Inverse function problems in senior one What is the inverse function of y = 10 to the x power + 10 to the negative x power divided by 10 to the x power - 10 to the negative x power?

Inverse function problems in senior one What is the inverse function of y = 10 to the x power + 10 to the negative x power divided by 10 to the x power - 10 to the negative x power?

Look at this question, this kind of statement - dizzy~
Like tongue twister
Here's a hint: use the x power of T = 10 instead
X = ln (under root sign (2 / (Y-1) + 1))
Definition domain: y =

If the function f (x) = x ^ 2-2ax + 1 has an inverse function in the interval [0,1] or [7,8], then what is the value range of real number a?

If there are inverse functions in the interval [0,1] or [7,8], then they are monotone functions
That is, the axis of symmetry is not in these two intervals
The axis of symmetry is x = a
So < = 7, a > = 1

Inverse function of y = 1 + 3x divided by 5-2x

X is represented by Y, and then the positions of XY are interchanged

Y = 2x / 3x-1 inverse function

y=2x/3x-1
3xy-y=2x
3xy-2x=y
（3y-2）x=y
x=y/3y-2
So y = x / 3x-2 is its inverse function

Y = 2x-3 / 3x + 1. It is better to have a process to find the inverse function

The definition domain of y = (2x-3) / (3x + 1) is x ≠ - 1 / 3
The inverse function is 2x-3 = 3YX + y (2-3y) x = y + 3  x = (y + 3) / (2-3y)
The inverse function y = (x + 3) / (2-3x) domain x ≠ 2 / 3

How to find the inverse function of y = 3x + 1 / 2x-1

Y = 3x + 1 / 2x-1 y = 7x / 2-1 replace y with X and replace x with y. The inverse function of x = 7Y / 2-1 2x = 7y-2 7Y = 2x + 2 y = 2x / 7 + 2 / 7 y = 3x + 1 / 2x-1 is: y = 2x / 7 + 2 / 7, please click "accept the answer", your adoption is my motivation,

Finding the inverse function of the function y = 3x + 1 / 2x-3

x=(3y+1)/(2y-3)
2xy-3x=3y+1
(2x-3)y=3x+1
y=(3x+1)/(2x-3)
The inverse function is itself

Given that the function f (x) = ax + B under the radical sign, there exists an inverse function y = F-1 (x), and f (- 1) = F-1 (1) = 2, find the values of real numbers a and B

f（－1）=√（-a+b）=2,-a+b=4；
f（x）=√（ax+b)》f-1（x）=【x²-b】/a
f-1（1）=【1²-b】/a=2,1-b=2a；
a=-1;b=3=

The known function f (x) = a − x If the symmetry center of the inverse function image of X − a − 1 is (- 1,3), then the value of real number a is () A. 2 B. 3 C. -3 D. -4

The function f (x) = a − x
The symmetry center of the inverse function image of X − a − 1 is (- 1,3), so the symmetry center of the original function is (3, - 1),
The function is f (x) = a − X
x−a−1＝−1+−1
X − a − 1, so a + 1 = 3, so a = 2
Therefore, a

It is known that the inverse function of function f (x) = (x-3) (AX-1) is to find the value of real number a by itself

Hello
Let y = (AX-1) / (x-3)
（x-3）y=ax-1
xy-3y=ax-1
xy-ax=3y-1
x（y-a）=3y-1
x=（3y-1）/（y-a）
Change the inverse function of the following variable
y=（3x-1）/（x-a）
The inverse function is itself
It can be solved
A=3
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