A focal coordinate is F1 (0, - 13), and the absolute value of the difference between a point P and two focal distances on the hyperbola is 24

A focal coordinate is F1 (0, - 13), and the absolute value of the difference between a point P and two focal distances on the hyperbola is 24

The absolute value of the distance difference between a point P and two focal points on hyperbola is 24
That is, 2A = 24, a = 12, a focal coordinate is F1 (0, - 13), that is, C = 13
In hyperbola, C ^ 2 = a ^ 2 + B ^ 2
So B = 5
Hyperbolic standard equation
y^2/144-x^2/25=1
y2/5-x2/144=1
What is the hyperbolic equation that has a common focus with the ellipse x ^ 2 / 4 + y ^ 2 = 1 and passes through the point Q (2,1)
The focus of ellipse x ^ 2 / 4 + y ^ 2 = 1 is (- √ 3,0), (√ 3,0)
Let the hyperbolic equation be x ^ 2 / a-y ^ 2 / (3-A) = 1
Taking the point Q (2,1) into the above formula, the solution is a = 2 or a = 6
When a = 6,3-a
x^2/6+y^/3=1
If the ellipse x ^ 2 / 4 + y ^ 2 / A ^ 2 = 1 and the hyperbola x ^ 2 / A ^ 2-y ^ 2 / 2 = 1 have the same focus, then the hyperbolic equation is
If the ellipse X & # 178 / 4 + Y & # 178 / A & # 178; = 1 has the same focus as the hyperbola X & # 178 / A & # 178; - Y & # 178 / 2 = 1, then the hyperbolic equation is
x²-y²/2=1
Because an ellipse has the same focus as a hyperbola
So 4-A & # 178; = A & # 178; + 2
The solution is a & # 178; = 1
How many cubic centimeters of coal does a piece of honeycomb briquette need? There are 12 holes with a diameter of 2cm above the 8cm high hole
First calculate the volume of solid honeycomb briquette 2 * 3.14 * 6 * 6 * 8 = 1808.64
The volume of the small hole is 2 * 3.14 * 1 * 1 * 8 * 12 = 602.88
The solid minus the small hole is 1808.64-602.88 = 1205.76
There is soil in the honeycomb briquette, and the proportion is 3.14 * (12 / 2) ^ 2 * 8-12 * 3.14 * (2 / 2) ^ 2 * 8 = 602.8800 ~ ~ 603
V cylinder = bottom area * height = (12 △ 2) & # 178; × π × 8 = 288 π
V small hole = (2 △ 2) &# 178; × π × 8 × 12 = 96 π
V=288π-96π=192π≈603
(the company takes it by itself.).. )3( )
Tell me the question
Can you explain the formula in special relativity
M = Mo / √ {1 - (V / C) ^ 2}
M = quality of movement
Mo = mass at rest
V = speed of movement
C = speed of light
It shows that the mass of any object increases with the increase of velocity
When the speed is close to the speed of light, the mass is close to infinity, so the object cannot reach the speed of light
Well, it seems that this one has made it very clear, because C is a constant and M0 is a constant, so this formula represents the phenomenon that M changes with V.
In the triangle ABC, we know B = AC and COS B = 3 / 4. Let the vector Ba * BC = 3 / 2, find a + C. (a, B and C are the opposite sides of angles a, B and C respectively
Urgent!
Three
Who can tell me the summation formula of equal ratio sequence?
Chinese!
I'm really sorry, I don't understand!!!
A(1-q^n)/(1-q) (q≠1)
Q is the ratio and a is the first number
Summation formula of equal ratio sequence
When Q ≠ 1, Sn = A1 (nth power of 1-Q) / (1-Q) = (A1 anq) / (1-Q)
When q = 1, Sn = Na1
Summation formula of equal ratio sequence
When Q ≠ 1, Sn = A1 (1-Q ^ n) / (1-Q) = (A1 anq) / (1-Q)
When q = 1, Sn = Na1
(A1 is the first term, an is the nth term, q is the common ratio)
"2 ＾ 3" means the third power of 2, that is, 2 ＾ 3 = 2 * 2 * 2 = 8
Primary school answers Volume 1
Well, only the teacher knows this, right? We don't even have this pamphlet, so we can't answer it
Can you provide a graph of the relationship between the length and the velocity of special relativity, a graph of the relationship between the mass and the velocity, and a graph of the relationship between the time and the mass
I just need those three diagrams of the relationship between speed and mass, length and time. It's not very abstruse
m=m。 /(1-V ^ 2 / C ^ 2) ^ (- 1) and so on
As far as I know, in Einstein's theory of relativity, there are only relations between velocity and length, between mass and velocity, but not between time and mass
After correction, the phenomenon of superluminal velocity will appear, which Einstein refused to admit
The last one you wrote was changed from - 1 to - 2
This question is too high-end Go to the professional forum
In the triangle ABC, a = 2, C = 45 degrees, Cos2 / 2, B = 5 / 2 and 5. Find the area of triangle ABC
In the triangle ABC, a = 2
C = 45 degree cos 2 / 2, B = 5 / 2 and 5. Find the area of triangle ABC
SINB / 2 = (radical 5) / 5,
sinB=2sinB/2 *cosB/2=4/5,
cosB=3/5,
The height h of side BC through a and the perpendicular foot of BC are d,
Let CD = x, then ad = X,
b*sinB=x,
b*cosB=2-x,
tgB=x/(2-x)=4/3,
So the triangle area is (1 / 2) * 2 * (8 / 7) = 8 / 7