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Factorization method: in solving quadratic equation of one variable, factorization first makes the equation into the form that the product of two quadratic equations is equal to 0, and then makes the product of two quadratic equations equal to 0 Factorization method: when solving quadratic equation of one variable, factorization first makes the equation into the form that the product of two quadratic equations is equal to 0, and then makes the two quadratic equations equal to 0 respectively, so as to realize (). This method is called factorization method
Factorization method: in solving quadratic equation of one variable, factorization first makes the equation into the form that the product of two quadratic equations equals 0, and then makes the two quadratic equations equal to 0 respectively, so as to realize (solve). This method is called factorization method
The method of finding its solution
The equation (X-5) (x + 1) = 16 is decomposed into two quadratic equations with one variable by factorization
(x-5)(x+1)=16
x²-4x-21=0
（x-7）（x+3）=0
The solution is x = 7 or x = - 3
If you don't understand,
x^2-4x-21=0
x-7=0
x+3=0
The root of (x-3) (x + 3) + (x-3) x = 0 is -
(x-3)(2x+3)=0
x1=3
x2=-1.5
（3x+1）²-（4x+13）²=0
Using the square difference formula
（3x+1）²-（4x+13）²
=（3x+1-4x-13）（3x+1+4x+13）
=（-x-12）（7x+14）=0
So x = - 12 or - 2
（3x+1）²-（4x+13）²=0
（3x+1+4x+13)(3x+1-4x-13)=0
(7x+14)(-x-12)=0
7x+14=0 -x-12=0
x1=-2
x2=-12
How many days will it take for an engineering company to lay an underground natural gas pipeline in Yinchuan city to complete the project 5 days ahead of schedule and increase the original work efficiency by 10%?
Suppose that the original plan to complete the project takes X days, and the original work efficiency is 1. Then: 1 × x = (1 + 10%) × (X-5), the solution is: x = 55. Answer: the original plan to complete the project takes 55 days
x²（x-1) - 4x(x-1) - 12
I'm sorry. I have a wrong number x & sup2; (x-1) & sup2; - 4x (x-1) - 12
If it's X & sup2; (x-1) & sup2; - 4x (x-1) - 12 = (x (x-1) - 6) (x (x-1) + 2) = (x-3) (x + 2) (X & sup2; - x + 2) if it's X & sup2; (x-1) - 4x (x + 1) - 12 = x & sup3; - 5x & sup2; - 4x-12 = x & sup3; - 6x & sup2; + X & sup2; - 4x-12 = x & sup2
x(x－1)－4x(x－1)－12＝0
x＾2－x－4x＾2＋4x－12＝0
x＾2－x＋4＝0
b＾2－4ac＝1－16＜0
So there is no solution
Simple
This problem can not be solved in the rational range, there is a root is 5 / 3 + (394 + 36 times root 113) ^ 1 / 3 + (394-36 times root 113) ^ 1 / 3
x^2(x-1)^2 -4x(x-1)-12=[x(x-1)-6][(x(x-1)+2]=(x^2-x-6)(x^2-x+2)=(x-3)(x+2)(x^2-x+2)
4x²=（3x-1）²
A:
4x²=(3x-1)²
(2x)²=(3x-1)²
So: 2x = 3x-1 or 2x = - (3x-1)
When 2x = 3x-1: x = 1
When 2x = - (3x-1): x = 1 / 5
So: the solution of the equation is X1 = 1, X2 = 1 / 5
Xiao Ming and Xiao Liang set out from a and B at the same time at 8 a.m., facing each other. It is known that Xiao Ming's speed is 2km faster than Xiao Liang's. The distance between them is 36km at 10 a.m. and 36km at noon. What is the distance between a and B?
Let the speed of the small light be x and the distance between the two places be y
Then the relationship at 10 o'clock is: 2x + 2 (x + 2) = y-36
The relationship at 12 o'clock is: 4x + 4 (x + 2) = y + 36
Solve the equation x = 17, y = 108
Therefore, the distance between the two places is 108 km
Let the speed of Xiaoliang be x km / h and the distance between AB and ab be y km
Then 2 * x + 2 * (x + 2) + 36 = y
4*X+4*（X+2)-36=Y
We can get x = 17, y = 108
Let the light speed be XKM / h
4x+4(x+2)-2x-2(x+2)=2*36
4x+4=72
4x=68
x=17
A: the original distance is 2 * 17 + 2 * 19 + 36 = 108 (km)
The answer is over
They walked two hours first, and then two hours later, they walked 72, so the front was 72, so the total length was 72 plus 36, so they got 108.
1.(x+y)²-4（x+y-1)
2.(x-y)²+4xy
3.(x-1)(x+3)+1
1.(x+y)²-4（x+y-1)=(x+y)²-4(x+y)+4=(x+y)²-2×2(x+y)+2²=(x+y-2)²2.(x-y)²+4xy=x²-2xy+y²+4xy=x²+2xy+y²=(x+y)² 3.(x-1)(x+3)+1=x²+2x+1-3=(x+1)&su...
.1,(x+y)²-4（x+y-1)=.(x+y)²-4(x+y)+4=(x+y-2)²
2,.(x-y)²+4xy=x²-2xy+y²+4xy=x²+2xy+y²=(x+y)²
The original formula of 1 = (x + Y-2) & sup2;
2 the original formula = (x + y) & sup2;
3 original formula = (x + 1 + √ 3) (x + 1 - √ 3)
4x²÷3x²=?
4x²÷3x²=4÷3=4/3
4 / 3 of the four directions
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