X squared-11x-12= Multiplication by cross

X squared-11x-12= Multiplication by cross

(x-12)(x+1)
Square of 11x = 2 to find x
x²=2/11
x²=22/121
So x = ± √ 22 / 11
The square of x = 2 / 11, x = 22 under the root of 11
When x is greater than or equal to - 1 and less than or equal to 2, what is the minimum and maximum value of the square of quadratic function y = - x
I need a detailed answer, thank you.
-1
When x = 2, the minimum value is - 4, and when x = 0, the maximum value is 0
-1
How to calculate the root number of 3 and the root number of 40
The root of 3 is the root of 40
=√2/(3√40)
=√80/120
=√5/30
It's equal to the root of 30. 10. Sorry, I miscalculated. The original formula will be reduced to one fifth of six times the root number, and the numerator denominator will be multiplied by the root number 5 to become the root number 5 of 30. I still don't know the root number 40 = root number (4 × 10) = 2 times root number 10 = 2 times root number (2 × 5) = 2 × root number 2 × root number 5. There's no problem with the rest. Child, ask the adults around you. ... unfold
Equal to the root of 30 10
It is known that x, y and Z are three nonnegative integers satisfying 3x + 2Y + Z = 5 and X + Y-Z = 2. If s = 2x + Y-Z, then the sum of the maximum and minimum of S is___ .
Method 1: to make s take the maximum, 2x + y the maximum, z the minimum, ∵ x, y, Z are three non negative integers, ∵ z = 0, solve the equations 3x + 2Y = 5x + y = 2, the solution is: x = 1y = 1, ∵ s the maximum = 2 × 1 + 1-0 = 3; to make s take the minimum, the equations 3x + 2Y + Z = 5 (1) x + Y-Z = 2 (2), (1) + (2) are 4x + 3y
When - 2 is less than x is less than 3, the maximum value of quadratic function y = x square - 2x + 3 is? And the minimum value is?
Y = x square - 2x + 3
=(x-1)^2+2
When - 2 is less than x is less than 3
When x = 1, there is a minimum value of 2
When x = - 2, the maximum value is: 11
y＝x²－2x＋3＝(x－1)²＋2
∵﹣2≤x≤3
When x = 1, y has a minimum value of 2
When x = - 2, y has the maximum value 11. Why does x = 1 have the minimum value? What is the maximum value when x = - 2?
(1) 3 times root number 2 + 2 times root number 8-root number 50 (2) root number 2 / 3 root number 12 + root number 3 plus (1)-
(1) 3 times root 2 + 2 times root 8-root 50
(2) 2 / 3 root 12 + root 3 plus 0 of (1-root 3)
I really need it. It would be better if I could explain it in detail
Double root 8 is equal to 4 times root 2 times root 50 is equal to 5 times root 2. This is a simple addition and subtraction. The answer is double root 2
The second question is not clearly described. According to what I read, the answer is 5
Given that 2x + Y-2 ≥ 0, x-2y + 4 ≥ 0 and 3x-y-3 ≤ 0, the maximum and minimum values of x ^ 2 + y ^ 2 are?
The maximum value is 13, the minimum value is 4 / 5x ^ 2 + y ^ 2 = R ^ 2, which is a circle with radius r at o point. The problem of maximum value and minimum value can be transformed into the problem of finding the maximum value of radius r square. 2x + Y-2 ≥ 0, x-2y + 4 ≥ 0, 3x-y-3 ≤ 0, which satisfies these three conditions is a triangle region in the first quadrant
Draw a sketch of the image of quadratic function y = 2x square plus 8x plus 134 (- 3 less than or equal to x less than or equal to 0), and say the maximum and minimum values according to the image
How to draw this! Ah, I don't quite understand,
This quadratic function is an opening upward, so the key is to find the lowest point of this function on the coordinate axis. Because I haven't done this topic for a long time, I just remember to use the method of calculus. When the original quadratic function of differential is proper 4x + 8 = 0, x = - 2, y has the minimum value. If I bring in x = - 2, y = 126. So the lowest point of the image is (...)
It is known that the length and width of a rectangle are 8 * radical 12 and 4 * radical 18 respectively, then its area is
Area = length * width
=8 * radical 12 * 4 radical 18
=8 * 4 * radical 4 * radical 3 * radical 9 * radical 2
=32 * 2 * radical 3 * 3 * radical 2
=192 * radical 6
S = 16 root number 3 * 12 root number 2 = 192 root number 6