Inverse function example: the inverse function of y = 2x-1 is y = 0.5x + 0.5 Example: the inverse function of y = 2x-1 is y = 0.5x + 0.5 How is it made
Exchange X and y, and then arrange it into the form of y = KX + B
Inverse function y = 2x + 3 / X-1 inverse function I want the detailed steps
Xy-y = 2x + 3 (Y-2) x = 3 + y x = (3 + y) / (Y-2) inverse function: y = (3 + x) / (X-2)
Finding the inverse function of y = 1 + LG (2x-3)
x=[10^(y-1)+3]/2
Y = LG (1-2x) inverse function and its definition domain It mainly defines the domain algorithm
Y = LG (1-2x) domain {x | x
Y = LG (1-2x), x < 0; inverse function
y=lg(1-2x)
10^y=1-2x
x=(1-10^y)/2
X1
y=lg(1-2x)>0
Inverse function y = (1-10 ^ x) / 2 x > 0
Find its inverse function: y = (2x-3) / (x + 1) (x ≠ - 1)
Inverse function is to change y into x, x into y, and then use X to represent y
The answer to the original question is as follows: y = (x + 3) / (2-x) (x ≠ 2)
The inverse function of function y = lgx and the image of function and inverse function of function y = LG 1 / X A X axis symmetry b y axis C straight line y = x symmetry D origin symmetry
The inverse function of the function y = lgx is y = 10 Λ X
The inverse function y = - 10 Λ X of the function y = LG 1 / X
Their images are symmetrical about the y-axis
B y axis
If the function image passes through the point (1,2), then the inverse function image of function y = f (4 + x) passes through the point
∵ function image crossing point (1,2) ᙽ function y = f (4 + x) image crossing point (- 3,2)
∵ the point (- 3,2) symmetric with respect to y = x is (2, - 3)
The inverse function image of function y = f (4 + x) passes through point (2, - 3)
Find the image passing point of the inverse function of function y = 1 / (x + 2) (x ≠ - 2) A(1/4,2) B(1/4,4/9) C(4,1/6) D(2,1/4)
The abscissa is replaced by Y and the ordinate is replaced by X
Option a
Who knows how to find the inverse function of y = x / 2x-1? I think liantai Youmeng is right because he has the sentence (x is not equal to 1 / 2).
Y (2x-1) = x (x is not equal to 1 / 2)
2xy-y=x
x(2y-1)=y
x=y/(2y-1)
f(x)=x/(2x-1)