Given that the solution of the equation 3m-x = 2m + 3 about X is 4, then what is the second power of m-2m =?

Given that the solution of the equation 3m-x = 2m + 3 about X is 4, then what is the second power of m-2m =?

3m-x=2m+3
The solution is 4
Then 3m-4 = 2m + 3
M=7
m²-2m
=49-14
=35
3m-x=2m+3
When x = 4,
Original formula = 3m-4 = 2m = 3
3m-2m=3+4
M=7
m²-2m
When m = 7,
Original formula = 7 & # 178; - 2x7
=49-14
=35
It is known that the solution of the equation 3m-x = 2m + 3 of X is 4
3m-4=2m+3
M=7
Original formula = M & # 178; - 2m
=7²-14
=49-14
=35
Two questions about trigonometric functions
1. In the triangle ABC, ab = AC, angle BAC = 120 degrees, BC = 2, root sign 3, find the perimeter of the triangle ABC
2. From the lighthouse 55 meters above the sea level, we received a signal for help from a sailing boat. From the lighthouse, we can see that the bow angle of the sailing boat is 21 degrees. How far is the sailing boat from the lighthouse? (accurate to 1 m)
(1) Because: ab = AC, ad = ad, angle ADB = angle ADC = 90 degrees, so: Triangle abd and triangle ACD are congruent triangle angle CAD = angle bad = angle BAC / 2 = 60 degrees BD = CD = BC / 2 = 2 * (3 ^ 0.5) / 2 = 3 ^ 0.5, angle B = angle c = 30 degrees, ad = AC / 2Ac ^ 2 = ad ^ 2 + CD ^ 2 = (AC /
Finding the minimum value and monotone decreasing interval of function y ≈ SiNx + cosx + 2
y=sinx＋cosx＋2=√2sin(x+π/4)+2
So the minimum value of Y is 2 - √ 2, where x + π / 4 = 2K π - π / 2, that is, x = 2K π - π / 4
The decreasing interval of y = SiNx + cosx + 2 = √ 2Sin (x + π / 4) + 2 is
2kπ+π/2≤x+π/4≤2kπ+3π/2
The solution is 2K π + π / 4 ≤ x ≤ 2K π + 5 π / 4
y≈???
2-2^1/2
The minimum is 2-radical 2
Minus interval [2K + 4, 2K + 5]
Six out of seven minus a quarter is a fraction
6/7-1/4=17/28
=17/28
17/28
seventeen-twenty-eighths
Acute angle trigonometric function in Junior Three
tan2°*tan4°* tan6°*.*tan88°
One in the middle of tan2 ° and multiply it to tan88 °
There should be process and result, thank you!
Tan88 = 1 / Tan (90-88) = 1 / tan2 in a right triangle ABC, the non right angle a is 88, and the other angle B is 2. Tana = BC / AC, tanb = AC / BC -- if a = a, then Tan (90-a) = 1 / Tana. Similarly, tan86 = 1 / Tan (90-86) = 1 / tan4 Tan46 = 1 / Tan (90-46) = 1 / tan44
Tana * COTA = 1, that is: Tana * Tan (90-a) = 1
The multiplication of the first and the last equals 1, the multiplication of the second and the penultimate equals 1 There are 44 pairs, and the last one is 1
What's the derivative of SiNx times the square of cosx
sinx*cos²x=-cos²x*(cosx)'
∴ (-cos³x)'=-3cos²x*(cosx)'=3cos²x*sinx
The derivative of (- 1 / 3) cos & # 179; X + C is SiNx * cos & # 178; X
What are 1.4, 7.6, 3.5, 4.8?
7/5
38/5
7/2
24/5
Five and one in six is four and a few
7/5 38/5 7/2 24/5
The problem of acute angle trigonometric function in Junior Three
In the second semester of junior high school, I just learned the inverse proportion function. Today, I saw the acute angle trigonometric function in junior high school. It said: Tana = the opposite side of angle A / the adjacent side of angle A. but angle a has two adjacent sides, so which one should be used to calculate Tana?
Tana = opposite side of angle A / adjacent side of angle A. This only applies to right triangles. The opposite side and adjacent side of angle a are two right sides of right triangles, not hypotenuses
No two adjacent sides are one opposite side, one adjacent side and one beveled side. After confirming the opposite side, we can see that the short side is the adjacent side, and the long side is the beveled side
…… If you are curious, you'd better borrow a book for the second semester of junior high school. It's basic knowledge
The adjacent side here refers to the adjacent side of the right angle side of this angle in a right triangle
I guess you don't quite understand. I suggest you get a math book for the second semester of the third year of junior high school
We should use the right angle side, not the hypotenuse side
Two right angle sides, one hypotenuse, Tana equals the opposite side of angle a divided by the other right angle side
Given SiNx + cosx = (√ 3) / 3, what is the value of sin2x?
sinx+cosx=(√3)/3
Square on both sides
(SiNx) ^ 2 + 2sinxcosx + (cosx) ^ 2 = 1 / 3
(sinx)^2+(cosx)^2=1
2sinxcosx=sin2x
So 1 + sin2x = 1 / 3
sin2x=-2/3
sinx+cosx=(√3)/3
Square of two sides:
(sinx)^2+(cosx)^2+2sinxcosx=1/3
1+sin2x=1/3
sin2x=-2/3
If one tenth of the students in class 51 are transferred to class 52, the number of students in the two classes will be equal
The original number of class 51 is unit "1"
Original 1-1 / 10-1 / 10 = 4 / 5 in class 52
The original number of class 52 is 4 / 5 of class 51
8 / 10 for example, if there are 100 people in class 51, then 1 / 10 people is 10, and there are 90 people left in class 51, which means that there are 80 people in class 52, so 80 / 100 is 8 / 10