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A and B trains leave from a and B at the same time. After five hours' meeting, the two trains still run at the same speed It takes another 4 hours to drive to B. It is known that car a travels 10 kilometers more per hour than car B. how many kilometers are there between the two places? 2. How many days will it take for the maintenance team to repair 1500 air tanks in 10 days with 30 people? How many days will it take to repair 9000 air tanks with 30 people The first question is not necessary 1. A and B trains leave from a and B at the same time. After 5 hours of meeting, the two trains still drive at the same speed, and then drive to B after 4 hours. It is known that car a travels 10 kilometers more per hour than car B. how many kilometers are there between the two places?
2. Set up a maintenance team to repair x gas tanks every day
30^10^x=1500
X=5
So 9000 divided by 60 divided by 5 = 30 days
It takes 30 days to repair 9000 gas tanks
1. If vehicle B travels x kilometers per hour, vehicle a will travel (x + 10) kilometers
The distance between the two places is y km
5(x+x+10)=y
9x=y
x=40,y=450
The distance between the two places is 450 km
Using equation a and B, the two trains run from two places 1500 kilometers apart and start at the same time. They meet six hours later. Car a travels 15 kilometers less than car B per hour. How many kilometers did the two cars travel when they met?
1 if the speed of car B is x, the speed of car a is x + 10, and the distance between the two places is 5 (x + X + 10)
4(x+10)=5x
The solution is x = 40
5(40+40+10)=450
2. It takes X days
（30+30）*x*（1500/）=9000
x=30
The two trains a and B leave each other at the same time. After five hours of meeting, the two trains run at the same speed, and then they arrive at their destination after four hours. It is known that a travels 10 kilometers more per hour than B. how many kilometers is the distance between the two places?
[10 △ 1-45] × (5 + 4), = [10 △ 15] × 9, = 50 × 9, = 450 (km). Answer: the distance between the two places is 450 km
A and B trains run 630 km from two places and run in opposite directions for 3 hours. It is known that the speed ratio of a and B trains is 4:3 to find the speed of B train
No equations
Speed sum: 630 △ 3 = 210 (km / h)
Speed of vehicle B: 210 ÷ (4 + 3) X3 = 90 (km / h)
630/3/(4+3)*3=90
630 △ 3 = 210 (km) speed and speed of two vehicles
210 × 3 / (4 + 3) = 90 (km)
A. Two cars B leave from a and B at the same time. After 4 hours, the two cars meet. The speed ratio of the two cars is 2:3. It is known that car a drives 50 kilometers less than car B
50÷(3-2)÷4
=50÷1÷4
=12.5
Speed of car a
12.5x2 = 25 km
A. Two cars B leave from a and B at the same time. After four hours, the two cars meet. The speed ratio of the two cars is 2:3. It is known that car a drives 50 kilometers less than car B. what is the speed of car a
Mathematics problem 1 (addition and subtraction of quadratic radical)
If there are rational numbers a and B, and root 8 + root 18 + root 1 / 8 = a + B root 2, find the value of a and B
Root 8 + root 18 + root 1 / 8 = a + B root 2,
2 radical 2 + 3 radical 2 + radical 2 / 4 = a + B radical 2
(5 + 1 / 4) radical 2 = a + B radical 2
So, a = 0, B = 5 + 1 / 4 = 21 / 4
When a car is moving in a straight line at a constant speed on a horizontal highway, it will be resisted by 5000 cattle. The distance that the car passes in one minute is 600 meters, so it is necessary to calculate the distance
1. Work done by the car in 10 minutes
2. The power of the car in 10 minutes
Force = resistance = 5000n in uniform linear motion
Work = 10 × 600 × 5000 = 3 × 10 ^ 7 J
Power = 3 × 10 ^ 7 / 10 / 60 = 50KW
8 bottles of mineral water 16 yuan, 2 bottles of pure milk 6 yuan, mineral water is cheaper than milk
From the unit price, a bottle of mineral water 2 yuan, a bottle of milk 3 yuan, mineral water is cheaper than milk
However, the nutritional value of milk is different from that of mineral water, and whether the capacity of a bottle of mineral water and a bottle of milk mentioned here is the same has not been informed. Therefore, it is impossible to judge
The speed ratio of car a and car B is 3:2. How many kilometers per hour are the speeds of car a and car B
Don't solve the equation!
240 △ 2.4 = 100 (km / h)
A = 100 × 3 / 5 = 60 (km / h)
B = 100 × 2 / 5 = 40 (km / h)
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The addition and subtraction of quadratic radical should be simplified
√3/√3+2-√12 10√2+3√5-7√2 5√12-3√8-2√27
3√20-2√45+9√5 （√6- √8/3）×√2 （2+3√2）(1-√2)
The addition of brackets, the spacing of the interval
Otherwise, the understanding is different
J the construction site needs to use 12m cubic meters of sand and stone to transport by truck with a load of 8t. How many trucks do you need to transport? {P sand and stone = 2.5 * 10 = 10 cubic kg / M
I converted it for you. 12 cubic meters of sand and stone is about 30 tons, 8 tons of trucks need 4 times
Eight ton trucks need to be pulled four times
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