If ∫ (- A is the lower limit, a is the upper limit) (x-1) DX = - 4, the definite integral is used to calculate a=

If ∫ (- A is the lower limit, a is the upper limit) (x-1) DX = - 4, the definite integral is used to calculate a=

∫(-a,a)(x-1)dx=(1/2*x^2-x)|(-a,a)=-2a=-4
A=2
Factorization: - 4 + 9x & # 178;
-4+9x²
=9x²-4
=(3x+2)(3x-2)
(3x-2)(3x+2)
--4+9x^2=9x^2--4
=(3x)^2--2^2
=(3x+2)(3x--2)．
∫ upper limit 3 lower limit-1 (4x-x2) DX definite integral
Original formula = (2x ^ 2-1 / 3 * x ^ 3) | (3, - 1)
=(18-9)-(2+1/3)
=9-7/3
=20/3
9x & # 178; - 4 = 0 factorization solution equation
9x²-4=0
(3x+2)(3x-2)=0
3x + 2 = 0 or 3x-2 = 0
x1=-2/3、x2=2/3
x1=2/3.。。 x2=-2/3
x1=-2/3,x2=2/3
Finding definite integral (1n X / √ x) * DX upper limit 4 lower limit 1
Step by step integral
∫[1,4] (1n x/√x)*dx
=2∫[1,4] 1n xd√x
=2√xlnx[1,4] -2∫[1,4] √xd1n x
=8ln2-2∫[1,4] √x/xd x
=8ln2-2∫[1,4] d√x
=8ln2-4√x[1,4]
=8ln2-4
How to find the factorization of 3Y & # 178; - 5xy-y and a (a + b) (B-A) - B (a + b) (a-b)
3y²—5xy—y
=y(3y-5x-1)
a(a+b)(b—a)—b(a+b)(a—b)
=a(a+b)(b—a)+b(a+b)(b-a)
=(a+b)(a+b)(b-a)
=(a+b)²(b-a)
3y²—5xy—y=y(3y-5x-1)
a(a+b)(b—a)—b(a+b)(a—b)=a(a+b)(b—a)+b(a+b)(b—a)=(a+b)^2(b-a)
3y²—5xy—y
=y(3y-5x-1)
Solution: extract common factor
a(a+b)(b—a)—b(a+b)(a—b)
=a(a+b)(b—a)+b(a+b)(b-a)
=(a+b)(a+b)(b-a)
=(a+b)²(b-a)
Solution: extract the common factor
The upper limit of definite integral DX / (e ^ x + 1 + e ^ 3-x) is positive and infinite, and the lower limit is 0
The upper limit of definite integral DX / (e ^ x + 1 + e ^ 3-x) is positive and infinite, and the lower limit is 0
=∫(0,+∞)e^x/(e^2x+e^x+e^3)dx
=∫(0,+∞)e^x/((e^x+1/2)^2+e^3-1/4)dx
=1/√(e^3-1/4)*arctan(e^x+1/2)/√(e^3-1/4)|(0,+∞)
=π/2√(e^3-1/4)-1/√(e^3-1/4)*arctan(3/2)/√(e^3-1/4)
How much is (7y-3z) - (8y-5z),
(7y-3z)-(8y-5z)
=2z-y
It is known that the image of the quadratic function y = x & # 178; - (M-3) x + m + 6 of X intersects with X axis at two points a and B, and satisfies AB = 3. The value of M and the coordinates of points a and B are obtained
AB = | x1-x2 | = root [(x1 + x2) ^ 2-4x1x2] = root [(M-3) ^ 2-4 (M + 6)] = root [(m ^ 2-10m-15)]
So m ^ 2-10m-15 = 9
m^2-10m-24=0
The solution is m = - 2 or M = 12
M = - 2, x ^ 2-5x + 4 = 0, so (1,0), (4,0)
M = 12, x ^ 2-9x + 18 = 0, so (3,0), (6,0)
Simplification: (7y-3z) - (8y-5z)=______ .
The original formula is 7y-3z-8y + 5Z = 2z-y