X-2 / 5x = 9 / 10

X-2 / 5x = 9 / 10

x-2/5x=9/10
(1-2/5)x=9/10
3/5x=9/10
x=9/10÷3/5
x=1.5
Solving the equation x ^ 2 = 50-9.5x
x^2=50-9.5x
x²+19/2x=50
(x+19/4)²=50+(19/4)²
(x+19/4)²=1161/16
x+19/4=±(√1161)/4
X = (- 19 + √ 1161) / 4 or x = (- 19 - √ 1161) / 4
x^2=50-9.5x
X ^ 2 + 9.5x-50 = 02x ^ 2 + 19x-100 = 0 can't be factorized, you can do it yourself
X^2+9.5X-50=0,(9.5)^2-4*1*(-50)=290.25
X = (- 9.5 ± √ 290.25) / 2 has two solutions
5x + 0.7 × 4 = 6.5
5X+2.8=6.5
5X=6.5-2.8=3.7
X=3.7/5
X=0.74
It is known that a, B and C are three numbers which are not equal to 0 and satisfy ABC > 0, a + B + C
3 points to me ~ you can ask me later~/
Three
Three
Calculate (x2 power + 4y2 power) 2 power + (x-2y) (2y-x) (x + 2Y) 2 power
=(x quadratic + 4Y quadratic) quadratic - (x-4y quadratic) quadratic = 16x2 Y2
Let the following quadratic function formula y = x ^ 2-3x + 4, y = 2x ^ 2-3x + 1
I know how to do the collocation method in the quadratic equation of one variable. But the quadratic function will not!
To find the formula of the above two functions is a process
How to explain the formula simply and clearly again! The teacher said too fast. Thought we all understood!
Y = a (X-H) ^ 2 + k
Y = x ^ 2-3x + 4 = x ^ 2-3x + (3 / 2) ^ 2 - (3 / 2) ^ 2 + 4 = (x-3 / 2) ^ 2 + 7 / 4Y = 2x ^ 2-3x + 1 = 2 (x ^ 2-3x / 2) + 1 = 2 [x ^ 2-3x / 2 + (3 / 4) ^ 2 - (3 / 4) ^ 2] + 1 = 2 [x ^ 2-3x / 2 + (3 / 4) ^ 2] - 9 / 8 + 1 = 2 (x-3 / 4) ^ 2-1 / 8 if you don't understand, please ask and have a good study!
Given that a, B and C are not equal to 0, find all possible values of a | a | + B | + C | C | + ABC | ABC |
① When a, B and C are all positive numbers, the original formula = 1 + 1 + 1 + 1 = 4; ② when a, B and C have two positive numbers and one negative number, the original formula = 1 + 1-1-1 = 0; ③ when a, B and C have one positive number and two negative numbers, the original formula = 1-1-1 + 1 = 0; ④ when a, B and C are all negative numbers, the original formula = - 1-1-1-1 = - 4
If a polynomial is divided by 2x-1, the quotient is the square of X + 1, and the remainder is 5x, then the polynomial is?
(2x-1) (X & # 178; + 1) + 5x = 2x & # 179; + 2x-x & # 178; - 1 + 5x = 2x & # 179; - X & # 178; + 7x-1 A: this polynomial is 2x & # 179; - X & # 178; + 7x-1
（-x-2y）(x2-2xy+4y2)
How much is it
（-x-2y）(x-2y)^2
=-(x+2y)(x-2y)^2
The quadratic function y = x & # 178; + 2x-1 is known
Finding the axis of symmetry of vertex coordinates in the direction of opening
With the opening upward, the axis of symmetry is a straight line passing through the point (- 1, - 2) and parallel to y, and the vertex coordinates are (- 1, - 2)
On the other hand, (- 1, - 2) x = - 1
y=x²+2x-1
y=(x+1)²-2
Function opening up, vertex coordinates (- 1, - 2), axis of symmetry x = - 1
Opening direction: upward
Vertex coordinates: (- 1, - 2)
Axis of symmetry: x = - 1