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If the point (m, n) is on the graph of function y = 2x + 1, then the value of 2m-n is () A. 2B. -2C. 1D. -1
By substituting the point (m, n) into the function y = 2x + 1, n = 2m + 1, we get 2m-n = - 1
If the focal length of the ellipse x Λ 2 / M + y ^ 2 / 4 = 1 is 2, then the value of M is?
The focal length is 2
So 2C = 2
C=1
The focus can be on the X or Y axis
|m-4|=1
So m = 5 or M = 3
If the ordinates of the intersection of the image and the Y-axis of the linear function y = 2x + m and y = - 3x + 2m + 6 are opposite to each other, then the value of M is?
Take x = 0, then we get two equations y = m; y = 2m + 6, because they are opposite numbers, - M = 2m + 6, and the solution is m = - 2
Simply, take x = 0, - M = 2m + 6 and get m = - 2
It is known from the title that negative m is equal to 2m plus 6
It is known that the two focal points of the ellipse are F1, F2, and a = 3 / 2. If the ellipse intersects a straight line through F1 at two points a and B, then the perimeter of △ abf2 is
As the title. Please (╯ 3 system) ╮
∵AB=AF1+F1B
∴AB+BF2+F2A=(AF1+F1B)+BF2+F2A
=(AF1+AF2)+(BF1+BF2)
From the definition of ellipse, AF1 + af2 = BF1 + BF2 = 2A
The perimeter is ab + BF2 + F2a = 2A + 2A = 6
Hope to adopt! If you have any questions, please ask!
When m, the image of the function y = 2x-2m-4 intersects the X axis on the negative half axis
When x = 0, y < 0
That is, y = 2 * 0-2m-4 < 0 (* means multiply sign)
The solution is m ＞ - 2
If the image of positive scale function y = KX passes through points (1, - 2), then the value of K is equal to______ .
∵ the image passes through points (1, - 2), ∵ 1 × k = - 2, and the solution is k = - 2
If the positive scale function y = KX is in the third quadrant, then K=
But the third quadrant k > 0
It is known that the image of linear function y = KX + B (k is not equal to 0) passes through point (- 1, - 5) and intersects with the image of positive scale function y = (1 / 2) x at point (2, a)
It is known that the image of the first-order function y = KX + B (k is not equal to 0) passes through the point (- 1, - 5) and intersects the image of the positive scale function y = (1 / 2) x at the point (2, a). The area of the triangle formed by the image of these two functions and the x-axis is calculated
Y = 1 when y = x / 2 and x = 2
Then y = KX + B passes (- 1. - 5) (2,1)
-5 =-k +b
1=2k+ b
k=2 b=-3
Y = 2x-3 and X axis intersect at (3 / 2,0)
S= 1/2 * 3/2 *1 =3/4
Substituting (2, a) into y = (1 / 2) x, the intersection coordinates are (2, 1)
Substituting (- 1, - 5), (2,1) into y = KX + B
The intersection of y = 2x-3 and X axis is (1.5, 0)
So s = 0.5 * 1.5 * 1 = 0.75
Why does the positive proportion function y = KX say in the book that K is not equal to 0?
When k = 0, it's not a positive proportional function, that's y = 0l, it's the x-axis, it's a constant function
If the slope is 0, the whole formula is meaningless
Positive scale function y = KX (k is not equal to o)
What is the domain? Any real number?
There are 1. Uniform motion, distance s and time is not proportional
2. The quotient of two numbers remains unchanged. Is the divisor proportional to the divisor (not 0)
The domain of definition is R. because any x can make y = KX meaningful
1. Success
2. Success
Do not understand can baidu Hi me
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