Calculation method of third order determinant

Calculation method of third order determinant

There are two ways. Please refer to the figure below carefully. If you still have any questions, please come to discuss them
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Finding the sum of all roots of equation [3x + 1] = 2x-1 / 2
Let [3x + 1] = 2x-1 / 2 = M
x=(2m+1)/4
[(6m+7)/4]=m
[3m/2+7/4]=m
Notice that M is an integer and M is eliminated on both sides
[m/2+7/4]=0
0≤m/2+7/4
If - 1 is one root of the equation 3x ^ 2 + 2x + k = 0, what is the other root and the value of K
Substitute x = - 1 into the equation
That is K + 3-2 = 0, k = - 1
The equation is: 3x ^ 2 + 2x-1 = 0
The other solution is 1 / 3
Is there any way to work out such a formula
What software or formula can be completed? For example, if I input result 2, I will list 1 + 1 = 2, 0 + 2 = 2
You see if this one meets your requirements
For the system of equations with known solutions, 3ax = 9by = 9by = 4Y
Do you have a problem with the title, 3x = y = 9, then 4 * 3-9 ≠ 5
1. According to the meaning of the title,
4X-Y=5 ①
6X+2Y=18 ②
aX+bY=-1 ③
3ax+4by =18 ④
① For * 2 + 2, 14x = 28 and x = 2 are obtained
Substituting x = 2 into (1) yields y = 3. Substituting x = 2 and y = 3 into (3) and (4) yields y = 3
2a+3b=-1 ⑤
6a+12b=18 ⑥
⑤ From * 4 - 6, 2A = - 22 and a = - 11 can be obtained
Substituting a = - 11 into 5
1. According to the meaning of the title,
4X-Y=5 ①
6X+2Y=18 ②
aX+bY=-1 ③
3ax+4by =18 ④
① For * 2 + 2, 14x = 28 and x = 2 are obtained
Substituting x = 2 into (1) yields y = 3. Substituting x = 2 and y = 3 into (3) and (4) yields y = 3
2a+3b=-1 ⑤
6a+12b=18 ⑥
⑤ From * 4 - 6, 2A = - 22 and a = - 11 can be obtained
Substituting a = - 11 into 5 gives 2 * [- 11] + 3B = - 1, and B = 7
A = - 11, B = 7
Given that the equations 4x-y = 5, ax + by = - 1 and 3x = y = 9, 3ax + 4BY = 18 have the same solution, find the value of a and B
The results are as follows
Because the solutions of the two equations are the same
From the system of equations
4x-y=5，
3x=y=9
The results are as follows
x=2 y=3
Substituting x = 2 and y = 3 into the equations:
ax+by=-1
3ax+4by=18
We get: 2A + 3B = - 1
Given that the equations 4x-y = 5, ax + by = - 1 and 3x = y = 9, 3ax + 4BY = 18 have the same solution, find the value of a and B
The results are as follows
Because the solutions of the two equations are the same
From the system of equations
4x-y=5，
3x=y=9
The results are as follows
x=2 y=3
Substitute y = 2 and x = 3
ax+by=-1
3ax+4by=18
The results show that 2A + 3B = - 1, 6a + 12b = 18,
A = - 11, B = 7,
So the value of a is - 11 and the value of B is 7
Given a function y = KX + B (K ≠ 0) when x = 1, y = 5, and the abscissa of the intersection of its image and X axis is 6, find the analytic formula of the function. It shows that the corresponding point in the coordinate plane must be on the function image if it satisfies the ordinal number pair of the function relation, otherwise, the coordinate of the point on the function image must satisfy the function relation
The coordinate of the intersection of the first-order function y = KX + B and X axis is (6, 0). According to the meaning of the question, we get K + B = 56K + B = 0, and the solution is k = - 1B = 6. Therefore, the analytic expression of the first-order function is y = - x + 6
Solving inequality: log2 (x ^ 2-2x + 2) > log2 (2x-1)
Because the base 2 is greater than 1, we can see from the image that x ^ 2-2x + 2 is greater than 2x-1, and the solution is x = 1 or x = 3
(0.5,3) and (3, infinity) ask: what is the detailed process? Master, please
It is known that the solution of the equation 5x-2m = 3x-6m + 1 about X is x, satisfying - 3 < x ≤ 2, and finding the integer value of M
By solving the equation 5x-2m = 3x-6m + 1, x = 12-2m. ∵ - 3 ∵ x ≤ 2, ∵ 12 − 2m ∵ 312 − 2m ≤ 2, the integer value of - 34 ≤ m < 134, ∵ m is 0, 1
The method of calculation (formula.)
①1+2+3+4+5+.+n
② 1 + 3 + 5 + 7 + 9 + 11 (the difference between each number is 2)
③ 1 + 2 + 4 + 7 + 11 + 16 =? (add 1,2,3 between each number)
④ 1 + 2 + 5 + 10 + 17 + 26 =? (add 1,3,5,7 between each number)
I only know that the first formula is (first term + last term) x number of terms △ 2
Is there any other formula similar to the first one?
If it's not the sum but the number one, how should it be calculated?
For example, what is the 54th number in the fourth requirement and so on? How should it be calculated?
The value of the n-th digit is 1 + (n-1) * 2. The value of the n-th digit is 1 + (1 + n) * n / 2. The fourth question is very simple. 1 + 2 + 5 + 10 + 17 + 261 2 is the square of 1 = 1, 15 is the square of 4 = 2
Given that the equations 4x-y = 5 ax + by = - 1 and 6x + 2Y = 18,3ax-4by = 18 have the same solution, find the value of A.B
By substituting the equation (2) x = 2 a x = 2 a x = 3 y = 1 4x = 5 by (3) y = 1 4x = 6 by (3) y = 1 4x = 5 by (3) y = 1 4x = 3 by (5) y = 3 by (5) y = 3 by (3) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (5) y = 3 by (3 by (5) y = 3 by (5) y = 3 by (3 by (5) y = 3 a x = 3 by (3 by (3