x + 2) - 5 = 3A + 2, the solution is x = (3a-1) / 4;
From [(3a + 1) / 3] x = a (2x + 3) / 2, x = 9A / 2;
Known (3a-1) / 4-1 / 15
(3ax + 3) x2 two thirds
x1=(3a-1)/4
x2=9/2a
X1
If x2-4xy + 4y2 = 0, then the value of X: is
x2-4xy+4y2=0
(x-2y)^2=0
x-2y=0
x=2y
x:y=2y:y=2:1=2
x=2y
Complete square x-2y = 0
The value of X is a straight line
x=2y
The factorization results in (x-2y) ^ 2 = 0
x=2y
Solution: because x2-4xy + 4y2 = 0
(x-2y)^2=0
So x = 2Y
It is known that the image of quadratic function y = x & # 178; + 2x + m has and only has one common point with X axis
If P (n, Y1), q (n + 2, Y2) are two points on the image of the quadratic function, and Y1 > Y2, the value range of real number n is obtained
Given the square root of LAL = 2 - (2), the square root of LBL = 3-2 (2), and the square root of a + B = 2-1, find the value of a and B
If a = 2-2 ^ (1 / 2), B = 3-2 (2) ^ (1 / 2), then a + B = 5-3 (2) ^ (1 / 2) = [6-3 (2) ^ (1 / 2)] - 1 is not equal to 2 ^ (1 / 2) - 1. If a = 2-2 ^ (1 / 2), B = 2 (2) ^ (1 / 2) - 3, then a + B = 2 ^ (1 / 2) - 1, meet the requirements. If a = 2 ^ (1 / 2) - 2, B = 3-2 (2) ^ (1 / 2), then a + B = 1-2 ^ (1 / 2) -
We also know that a + B = √ 2-1 & gt; 0 among the above four values, only (2 - √ 2) + - 3 + 2A = - 3 + 2 times the square root of 2, B = 2, a = - 3 + 2 times the square root of 2, B = 2
Here's a very simple way.
From the meaning of the title, we can see that - 1 = 2-3
From the absolute value of a and B, we can judge that a = 2 - √ 2, B = 2 √ 2-3
A + B = √ 2-1 is brought in to verify, so a = 2 - √ 2, B = 2 √ 2-3.