0.3x of 0.2 + 0.5 minus 2x of 3 = minus 2x of 3

0.3x of 0.2 + 0.5 minus 2x of 3 = minus 2x of 3

2 / 0.3x can be written as 2 / 3x, and the result remains unchanged. It is simplified that 3 / 2x + 0.5-2 / 3x equals 5 / 6x + 0.5 = - 3 / 2 / 18 / 5x. Are you sure the problem is correct?
The solution of 2x + 2 of 0.3 and 2 of 3 = 1.4-3x of 0.2 is
2x/0.3+2+2/3=(1.4-3x)/0.2
2x/(3/10)+8/3=(1.4-3x)/(1/5)
10*2x/3+8/3=5(1.4-3x)
20x/3+8/3=7-15x
20x+8=21-45x
65x=13
x=1/5
2x/0.3+2+2/3=(1.4-3x)/0.2
2x/(3/10)+8/3=(1.4-3x)/(1/5)
10*2x/3+8/3=5(1.4-3x)
20x/3+8/3=7-15x
20x+8=21-45x
65x=13
x=1/5
0.3x-1 = 2 (2x-1 / 5)
0.3x-1=2x-1/5
0.3x-2x-1/5-1=0-3x-8/10=0
X=8
If the system of inequalities 3x-3a
Both a and B are greater than 0
It's better to have a formula for the conversion of degrees, minutes and seconds,
Degrees, minutes and seconds = degrees + minutes / 60 + seconds / 3600 = degrees
3x+5=4x-3
3x+5=4x-3
4X-3X=5+3
X=8
X=8
3x+5=4x-3
X=8
X=8.
3x+5=4x-3
5+3=4x-3x
8=x
3x+5=4x-3
4x-3x=5+3
X=8
If the image of a first-order function passes through point a (0,2) and intersects point B with the image of positive scale function y = - x, and the ordinate of B is 1, then the expression of the first-order function is
The ordinate of B is 1,
By substituting y = 1 into y = - x, we get - x = 1, x = - 1
∴B(-1,1)
∵ the first-order function image passes through points a (0,2), B (- 1,1), ∵,
Let y + X be analytic
{b=2
-k+b=1
The solution is: {k = 1
B=2
The expression of the linear function is y = x + 2
Y = 1 into y = - x
We get x = - 1
Let the expression of a function be such that y = KX + B
X = - 1, y = 1, x = 0, y = 2
We get 1 = - K + B
2=b
The solution is k = 1
The expression of this function is y = x + 2
y=kx+b
2=b
y=kx+2
y=-x
Y=1
x=-1
1=-k+2
K=1
y=x+2
Solution: substituting y = 1 into y = - x, we get 1 = - x, x = - 1. Then point B is (- 1,1)
Let the linear function be y = KX + B. the image passes through a (0,2), B (- 1,1)
2=b;
1=-1k+b=-k+2,k=1.
So the expression of a function is y = x + 2
Let I = R, a = {y | y = x ^ 2-2}, B = {x | y = log2 (3-x)}, then CIA ∩ B
A
y=x²-2>=-2
So CIA = {x | x0
X
（-2x+1）*（-3x+1）
(2x-1)*(3x-1)
（-2x+1）*（-3x+1）
Senior high school mathematics series general formula, please list out, thank you~
(1) the sequence {an} satisfies A1 = 1 and an = an-1 + 3n-2 (n ≥ 2), find an. (2) the sequence {an} satisfies A1 = 1 and an = an-1 + 2n (1) (n ≥ 2), find an. (1) know an-an-1 = 3n-2 from an = an-1 + 3n-2, note f (n) = 3n-2 = An-an
Equal ratio sequence or equal difference sequence?
Accumulation method, accumulation method, reciprocal method, undetermined coefficient method, construction method, auxiliary sequence method!!