How to solve the inequality 3x + 6 > 15?

How to solve the inequality 3x + 6 > 15?

3x+6>15
3x>15-6
3x>9
x>9/3
X>3
3x+6>15
3x>15-6
3x>9
x>9÷3
X>3
3x> 15-6
3x > 9
So x > 3
3x>9
X>3
15-3x ≤ X-1 solution inequality
15-3x≤x-1
-3x-x≤-1-15
-4x≤-16
x≥4
15-3x≤x-1
-3x-x≤-1-15
-4x≤-16
x≥-16/(-4)
x≥4
Solve the following inequality (1) X-5 / 2 + 1 > x-3 (2) - X / 5 + X / 15 ≤ - 1 (3) 1 / 3-2 < 1-1 / 5x (4) x - (3x-1) ≤ x + 2
(1) The two sides of X are eliminated, and the result is - 3 / 2 > - 3, which is always true, X ∈ R (that is, X is an arbitrary number)
(2) If - 2x / 15 ≤ - 1, X ≥ 15 / 2
(3) If - 8 / 3 < - 1 / 5x 3 / 8 < 5x, X > 3 / 40
(4) If x-3x + 1-x-2 ≤ 0 - 3x-1 ≤ 0, X ≥ - 1 / 3
Solving inequality 3x + 1 / X-1 ≥ 5
3x + 1 / X-1 is greater than or equal to 5,
(x-1)/(3x+1)≥5
(x-1-15x-5)/(3x+1)≥5
(14x+6)/(3x+1)≤0
-6/14≤x≤-1/3
And ∵ x ≠ - 1 / 3
∴-6/13≤x
What is the solution set of inequality 3x-1 < x + 5?
It's X
Formula of physical area method
In physics V-T diagram and x-t diagram, some unknown quantities (such as displacement) can be calculated by area method. Do you need any explanation or formula in the process of solving the problem? If so, please list
The area in the V-T graph is the displacement,
As long as a simple explanation: the displacement is the size of which area in the V-T diagram, and what can be obtained from the area formula .
Solving equation 20-4 (3x + 2) = 4 + 4x
20-4(3X+2)=4+4X
20-12X-8=4+4X
4X+12X=20-8-4
16X=8
X=8÷16
X=0.5
20-12x-8=4+4x
16x=8
x=1/2
20-4(3X+2)=4+4X
20-12X-8=4+4X
4X+12X=20-8-4
16X=8
X=8÷16
X=0.5
20-4(3X+2)=4+4X
20-12x-8=4+4x
16x=8
x=1\2
Calculate the values of (3x + y) ^ 2, (- 2x-3y) ^ 2 and (3 / 4x-2) ^ 2 respectively
(3x+y)^2=9x^2+6xy+y^2
(-2x-3y)^2=4x^2+12xy+9y^2
(3/4x-2)^2==9/16x^2-3x+4
Let a = {X - 5 ≤ x ≤ 3}, B = {x 4}, find a ∩ B, (CRA) ∩ (CRB)
Let a = {X - 5 ≤ x ≤ 3}, B = {x 4},
A∩B={x|-5≤x<-2}
(CRA)∩(CRB)
=((-∞,-5)∪(3,+∞))∩([-2,4])
={x|3<x≤4}
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If you don't understand this question, you can ask,
Find the linear equation perpendicular to the line 3x + 2y-6 = 0 and the sum of intercept on two coordinate axes is - 2
The slope is 3 + 2-6
Let the linear equation be y = 2 / 3x + B
Let x = 0, y = B
Let y = 0, x = - 3B / 2
b-3b/2=-b/2=-2
So B = 4
So the equation is y = 2 / 3x + 4