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Formula for calculating the area of regular hexagon?
Area formula of regular n-polygon
S=C*r/2
C -- perimeter
R -- radius
Area formula of regular hexagon and sum of inner angles of regular hexagon
(n = (n = 720 2-type interior angle) * (n = 6)
Area formula: if the side length is a, the area formula is s = (3 root sign 3 / 2) a ^ 2
The area of an equilateral triangle is 12, and the side length of a regular hexagon is equal to half of the regular triangle Write down the formula,
It can be seen from the graph that the area of the hexagon is one and a half times that of the triangle, that is, 12 × 3 / 4 × 2 = 18
How to find the area of a regular hexagon I know it can be divided into six equilateral triangles, but I forget the area of the equilateral triangle
6(6*3√3*1/2)=54√3
You are welcome to ask
A formula for the area of a regular hexagon with a side length
A formula for the area of a regular hexagon with a side length
The area of regular hexagon is 6 × 1 / 2 × a × (√ 3 / 2) a = 3 √ 3A / 2
How to calculate the area of a regular hexagon with side length 1 S=6S'=3(√3)1²/2 How to calculate?
Connect the relative vertices and divide it into six small regular triangles
A regular hexagon with an area of 12 square meters What's the angle --|| What is the specific side length --||
A regular hexagon is composed of six equilateral triangles. The area of each equilateral triangle is 12 / 6 = 2, and the height of an equilateral triangle is √ 3 / 2 times of the length of the side. Let the side length be XX * x * √ 3 / 4 = 2x * x = 8 √ 3 / 3 = 4
The area formula of a regular hexagon: how many square meters is the area of a regular hexagon with a side length of 30 cm? How many square meters is the area of a regular hexagon with a side length of 30 cm? How to calculate the number under the root sign?
When the side length of the area formula of a regular hexagon is 30, there is an area formula s = (3 root sign 3 / 2) 30 ^ 2 = regular hexagon ruler and gauge drawing: draw a circle, make a diameter. Take the two ends of the diameter as the center of the circle, draw the circle respectively with the radius of the circle made, make four intersections, and connect the four points and the two ends of the diameter in order
Hexagon area formula No letters
Divide the hexagon into six triangles and calculate the area
The side length of a hexagon is 25 cm. What is its area?
An equilateral hexagon can be divided into two isosceles triangles and a rectangle
25 * radical 3 = length of middle rectangle,
25 / 2 = height of top triangle
therefore
(25 * radical 3 * 25 / 2) / 2 = area of a triangle
Pushing area = [(25 * root 3 * 25 / 2) / 2] * 2 + 25 * 25 * root 3
How much do you want
RELATED INFORMATIONS
- 1. It is known that the radius of circumscribed circle of regular hexagon is 2, and the area of regular hexagon is?
- 2. An equilateral triangle has a circumference of 2.4 decimeters and a height of 0.6 decimeters. Its area is () decimeters
- 3. If the perimeter of an equilateral triangle is equal to that of a circle, then their area ratio is equal to
- 4. PI 1 to 100
- 5. The circumference of a circle is fixed, and its ratio is inversely proportional to its diameter. Right or wrong? The judgment of midterm exam, I hit X
- 6. Draw the largest circle in a square with a circumference of 32 decimeters. What is the area of the circle?
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- 8. The diameter of a circle is 5 meters. What is its circumference? The ratio of circumference is 3
- 9. The position relation between circle x ^ 2 + y ^ 2-4x + 2Y + 4 = 0 and circle x ^ 2 + y ^ 2 + 2x-6y-26 = 0
- 10. Given the circle C1: x square + y square + 2x + 6y + 9 = 0 and circle C2: x square + y square - 6x + 2Y + 1 = 0, find the common tangent equation of circle C1 and circle C2
- 11. As shown in the figure, ∠ AOC: ∠ cod: ∠ BOD = 2:3:4, and a.o.b is on a straight line, OE.OF Divide ∠ AOC and ∠ BOD equally, og bisect ∠ EOF, and calculate ∠ GOF
- 12. Given the triangle ABC, the angle c is a right angle, and Ca = CB, D is the midpoint of CB, e is a point on AB, and AE = 2be, it is proved that ad is perpendicular to 2EB Using the scalar product of a plane vector, Should be AE = 2EB, verify that ad is perpendicular to CE
- 13. AB is the chord of circle O, AE, arc = BF, arc radius OE, of intersect a, B, C, D respectively, which indicates that OCD is isosceles triangle
- 14. 1. The vertical bisector of line AB is Mn, if point P is on Mn and PA = 10cm, then Pb=________ 2. On the triangle ABC, ab = AC, BC = 2, angle BAC = 30 degrees, the vertical bisectors on its three sides intersect at point O, then OA=———— 3. In the triangle ABC, ab = 7, AC = 5, ad is the center line of side BC, then the value range of ad is______
- 15. As shown in the figure, in the hexagon ABCDEF, AF ∥ CD, ab ∥ ed, ∠ a = 140 °, B = 100 °, e = 90 °. Calculate the degrees of ∠ C, ∠ D and ∠ F
- 16. As shown in the figure, it is known that AB is the diameter of ⊙ o, BC is the tangent point of point B tangent to ⊙ o, and the line AD / / OC passing through point a on ⊙ o, if OA = 2 and AD + OC = 6, then CD=
- 17. As shown in the figure, AB is the diameter of ⊙ o, ad is the chord, ∠ DBC = ∠ a, OC ⊥ BD at point E (1) It is proved that BC is tangent of ⊙ o; (2) If BD = 12, EC = 10, find the length of AD
- 18. As shown in the figure, AB is parallel to CD, ad and BC intersect at point O, EF passes through point O and intersects AB, CD at e and f respectively, and AE = DF. It is proved that O is the midpoint of EF
- 19. AB is the diameter of circle O, the chord AC is parallel to the radius OD, proving that CD = dB
- 20. It is known that AB is the diameter of circle O, BC is the tangent line of circle O, the tangent point is B, passing through point a as parallel line ad of OC, intersecting circle O with point D, connecting DC, (1) verification: CD is tangent line of circle O. (2) if radius of circle O is known 5. BC = 12, find BD