Minus 3-2x is the square of 5x. The polynomial of 3x-8 is A. 5 (square of x-x) - 11 B. The square of 5x-x-11 C. The square of - 5x + X + 11 C. 5 (square of x-x-1)

Minus 3-2x is the square of 5x. The polynomial of 3x-8 is A. 5 (square of x-x) - 11 B. The square of 5x-x-11 C. The square of - 5x + X + 11 C. 5 (square of x-x-1)

The polynomial that subtracts 3-2x equals the square of 5x + 3x-8 is a, 5 (the square of x-x) - 11

If a polynomial adds 3x squared minus 2x plus 1 to get 5x squared plus 2x minus 6, then the polynomial is equal to ()

(5x²+2x-6)-(3x²-2x+1)
=5x²+2x-6-3x²+2x-1
=2x²+4x-7

A polynomial minus 3x square - 5x + 1 equals 3x + 1, what is the polynomial equal to

Yes (3x? - 5x + 1) + (3x + 1)
=3x²-5x+1+3x+1
=3x²-2x+2

A polynomial m minus the square of - 5x + 3x is equal to the square of 5x - 6x-7

M=(-5x+3x^2)+(5x^2-6x-7)
=-5x+3x^2+5x^2-6x-7
=(3+5)x^2+(-5-6)x-7
=8x^2-11x-7

A is the square of 5x + 2x minus 1, B is the square of minus 2x minus 3x plus 5 What is a plus B? What is a minus 3B?

A + B = the square of 3x - x + 4 a-3b = the square of 11x + 11x-16

7x squared-5x + 3-2x + 3x squared-5

7x squared-5x + 3-2x + 3x squared-5
=10x²-7x-2

How to find the inverse function of function f (x) = 1 + ln (x + 2)

f(x)=1+ln(x+2)
y=1+ln(x+2)
ln(x+2)=y-1
x+2=e^(y-1)
x=-2+e^(y-1)
x. Y position exchange
y=-2+e^(x-1)
That is, the inverse function of the original function is f ^ (- 1) (x) = - 2 + e ^ (x-1)

How to find the inverse function of y = 2sin3x and y = 1 + ln (x + 2)?

The steps of inverse function y and X are x = y, y = x, y = sin3x, 3x = arcsiny, x = 1 / 3 · arcsiny, x = 1 / 3 · arcsiny, x = y = 1 / 3 · arcsinx, then multiply the 2 steps to solve the inverse trigonometric function: solve x, exchange x, y, write the inverse function

The inverse function of the function y = ln (x-1) is______ .

∵y=ln(x-1)
∴x=ey+1(y∈R),
The inverse function of the function y = ln (x-1) is y = ex + 1 (x ∈ R)
So the answer is: y = ex + 1 (x ∈ R)

Finding the inverse function of y = 2-ln (x + 1)

y=2-ln(x+1)
2-y=ln(x+1),
e^(2-y)=x+1,
x=e^(2-y)-1
y=e^(2-x)-1