Given that 2x and 3x-5 are opposite to each other, we can find the value of X

Given that 2x and 3x-5 are opposite to each other, we can find the value of X

2x+3x-5=0
5x=5
X=1
2X+3X-5=0
X=1
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If 3-2x / 4 and 3x-2 / 5 are opposite numbers, then what is x?
If the solution set of inequality a ≤ 3 / 4x & sup2; - 3x + 4 ≤ B about X is exactly [a, b], then the value of a + B is -
The answer is: when a = 0, B = 4, it happens to be true, so a + B = 4. Why?
It can be explained from the image that f (x) = 3 / 4x & sup2; - 3x + 4 itself is a parabola. Draw two straight lines parallel to the X axis, y = A and y = B. if both lines have two intersections with the parabola, then the solution set should be two intervals, so rounding off, so the line y = A should have only one or no intersection with the parabola, so a is less than
Through the point (2,2), the axis of symmetry is x = 3, the distance from the vertex to the origin is 5, find the analytic formula of quadratic function
Because the distance from the vertex to the origin is 5, so there is √ (3 ^ 2 + A ^ 2) = 5, and the solution is n = ± 4. So we can set the analytic expression of the quadratic function as y = a (x-3) ^ 2 ± 4. Because the function passes through the point (2,2), there is 2 = a (2-3) ^ 2 + 4, and the solution is a = - 22 = a (2-3) ^ 2-4, and the solution is a = 6, so the quadratic function
The known set a = {x | 0 ≤ x-m ≤ 3}, B = {x | x}
0≤x-m≤3
∴m≤x≤3+m
(1) A ∩ B = empty set
M ≥ 0 and M + 3 ≤ 3
So m = 0
（2）A∪B=B
m+33
Yield M3
A can be reduced to {m ≤ x ≤ 3 + m}
(1) A intersection B is an empty set, M = 0
(2) If a and B are B, then the range of B includes a, then M + 33, that is, M > 3 or m
Let XY satisfy the constraint conditions Y-A ≥ 0, x-5y + 10 ≥ 0, x + Y-8 ≤ 0, and the minimum value of Z = 2x-5y is - 10, then the value of a is zero
The line x-5y + 10 = 0 intersects with x + Y-8 = 0 at point a (5,3),
The line y = a intersects with x-5y + 10 = 0 and X + Y-8 = 0 at B (5a-10, a) and C (8-A, a)
By drawing a schematic diagram, we know that x-5y + 10 > = 0, and X + Y-8
Write the letter formula of trapezoid area:______ .
The area formula of trapezoid is expressed by letters: S = (a + b) × h △ 2. So the answer is: S = (a + b) × h △ 2
Solving inequality 2-4x / X & sup2; - 3x + 2 ≥ x + 1
Decomposition factor: 2 (1-2x) / (x-1) (X-2) ≥ x + 1
General score of item transfer: [2 (1-2x) - (x-1) (X-2) (x + 1)] / (x-1) (X-2) ≥ 0
It is shown that: - x (X & # 178; - 2x + 3) / (x-1) (X-2) ≥ 0 has the same solution as X (X & # 178; - 2x + 3) (x-1) (X-2) ≤ 0 (x ≠ 1, X ≠ 2)
The solution is reduced to (x) = ｛ - 2 (x) = ｛ - 1
The image symmetry axis of quadratic function y = - x2 + 6x + 3 is______ .
∵ y = - x2 + 6x + 3, a = - 1, B = 6, x = - B2A = 3, i.e. straight line x = 3
Let a = {x | 0 ＜ x-m ＜ 2}, B = {x | x ≤ 0 or X ≥ 3} respectively find the value range of real number m satisfying the following conditions: 1. A ∩ B = empty set 2. A ∪ B = B
1. From 0 ＜ x ＜ 3, m ＜ x ＜ 2 + m, so m ≤ 0, 2 + m ≥ 3, m ≥ 1, so m ≥ 1 or less than or equal to 0 2.2 + m ≤ 0, m ≤ - 2, so m ≥ 3 or less than or equal to - 2