What is the integer solution of the system of inequalities - 3 less than or equal to 2 / 2 - 3x + 1 less than or equal to 2

What is the integer solution of the system of inequalities - 3 less than or equal to 2 / 2 - 3x + 1 less than or equal to 2

Multiply by 2
-6
Is the integer solution of the inequality system {3x + 1 > 8,2 / 2 x + 1 greater than or equal to X-1?
7/3＜x≤3
Inequality of 10-7x less than 6-3x solution
10-7x
X>1
If 10-7x is less than 6-3x, the shift term is less than 4x and the solution x is greater than 1
10-7x
Solving inequality (- 3x ^ 2 - 7x + 14) / (x ^ 2 + 3x-4) ≥ - 2
The process of answering questions
(3x²+7x-14)/(x²+3x-4)≤2
(3x²+7x-14)/(x²+3x-4)-2≤0
(3x²+7x-14-2x²-6x+8)/(x²+3x-4)≤0
(x²+x-6)/(x-1)(x+4)≤0
(x-2)(x+3)(x-1)(x+4)≤0
Using the combination of number and shape, odd through even not through, and the denominator is not 0
that
——-（-4）——（-3）——1——2
X
How to deduce the formula of circle area
S = circumference * square of radius
It seems that the circle is decomposed into many squares at the beginning. Generally, you just write down the formula!!!
A. (x-2y) (2Y + 3) B. (x-2y) (- x + 2Y) C. (x-2y) (- x-2y) d. (x-2y) (2y-x)
Say why?
C.(x-2y) (-x-2y)
There are two items, one is the same and the other is opposite
In the second bracket of item B, a negative sign becomes the square of - (x-2y)
3x-2y=1 5x+3y=8 3y-6z=-1
3x-2y=1 ①
5x+3y=8 ②
3y-6z=-1③
①×3+②×2
9x+10x=3+16
19x=19
X=1
∴3-2y=1
Y=1
∴3-6z=-1
z=2/3
That is: the solution of the equations is x = 1; y = 1; Z = 2 / 3
For what? Question: how to solve the equation
Given the function f (x) = loga (x + 1), G (x) = loga (4-2x) (a > 0, and a ≠ 1); (I) find the domain of definition of function y = f (x) - G (x); (II) find the range of values of X that make the value of function y = f (x) - G (x) positive
(I) we can get x + 1 ＞ 04 − 2x ＞ 0 and the solution is - 1 ＜ x ＜ 2. We can get that the definition domain of function f (x) is (- 1,2). (II) f (x) = f (x) - G (x) = log a (x + 1) - log a (4-2x) = log a & nbsp; X + 14 − 2x, & nbsp; When a ＞ 1, from x + 14 − 2x ＞ 1 − 1 ＜ x ＜ 2, the solution is 1 ＜ x ＜ 2, so the value range of X is (1,2). When 0 ＜ a ＜ 1, from 0 ＜ x + 14 − 2x ＜ 1 − 1 ＜ x ＜ 2, the solution is - 1 ＜ x ＜ 1, so the value range of X is (- 1,1)
Factorization (X & sup2; + Y & sup2; - A & sup2;) & sup2; - 4x & sup2; Y & sup2;
(x²+y²-a²)-4x²y²
(x²+y²-a²)²-4x²y²=（x²+y²-a²+2xy)(x²+y²-a²-2xy)=[(x+y)²-a²][(x-y)²-a²]=(x+y+a)(x+y-a)(x-y+a)(x-y-a)
A: use the square difference formula
(x²+y²-a²)-4x²y²
=(x²+y²-a²-2xy)(x²+y²-a²+2xy)
=[(x-y)²-a²]*[(x+y)²-a²]
=(x-y-a)(x-y+a)(x+y-a)(x+y+a)
(x²+y²-a²)²-4x²y²
=(x²+y²-a²+2xy)(x²+y²-a²-2xy)
=[(x+y)²-a²][(x-y)²-a²]
=(x+y+a)(x+y-a)(x-y+a)(x-y-a)
The calculation formula of circumference length is as follows:______ The calculation formula of circle area is as follows:______ .
The radius of a circle is represented by the letter R, the diameter by the letter D, and the area by the letter S. the circumference formula of a circle is C = 2 π r = π D, and the area formula of a circle is s = π R2, so the answer is: C = 2 π r = π D; s = π R2