To solve the hyperbolic equation, it has the same focus as the ellipse x ^ 2 + 4Y ^ 2 = 64, and the absolute value of the distance difference between the point on the hyperbola and the two focuses is 1?

To solve the hyperbolic equation, it has the same focus as the ellipse x ^ 2 + 4Y ^ 2 = 64, and the absolute value of the distance difference between the point on the hyperbola and the two focuses is 1?

The absolute value of the distance difference between the point on the hyperbola and the two focal points is 1: 2A = 1, a = 1 / 2, the square of a = 1 / 4. From the ellipse, we can get the square of C = 64-16 = 48, the square of B = the square of C-A, and then we can write the hyperbolic equation
The focus is on the x-axis, the focal length is 10, and the absolute value of the difference between the distance between a point m on the hyperbola and the focus is equal to 6?
2c=10 c=5 2a=6 a=3 b=4 x^2/9-y^2/16=1
A cylindrical sand pile has a bottom area of 28.26 square meters and a height of 2.5 meters. How many meters can a 10 meter wide road be paved with 2 cm thick sand?
2 cm = 0.02 M, volume of sand pile: 28.26 × 2.5 = 70.65 (M3); length of paveable Road: 70.65 △ 10 × 0.02 = 70.65 △ 0.2 = 353.25 (m). Answer: paveable Road: 353.25 M
What is the most famous formula of special relativity?
Lorentz coordinate transformation x = γ (x-ut) y = y z = Z t = γ (t-ux / C ^ 2) (Note: γ = 1 / SQR (1-u ^ 2 / C ^ 2), β = u / C, u is the velocity in inertial frame.) relativistic mechanics (1) velocity Transformation: V (x) = (V (x) - U) / (1-V (x) U / C ^ 2) V (y) = V (y) / (γ (1-V (x) U / C ^ 2)) V (z)
Let m = (a, CoSb), n = (B, COSA), and m be parallel to n,
And the vector m is not equal to the vector n. (1) prove that a + B = 90 degrees, and find the value range of sina + SINB. (2) let Sina + SINB = t, express (Sina + SINB) / sinasinb as the function f (T) of T, and find the range of y = f (T)
There are a lot of questions. First of all, if vector m is parallel to vector n, there is a / b = CoSb / cosa. Then we get a / b = Sina / SINB from the sine theorem, we can get the equation Sina * cosa = SINB * CoSb. Because vector m is not equal to vector n, so a + B = 90 ° Sina + SINB = Sina + cosa = root 2 * sin (a + 45 °) we get the solution Sina + SINB = t
It is known that {an} is an arithmetic sequence, the sum of the first n terms is Sn; {BN} is an equal ratio sequence, and A1 = B1 = 1, A4 + B4 = - 20, s4-b4 = 43. (1) find the general formula of {an} and {BN}; (2) find the sum of the first n terms of {an · BN}
(1) Let n = − 3 D = n + 3 D = n − 3 D = n − 3 D = n − 3 D + 3 D = n − 3 D = n − 3 D = n − 3 D + 3 D = n − 3 D = n − 3 D = n − 3 D + 3 D = n − 3 D = n − 3 D = n − 3 D + 3 D = n − 3 D = n − 3 D = n − 3 D = (5 points) (2) TN = 1 · (- 3) 0 + 3 · (- 3) 1 + 5 · (- 3) 2 + +(2n − 1) · (− 3) n − 1 × (- 3) get: − 3tn
Sixth grade mathematics book unit 2 exercise 5 question 3.4 Jiangsu Education Press
Who has all the formulas of special relativity?
Relativistic mechanics (1) velocity transformation: V (x) = (V (x) - U) / (1-V (x) U / C ^ 2) V (y) = V (y) / (γ (1-V (x) U / C ^ 2)) V (z) = V (z) / (γ (1-V (x) U / C ^ 2)) (2) scale effect
In the triangle ABC, the opposite sides of the angles a, B and C are a, B and C respectively. The vectors M = (a, CoSb) and N = (B, COSA), and M is parallel to N, M is not equal to n
Finding the value range of sina + SINB
Vector M = (a, CoSb), n = (B, COSA), and M is parallel to n
∴acosA-bcosB=0
According to the sine theorem:
a=2RsinA,b=2RsinB
∴sinAcosA-sinBcosB=0
∴sin2A=sin2B
∵ m is not equal to n ∵ a ≠ B, a ≠ B
∴2A+2B=π
∴A+B=π/2
∴B=π/2-A,A∈(0,π/2)
∴sinA+sinB
=sinA+sin(π/2-A)
=sinA+cosA
=√2sin(A+π/4)
∵π/4
To find the formula for the sequence of equal ratio and difference, to find the sum and so on, write as many as you have,
Summation formula of arithmetic sequence:
1.Sn=n(a1+an)/2
2.Sn=na1+[n(n+1)d]/2
The summation formula of equal ratio sequence:
(1) Sn=(a1-anq)/(1-q) (q≠1)
(2) Sn=a1(1-q^n)/(1-q) (q≠1)
The general formula of arithmetic sequence and proportional sequence is as follows:
Arithmetic sequence an = a1 + (n-1) d. where D is the tolerance
An = A1 * q ^ (n-1), where q is the common ratio
The law between adjacent terms of arithmetic sequence and arithmetic sequence is as follows
Arithmetic sequence 2 * an = a (n-1) + a (n + 1), where D is tolerance
Equal ratio sequence (an) & sup2; = a (n-1) * a (n + 1), where q is the common ratio