4X - [3x - (2x-3)], where x = 1 | 2

4X - [3x - (2x-3)], where x = 1 | 2

The original formula = 4 * 1 / 2 - (3 * 1 / 2 - (2 * 1 / 2-3)) = 2 - (3 / 2 + 2) = 2-7 / 2 = - 3 / 2
3x ^ 2 (2x ^ 2-x + 1) - x (3x ^ 3-4x ^ 2 + 2x), where x = - 1
3x^2*(2x^2-x+1)-x(3x^3-4x^2+2x)
=6x^4-3x^3+3x^2-(3x^4-4x^3+2x^2)
=3x^4+x^3+x^2
=3*1-1+1
=3
4x+2x+x-3x=12
4x+2x+x-3x=12
(4+2+1-3)x=12
4x=12
x=12/4
X=3
If you understand, take it
X=3
7x-3x=12
4x=12
X=3
6X－2X=12 4X=12 X=3
The coordinates of the intersection of the image of the first-order function y = 3x + 1 and the second-order function y = x ^ 2 + X + 1 are
Formula y = 3x + 1
Formula y = x ^ 2 + X + 1 2
Substitute Formula 1 into formula 2 to get x ^ 2-2x = 0
x(x-2)=0
X1 = O, X2 = 2 are substituted into Formula 1 to get Y1 = 1, y2 = 7
So the coordinates of the intersection points of the two images are (0,1), (2,7)
(0,1) (2,7)
Given the linear function y = KX + B, when x = 1, y = - 1, and the abscissa of the intersection of its image and X axis is - Four Thirds, then the expression is?
-1=k+b（1）
0=-4k/3+b（2）
（1）-（2）
7k/3=-1
k=-3/7
Bring in (1)
b=-4/7
therefore
y=-4x/7-3/7
The straight line y = KX + B goes through (1, - 1) and (- 4 / 3,0). So there are: K + B = - 1, - 4 / 3K + B = 0... So k = 3, B = - 4, so y = 3x-4.
Let m and n be two nonempty sets, and define M-N = {x | x ∈ m, and X does not belong to n}
(1) If a = {x | x ≥ 0, X ∈ r}, B = {x | - 5 ≤ x ≤ 10}, find b-a
(2) Find a - (a-b), B - (B-A)
A-B = {x | x > 10}
A-(A-B)={x|0
The first is to draw the number axis solution, and the second is to use Wayne diagram
The quadratic term of X is not contained in the difference of the algebraic formula 3x minus 2 times (5 + x-2x Square) plus the square of MX (m times (x square)), and the value of M is obtained
Original formula = 9x ^ 2-2 (5 + x-2x ^ 2) + MX ^ 2
=(9+4+m)x^2-2x-10
The quadratic term without x is the quadratic term of X, and the coefficient is 0, that is, 9 + 4 + M = 0,
So m = - 13
-13
Original formula = 9x ^ 2-2 (5 + x-2x ^ 2) + MX ^ 2
=(9+4+m)x^2-2x-10
So m = - 13
Original formula = 3x ^ 2-2 (5 + x-2x ^ 2) + MX ^ 2
=7x^2+mx^2-2x-10
The quadratic term without x is the quadratic term of X, and the coefficient is 0, that is, 7 + M = 0
So m = - 7
Figure area formula and area conversion learned in mathematics of grade 5 Volume 1
Parallelogram: S = ah
Triangle: S = ah △ 2
Trapezoid: (a + b) × h △ 2
S = parallelogram
Triangle: S = ah △ 2
Trapezoid: (a + b) × h △ 2
Height of parallelogram: a = s / h
The difference of solving equation 3x-1 divided by the sum of 4x + 1 = 2 / 5
We need to figure out the calculation process
3x-1/(4x+1)=2/5
3x-1 =2(4x+1)/5
3x-1 =(8x+2)/5
5(3x-1)=8X+2
15x-5 =8x+2
15x-8x =2+5
7x=7
X=1
Multiply both sides by 4x + 1, and then solve a quadratic equation of one variable
Given the intersection of the image of the first-order function y = KX + B with the x-axis and the y-axis, the coordinates are a (2.0) B (0.3) respectively
0=2k+b
3=b
k=-1.5
y=-1.5x+3
Just bring it in