To solve the equations of 5x + 0.8 = 5.6 and 1.4: x = 1:0.75 Online and so on, fast, fast, fast, fast, fast, fast, fast

To solve the equations of 5x + 0.8 = 5.6 and 1.4: x = 1:0.75 Online and so on, fast, fast, fast, fast, fast, fast, fast

5x + 0.8 = 5.6
5x = 4.8
5x=14.4
x=2.88
1.4:X=1:0.75
x=1.4*0.75
x=1.05
5 0
5-6 / 5x = 1 / 3 solution
5-6 / 5x = 1 / 3
Multiply both sides by 6 at the same time
30-5x=2
5x=30-2
5x=28
x=28/5
I'm glad to answer for you. The 1900 team will answer for you
Please click the [select as satisfactory answer] button below,
5-6 / 5x = 1 / 3, both sides multiply by 6 at the same time
30-5x=2
5x=30-2
5x=28
X = 28 / 5
Three times five
5-6 / 5x = 1 / 3
5-1 / 3 = 5x / 6
5x out of 6 = 14 out of 3
X = 14 / 3 ÷ 5 / 6
X = 28 / 5
5-6 / 5x = 1 / 3
30-5x=2
5x=30-2
5x=28
x=28/5
I'm glad to answer for you. I wish you progress in your study!
Please click the "select as satisfactory answer" button below, thank you!
How to solve the equation of 5 / 6 x minus 1 = 7 / 8
x*5/6-1=7/8
x*5/6=1+7/8
=15/8
x=15/8 *6/5
=9/4
Answer: 9 / 4
5/6x-1=7/8
5/6x=1+7/8
5/6x=15/8
x=15/8*6/5=9/4
It's nine fourths, two and a quarter
5x/6-1=7/8
5x/6=15/8
x=(15/8)*6/5
=9/4
5*x/6-1=7/8
5*x/6=15/8
x=9/4
9/4
5/6x-1=7/8
Multiply both sides of the equal sign by 48
40x-48=42
40x=90
x=9/4
Solve the equation 5x-1 of 8 = 7 of 4
Please
5x of 8 = 1 + 7 of 4
5 out of 8 = 11 out of 4
X = 11 / 4 ÷ 5 / 8
X = 22 / 5
5/8x-1=7/4
5/8x=11/4
x=11/4*8/5
x=22/5
(5x-1)/8=7/4
4*(5x-1)=8*7
20x-4=56
20x=60
X=3
5x-1 of 8 = 7 of 4 & # 160;
5x-8=14
5x=22
x=22/5
Hope to help you!
5x of 8 = 1 + 7 of 4
If you go to the denominator, you have to
5x=8+14
Merge the similar items to get
5x=22
If the coefficient is changed to 1, the result is as follows
x=4.4
Hope to help you!
16(5x+1)＝18(9x+1)−13(1−x)．
If you remove the denominator, you will get 4 (5x + 1) = 3 (9x + 1) - 8 (1-x). If you remove the brackets, you will get 20x + 4 = 27x + 3-8 + 8x. If you merge the items, you will get 15x = 9. If you change the coefficient to 1, you will get x = 35
The position reduction of the number ABC on the number axis | a + B | + | B + C | + | C + A|
The number axis is c b 0 a
The absolute value of B is greater than that of A
-b-a-b-c-c-a=-2b-2c-2a
The absolute value of B is greater than that of A. so | a + B | minus the absolute value is - b-a
The number axis is c b 0 a
The absolute value of B is greater than the absolute value of A. the absolute value of C is greater than the absolute value of A
A + B gets a negative number B + C gets a negative number C + a gets a negative number
|a+b|+|b+c|+|c+a|=-b-a-b-c-c-a=-2b-2c-2a
-2a-2b-2c
Finding the square of the polynomial 5x to the second power of - 7x + 13 and - 5-6x + 2x
The second half of the title is (5x) square and - 5-6x + 2 (twice of x), and is the one of subtraction, multiplication and division
If the line x-2y + 2 = 0 intersects the ellipse x2 + 4y2 = 4 at two points a and B, then | ab | = 0___ .
Because the straight line x-2y + 2 = 0 and ellipse x2 + 4y2 = 4 intersect at two points a and B, the solution of x-2y + 2 = 0x2 + 4y2 = 4 is x = 0y = 1 or x = - 2Y = 0, and the coordinates of a and B are (0,1), (- 2,0), so | ab | = (0 + 2) 2 + (1-0) 2 = 5, so the answer is: 5;
The quadratic function y = 2x & # 178; + x-3 is known
How many intersections does the function image have with the x-axis? And the coordinates of the intersections are obtained
Y = 2x & # 178; + x-3 = (2x + 3) (x-1) = 0, then x = 1, or x = - 3 / 2
So there are two intersections, which are (- 3 / 2,0) and (1,0)
If there is an intersection point with X axis, y = 0
Then 2x & # 178; + x-3 = 0
(2x+3)(x-1)=0
We get x = 1 or x = - 3 / 2
So there are two points of intersection, namely: (1,0) and (- 3 / 2,0)
Hope to help you, hope to adopt, thank you!
Given the position of ABC three numbers on the number axis as shown in the figure, the result of simplifying | a + B | - | C-B |, is_______ .
Picture:________ c______ 0___ a_________ b___
│a+b|-|c-b|
=a+b-(b-c)
=a+b-b+c
=a+c
According to the meaning of the title, the original formula = IC AI = 12