![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
The number corresponding to point a on the number axis is - 5. Point B is on the right side of point A. electronic ant a and B move to the left at the speed of 2 units / s and 1 unit / s respectively in B. electronic ant a and B move to the left at the speed of 1 unit / s Ant C moves to the right at a speed of 3 units per second Let the time of their simultaneous departure be T seconds. Is there a value of t so that the distance between C and B is twice that between C and a? If there is a value of T, please explain the reason
There should be two. One is to the left of a and the other is to the right of A. let the distance between B and a be S1. On the right of a, the distance between C and B is s-4t, and the distance between C and a is s-5t. Because the distance between C and B is twice that between C and a, the solution of 2 (s-4t) = s-5t is t = s / 32
It is known that the corresponding numbers of a and B on the number axis are - 20 and 100 respectively
Ant P starts from point B and moves to the left at the speed of 6 U / S; ant Q moves to the right at the speed of 4 U / s at the same time. Question: if two ants meet at point C on the number axis, what is the number of point C?
Ant P starts from point B and moves to the left at the speed of 6 U / S; ant Q moves to the left at the speed of 4 U / s at the same time. Question: if two ants meet at point D on the number axis, what is the number of point d?
1. Suppose that after X minutes, two ants meet
Then: 6x + 4x = 120
x=12
4X12=48
48-20=28
So the number corresponding to point C is 28
2. Suppose two ants meet after y minutes
So 6y = 4Y + 120
y=60
4X60=240
240+20=260
So the number of left motion points is - 260
Let 6x + 4x = 120 x = 12 for x seconds
100-12*6=28
C:28
Let 6x-4x = 120 x = 60 for x seconds
-20-60*4=-260
D:-260
The coordinate of point a is negative 20, and that of point C is 40. An electronic ant beetle starts from point C and moves to the left at a speed of two units per second
1. What is the sum of the distances between the electronic ant a and ab when it comes to D at the midpoint of BC?
————a——b——d——c————
-20 x y 40
The sum of the distances d to a and D to B is two times the distance BD plus the distance ab
Then BD = DC
So the sum of distances is ab + BD + CD = 60
On the number axis, a = - 4, B = - 2, C = 3, how to move the two points in a, B, C to make the three points represent the same number
1. A moves 2 units to the right and C moves 5 units to the left
2. A moves 7 units to the right, B moves 5 units to the right
3. B moves 2 units to the left and C moves 7 units to the left
A move two units to the right C move five units to the left
There are three points A.B.C on the number axis, which represent - 3, 0 and 2 respectively?
(1) Point a does not move (- 3),
Point B moves 3 units (- 3) to the left and point C moves 5 units (- 3) to the left
(2) Point B does not move (0),
Point a moves 3 unit lengths (0) to the right and point C moves 2 unit lengths (0) to the left
(3) Point C does not move (0),
Point a moves 5 unit length (0) to the right and point B moves 2 unit length (0) to the right
First, find the average of the three points, that is s = (- 3 + 2 + 0) / 3 = - 1 / 3
So move A-8 / 3 grid to the right end of the number axis, B-1 / 3 grid to the left end of the number axis, and C-7 / 3 grid to the left end of the number axis
How can I make 1 + A + 2A equal to 0?
a＝－1/3
Here, a equals minus one-third.
When a = negative third, 1 + A + 2A = 1 + 3A = 1 + 10 (negative third x3) = 0
A is equal to - 1 / 3
∵ 1 ∵ 10 a ∵ 10 2A = 0 ∵ a = - 1 / 3
That is, 3A equals - 1, and a equals - 1 / 3
When a = - 1 / 3
How can I get 21 by adding, subtracting, multiplying and dividing five nines and brackets?
(99+9)÷9+9=21
(99+99)÷9=22
Is that what you want?
If Tana = 2, then sin ^ 2A + 2sinacosa=
According to the formula sin2a = 2tana / (1 + Tan & # 178; a) = 4 / 5
cos2A=(1-tan²A)/(1+tan²A)=-3/5
sin²A+2sinAcosA=1/2(1-cos2A)+sin2A=1/2(1+3/5)+4/5=8/5
Electric energy conversion
The air output per minute of a machine is 85, and the power is 450. How much is the power consumption for 8500 wind?
How do you get that 0.75?
To produce 8500 air volume, it takes 8500 / 85 = 100 minutes = (100 / 60) hours. The power is the electricity consumption of this machine for every hour of operation, which may be 450 watts. If you change it into kW, that is, 0.45 kW, the total consumption is 0.45 × 100 / 60 = 0.75 kwh = 0.75 degrees
If the air output per minute is 85, the air output per second is 85 / 60 = 1.41
Power is the power consumption per second! That is, every 1.41 air volume needs 450W electricity!
Power consumption = 8500 divided by 1.41 * 450 = 2712765w = 0.75 kwh!
