2X+3Y=54 3X+2Y=56 X=?Y=?

2X+3Y=54 3X+2Y=56 X=?Y=?

2X + 3Y + 3x + 2Y = 5x + 5Y = 110, that is, x + y = 22
3X+2Y-2X-3Y=X-Y=2
X+Y+X-Y=22+2
2X=24
X=12
Y=12-2=10
Y=10
x=12
x=12,y=10
x=12
y=10
x=12 y=10
X=12
Y=10
X=12，y =10
Y=10.X=12
X=12，y =10
x=12,y=10
Take it
3*(2X+3Y)=162
2*(3X+2Y)=112
By subtracting, we get y = 10 and substituting it into the original formula, we get x = 12
2X + 3Y = 54 is a copy. Multiply the copy by 3 to get 6x + 9y = 162
If 3x + 2Y = 56 is two, multiply the two by 2 to get 6x + 4Y = 112
By subtracting two from one, we get 5Y = 162-112, y = 10 and x = 12
X+Y=22，X=12，Y=10
Factorization: 121 (a + b) ^ 2-169 (a-b) ^ 2
121（a+b)^2-169(a-b)^2
=(11a+11b-13a+13b)(11a+11b+13a-13b)
=(24b-2a)(24a-2b)
=4(12b-a)(12a-b)
121（a+b)^2-169(a-b)^2
=[11(a+b)-13(a-b)][11(a+b)+13(a-b)]
=(11a+11b-13a+13b)(11a+11b+13a-13b)
=(24b-2a)(24a-2b)
=4(12b-a)(12a-b）
121 = 112169 = 132, so the original formula = 112 (a + b) 2-132 (a-b) 2 = (11a + 11b) 2 - (13a-13b) 2=
(11a+11b+13a-13b)(11a+11b-13a+13b)=(24a-2b)(24b-2a)
3x + 2Y = 54 2x + 3Y = 56 find x = () y = ()
x=( 10 ) y=( 12 )
Method 1: according to one of the equations, use one of the unknown numbers to represent another number, bring in another equation to get an unknown number, and then bring in the equation to get another unknown number.
Method 2: combine the two equations: get 5x + 5Y = 90, then x = 18-y.
Take the expression of X into one of the equations (take equation 2 as an example): 2 (18-y) + 3Y = 46. Y = 10. So: x = 18-y = 18-10 = 8.
So: x = 8, y = 10. ... unfold
Method 1: according to one of the equations, use one of the unknown numbers to represent another number, bring in another equation to get an unknown number, and then bring in the equation to get another unknown number.
Method 2: combine the two equations: get 5x + 5Y = 90, then x = 18-y.
Take the expression of X into one of the equations (take equation 2 as an example): 2 (18-y) + 3Y = 46. Y = 10. So: x = 18-y = 18-10 = 8.
So: x = 8, y = 10. Put it away
The solution of the equation is x = 10, y = 12
Factorization 169 (a + b) ^ - 121 (a-b) ^ write out the whole process
=[13(a+b)+11(a-b)][13(a+b)-11(a-b)]
=(24a+2b)(2a+24b)
=4(12a+b)(a+12b)
169 is the square of 13, 121 is the square of 11, and then take each part as a whole, thinking as a whole, and then a formula of square difference. When calculating carefully, it should be a simple problem! More practice! Before solving the problem, pay more attention to observation, do not rush to answer, observation to understand, after this kind of questions are no problem!
x+y+z=15 4x+2y+3z=56
There are infinitely many solutions, but each solution has a corresponding proportional relationship,
This kind of question appeared again in the test, such as: how much did it cost to buy an apple, two peaches and a watermelon,
Then, how much is it to buy a watermelon, an apple and a peach,
In this problem, you can make one of the unknowns 0, and then get a fixed explanation. Although each number is different, its sum is fixed
I agree with the answer
There are only two equations, three unknowns, which cannot be solved
If you just need two solutions, you can directly take x as 0 and find y and Z. in this way, can you get three solutions soon
Z = 2 x 12
If there are several unknowns in the system of linear equations of one variable, at least several equations are needed to obtain the finite solution.
You have three unknowns, but only two equations. You can't get a finite number of solutions. Ask: ask for 2
Factorization 9 (a-b) & # 178; - 25 (a + b) & # 178;
Wait
To solve the system of equations X: Y: Z x = 1:2:3 x + 2Y + 3Z = 56
X=k
y=2k
z=3k
14k=56
K=4
therefore
{x=4
{y=8
{z=12
Let x = k, then y = 2K, z = 3k, because x + 2Y + 3Z = 56, so K + 4K + 9K = 56, the solution is k = 4, so Briefly
How to write 36 (a + b) & 178; - 25 factorization
36(a+b)²-25
=[6(a+b)]²-5²
=(6a+6b+5)(6a+6b-5)
X + y + Z = 2 x-2y + Z = - 1 x + 2Y + 3Z = - 1 to solve the cubic equation,
X-2y + Z = - 1, x + 2Y + 3Z = - 1 and 2x + 4Z = - 2 respectively
2X + 2Y + 2Z = 4 and x-2y + Z = - 1 of multiplying 2 on both sides of X + y + Z = 2 add 3x + 3Z = 3, that is 2x + 2Z = 2
2X + 2Z = 2 2x + 4Z = - 2 subtract left and right to get z = - 2 x = 3
Substituting any formula y = 1
x+y+z=2.......m
x-2y+z=-1.....n
x+2y+3z=-1....a
N + A: 2x + 4Z = - 2..... T
2 * m + N: x + Z = 1... Q
2q-t: z = - 2, x = 3
Substituting the values of X and Z into m, we get y = 1
Factorization: A & # 178; - 25 / 1b & # 178;
A & # 178; - 1 / 25 B & # 178;
=It can be divided into two parts;
=(a + 1B / 5) (a-1b / 5)
simple form
=A & # 178; - (B / 5) &# 178;
=(a + 5 / b) (a-5 / b)
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simple form
=A & # 178; - (B / 5) &# 178;
=(a + 5 / b) (a-5 / b)
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~If you agree with my answer, please click the "adopt as satisfactory answer" button in time~
~The mobile phone questioner can click "satisfied" in the upper right corner of the client.
~Your adoption is my driving force~~
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A & # 178; - 1 / 25 B & # 178;
=a²-(b/5)²
=(a+b/5)(a-b/5)
This paper mainly studies the square difference formula
A & # 178; - 1 / 25 B & # 178; = (a + B / 5) (a-b / 5)
a²-b²/25=a²-（b/5）²
=（a+b/5）（a-b/5）
Using the square difference formula