The result of (3m ^ 3 * n ^ - 3) ^ 3 * (- Mn ^ - 3) ^ - 2 is reduced to the form with only positive integral exponential power?

The result of (3m ^ 3 * n ^ - 3) ^ 3 * (- Mn ^ - 3) ^ - 2 is reduced to the form with only positive integral exponential power?

(3m^3*n^-3)^3 * (-mn^-3)^-2
=9m^9/n^9*n^6/m²
=9m^7/n^3
The second power of (3m + 2n-16) and l3m-n-1l are opposite to each other
Find the value of M + n
If the numbers are opposite to each other, the sum equals 0
If one is greater than 0, then the other is less than 0
So both equations are equal to zero
So 3M + 2n-16 = 0 (1)
3m-n-1=0 (2)
(1)-(2)
3n-15=0
n=5,
Substituting (1), 3M + 10-16 = 0, M = 2
m+n=7
If M = 3T, n = 3M, t = - 3, then M + N + t=
3T is 3T
Three fourths divided by three fourths multiplied by a few fractions equals three fourths
A is a nonzero natural number
emergency
What is 3 / 4 divided by a equal to 3 / 4 times a fraction
3 / 4 divided by a = 3 / 4 times 1 / 4
=3/4a
It is known that the image of the first-order function y = KX + B passes through point P (1,2) and intersects point a with the positive half axis of X axis and point B with the positive half axis of Y axis. If Tan ∠ Pao = 12, the coordinates of point B are obtained
Let the coordinates of point a be (a, 0), as shown in the figure, then AQ = A-1. From the meaning of the title, we can see that Tan ∠ Pao = pqaq = 2A − 1 = 12, the solution is a = 5, that is, the coordinates of point a are (5, 0), OA = 5, because Tan ∠ Pao = oboa = 12, OA = 2ob = 5, so ob = 2.5. We know that B is on the positive half axis of Y axis, so the coordinates of B are (0, 2.5)
The monotone decreasing interval of the function y = | SiNx | + | cosx | is
Let f (x) = | SiNx | + | cosx |, f (x + π / 2) = | SiNx | + | cosx |, we know that f (x) = f (x + π / 2), so the period is π / 2, so we only need to draw [0, π / 2] image
0.6 = what percentage is equal to 60 percent?
 
Acute angle trigonometric function
In RT triangle ABC, angle ACB = 90 degrees, CD is perpendicular to AB and D. if BC = 15, ad = 16, calculate Tan angle ACD
AD*BD=CD^2
CD^2=16BD
CD^2+BD^2=BC^2=225
BD^2+16BD-225=0
BD=9 CD=12
Tan angle ACD = CD / BD = 4 / 3
It's a clever way
Find the decreasing interval of function y = cosx / (1-sinx)
Y = cosx / (1-sinx) = ((cosx / 2) ^ 2 - (SiNx / 2) ^ 2) / (cosx / 2-sinx / 2) ^ 2 = (cosx / 2 + SiNx / 2) / (cosx / 2-sinx / 2) = (1 + TaNx / 2) / (1-tanx / 2) = Tan (x / 2 + Pai / 4) is a monotone increasing function in the interval (k * Pai-Pai / 4, K * Pai + Pai / 4)
How many parts is nine divided by six seventh
9/(7/6)=21/2