The inequality KX ^ 2-2x + 6K about X is known

The inequality KX ^ 2-2x + 6K about X is known

kx²-2x+6k
Higher one inequality: the square of known inequality KX - 2x + 6K
This problem is actually very simple
First, K ^ 2-2x + 6K = K (x-1 / k) ^ 2 + 6k-1 / K
If the system of inequalities {2x-m ＞ 1,3x-2m ＜ - 1} about X has no solution, the value range of M is obtained
From (1)
2x>m+1
∴x>(m+1)/2
From (2)
3x=4m-2
∴m
Given that the inequality system {2x-m > 2 about X has no solution, find the value of M {3x-2m
2x-m>2
3x-2m
Factorization 2x ^ 2-2xy-3y ^ 2
In this case, you take y as 1 and solve the equation 2x ^ 2-2x-3 = 0 to get x = (1 + - radical 7) / 2
So the answer is [X-Y (1 + radical 7) / 2] [X-Y (1-radical 7) / 2]
If you have to break it down
2[x-(1+√7)y][x-(1-√7)y]
The process is to let 2x & # 178; - 2x-3 = 0 to get x = 1 ± √ 7
Radical 2 (x-x1) (x-x2) = 0
2x²-xy-3y²
=(2x-3y) (x + y) question: it's XY minus twice
In deriving the formula for calculating the area of a circle, the circle is divided into several parts and put together into a rectangle similar to human beings. The length is 6.42 meters more than the width. What is the area of a circle in square centimeters
R=6.42/(3.14-1)=3
S=3.14*3^3=28.26
Length of rectangle = half circumference of circle = 3.14 * radius
Width of rectangle = radius
Therefore, the radius is 6.42 / (3.14-1) = 3M
Circular area = 3.14 * 3 * 3 = 28.26 square meters = 282600 square centimeters
How much does the sum of 3x-5y + Z and - 2x + 4y-3z add to make it equal to - 3x + 4y-6z? How do you calculate it?
15X+13Z+2Y
-4x+5y-4z
The system of equations {2x-y = 5,3x-2y = 8} after eliminating y, the obtained equation is
6. The equation {2x-y = 5} is ()
{3x-2y=8
A.3x-4x+5=8 B.3x-2(5-2x)=8 C.3x-4x+10=8 D.3x-4x-10=8
2x-y=5
y=2x-5
3x-2y=8
y=3x-8/2
2x-5=3x-8/2
4x-10=3x-8
3x-4x+10=8
Choose C
Multiply 2x-y = 5 by 2 and subtract to get x = 2
Let a be greater than 0A and not equal to 1, and f (x) = a ^ LG (x ^ 2 + 1) has the maximum value, then the solution set of inequality loga ^ (x ^ 2-5x + 7) 0 is
X ^ 2 ≥ 0, so x ^ 2 + 1 ≥ 1, so LG (x ^ 2 + 1) ≥ 0
∵ a > 0 and a ≠ 1, f (x) = a ^ LG (x ^ 2 + 1) has the maximum value,
If f (x) = a ^ LG (x ^ 2 + 1) is a decreasing function,
∴0＜a＜1,
Therefore: loga ^ (x ^ 2-5x + 7) is a decreasing function,
Log a ^ (x ^ 2-5x + 7) 0, we can get 0 ＜ x ^ 2-5x + 7 ＜ 1, we can get 2 ＜ x ＜ 3 by solving the inequality
novel
If the difference of solution x y of binary linear equations x + 2Y = 5K, 3x + 7Y = k-1 is 17, the value of K is obtained
The reduction is: x = 33K + 2; y = - 1-14kx-y = 33K + 2 + 1 + 14K = 17; the reduction is: k = 14 / 47
Solution: x + 2Y = 2K
Then 3x + 6y = 6K
3x+7y=k-1
Then y = 1-5k
x=2k-2y=2k-2+10k=12k-2
Because | X-Y | = 3
Then | 12k-2-1 + 5K | = | 17k-3 | = 3
17k = 6 or 17k = 0
K = 6 / 17 or K = 0
Are you satisfied with the above answers?