Thank you!!!
four hundred and sixty-five thousand six hundred and forty-five
How much is a: B
choice
a. 4:1 b.4 what should be filled in
Answer: A, 4:1
The correct answer is a: B = 4:1
Choose a 4 to 1
So a: B = 4:1 = 1
RELATED INFORMATIONS
- 1. It is known that there are three points a, B and C on the number axis, which are negative 24, negative 10 and 10. Two electronic ants a and B are facing each other from two points AC at the same time, and the velocity of a is 4 units Three questions first and third solution, online chat, urgent! Question 1: how many seconds later, the distance from a to ABC is 40 units. Why does the title say that a starts from a, but other netizens say that a is between ab
- 2. Use a scale and a compass to make a line so that its length is 10 cm Please write the way, thank you!
- 3. Use a scale and a compass to make a line so that its length is 3 cm
- 4. The distance between the number axis and the point representing the number 2 is the root, and the number of 6 units long is
- 5. If a root of the equation 2x & # 178; + (T + 3) x-4 = 0 about X is a, and A-2 / a = 6, find the value of T
- 6. 1. The solution of equation (x-1) &# 178; = 4 is? 2, and the solution of one variable quadratic equation 1 / 4x & # 178; - 1 = 0 is? 3?
- 7. If the equation 2x & # 178; - x + a-5 = 0 has two roots, the value range of a is
- 8. Given that a root of the equation 4x & # 178; - 5kx + K & # 178; = 0 is x = 2, then K=
- 9. The probability of taking any two numbers a and B in the interval [0,1] so that the equation x ^ 2 + 2aX + B ^ 2 = 0 has two unequal real roots
- 10. If X1 = - 1 is a root of the equation x2 + MX-5 = 0 about X, then the other root of the equation is x2=______ .
- 11. The moving point a starts from the origin and moves along the negative direction of the number axis, while the moving point C on the number axis always moves along the number axis at a speed of 10 unit length / s Moving point a starts from the origin and moves in the negative direction along the number axis, while moving point B also starts from the origin and moves in the positive direction along the number axis. After 4 seconds, the two points are 20 unit lengths apart. It is known that the velocity ratio of moving point a and B is 2:3 (1). Calculate the velocity of two moving points (2). If two points a and B start from the positions marked in (1) at the same time, they move in the negative direction along the number axis according to the original velocity, A few seconds later, the origin is just in the middle of the two moving points (3) on the number axis, and the moving point C has been moving along the number axis at a speed of 10 unit length / second. When a and B start from the position marked in (1) and move in the negative direction of the number axis, the moving point will catch up with a and then return to B, and then reverse a when B meets. In this way, when B catches up with a, C stops moving immediately, How many unit lengths does point C move
- 12. On the number axis, point a stands for negative 6, and point B stands for positive 4. Please divide line AB into five equal parts, and the point is cdef from left to right. Write down the numbers they represent
- 13. A point on the number axis that represents an integer is called an integral point. The unit length of a certain number axis is 1 cm. If you draw a line AB with the length of 2008 cm randomly on the number axis
- 14. On the number axis, the distance from point a to the origin is 3, and the distance from point B to the origin is 4
- 15. On the number axis, points a and B represent rational numbers a and B respectively, and the origin o is just the midpoint of AB, then the value of (a + b) 100 + (A / b) 2008 is (a + b) 100 (A / b) 2008
- 16. On the number axis, O is the origin, a and B are - 8 and 2, respectively 1. Finding the length of ab 2. The moving point P starts from a and moves to the right along the number axis with a speed of 3 unit lengths per second; meanwhile, the moving point Q starts from B and moves to the left along the number axis with a speed of 1 unit length per second. When P and Q coincide, the two points stop moving at the same time. Let the movement time of the two points be T seconds, and a formula containing t be used to express the length of the segment PQ 3. Under the condition of (2), the distance from point P and Q to origin o is equal when t is the value And do timely explanation, the more detailed the better, 3Q~
- 17. As shown in the figure, point C is on the number axis, and AC: BC = 1:5, find the number corresponding to point C. 2) if a starts from a and B at the same time, the speed of a is 3 times slower than that of A Bit / s, meet 2 units from the origin, the equation graph is a straight line, a is - 10, B is 14
- 18. As shown in the figure, it is known that A.B.C is three points on the number axis, and the number represented by point C is 6, BC = 4, ab = 12 The moving point P.Q starts from A.C. at the same time, the point P-2 unit length per second has a uniform speed of work along the number axis, and the point Q-1 unit length per second has a uniform speed of work along the number axis to the left. Suppose the movement time is t (T > 0), and what is the value of T, one of the three points o and P.Q is exactly the midpoint of the line segment connected by the other two points
- 19. Given that points a, B and C are three points on the number axis, the number corresponding to point C is 6, BC = 4, ab = 12. (1) find the number corresponding to points a and B. (2) the moving points P and Q start from a and C at the same time. They move along the positive direction of the number axis at the speed of 6 units per second and 3 units per second, respectively. M is the midpoint of a and P, n is on C and Q, and CN = one third CQ. Let t (T > 0) be the moving time, When the number corresponding to n (expressed by the formula containing T) is the value of T, OM = 2bn
- 20. ∫ x radical (2x-x ^ 2) DX