It is known that the square of ellipse x plus the square of 4Y is equal to 1 and the line y is equal to x plus M. when the line and ellipse have a common point, the value range of real number m is calculated? Don't you understand?

It is known that the square of ellipse x plus the square of 4Y is equal to 1 and the line y is equal to x plus M. when the line and ellipse have a common point, the value range of real number m is calculated? Don't you understand?

For example, each row can be regarded as an arithmetic sequence: the first row tolerance a relation is 2a, the first row number is 2 (A-1), then x (A.B) = 2 (a '- 1) + 2A (B-1) = 2 (A-1) (2b-1) 2000 = 24 * 125, let A-1 = 4, 2b-1 = 125 get (5,63) satisfied
What is the condition that M + 2 / x square + 1-m / y square equals 1 is an ellipse
1 is greater than m, greater than - 2 and M is not equal to - 0.5
When sin (quarter π - b) + cos (quarter π - b) = 5 / 1, the value of cos2b is?
Solution sin (π / 4-b) + COA (π / 4-b) = 1 / 5
√2sin(π/4-b+π/4)=1/5
√2sin(π/2-b)=1/5
cosb=√2/10
So cos2b = 2cos ^ 2b-1 = - 24 / 25
Three steps of drawing inverse scale function image
As above
1. Establish rectangular coordinate system 2. Trace point 3. Connect line
Simplification of COS (α + β) cos β + sin (α + β) sin β
RT QAQ 3Q!
According to the formula cos α · cos β = (1 / 2) [cos (α + β) + cos (α - β)] sin α · sin β = - (1 / 2) [cos (α + β) - cos (α - β)], we can get the formula = (1 / 2) [cos (α + 2 β) + cos α] -- (1 / 2) [cos (α + 2 β) - cos (α)] = cos α
You find that this is the cosine of the sum difference of the feet
cos(α+β)cosβ+sin(α+β)sinβ=cos[(α+β)-β]=cosα
Judge whether points a (- 2,7), B (1,2 / 3, - 8,2 / 5), C (1, - 14), D (2,7) are on the same inverse scale function image
Judgment point
A (- 2,7), B (1,2 / 3, - 8,2 / 5), C (1, - 14), D (2,7)
If it is on the same inverse scale function image, which points are on the same function image, and the analytic expression of the function is obtained
From (- 2) * 7 = - 14, a (- 2,7) on xy = - 14, from (1,2 / 3) * - 8,2 / 5) = - 14, B (1,2 / 3, - 8,2 / 5) on xy = - 14, from 1 * (- 14) = - 14, C (1, - 14) on xy = - 14, from 2 * 7 = 14, D (2,7) on xy = 14, a (- 2,7), B (1,2 / 3, - 8,2 / 5), C (1, - 14), D (2,7) on the same
From (- 2) * 7 = - 14, we get that a (- 2,7) is on xy = - 14,
From (1,2 / 3) * (- 8,2 / 5) = - 14, we get that B (1,2 / 3, - 8,2 / 5) is on xy = - 14,
From 1 * (- 14) = - 14, C (1, - 14) is on xy = - 14,
From 2 * 7 = 14, D (2,7) is on xy = 14
A (- 2,7), B (1,2 / 3, - 8,2 / 5), C (1, - 14), D (2,7) are on the same inverse scale function image
The analytic expression of this function is y = - 14 / X
From (- 2) * 7 = - 14, we get a (- 2,7) on xy = - 14, from (1,2 / 3) * - 8,2 / 5) = - 14, we get B (1,2 / 3, - 8,2 / 5) on xy = - 14, from 1 * (- 14) = - 14, we get C (1, - 14) on xy = - 14, from 2 * 7 = 14, we get D (2,7) on xy = 14, a (- 2,7), B (1,2 / 3, - 8,2 / 5), C (1, - 14), D (2,7) on the same inverse scale function image, the analytic formula of the function is y = - 14 / X
It is known that cos (2a-b) = - 11 / 14, sin (a-2b) = 4 √ 3 / 7,0
Because 0
The image of inverse scale function y = k: X passes through point a (2,3). Please judge whether B (1,6) is on the image of this inverse scale function
Y = K / x, through (2,3) points, substituting into the formula, we find that K is 6,
Bring B (1,6) in, left = right
So B is on this inverse scale function graph
Cos (PAI / 2 + a) sin (3 Pai / 2-B) + sin (3 Pai / 2-A) COA (3 Pai / 2-B) = - 1 / 2A belongs to (PAI / 2, PAI) B (PAI, 2 PAI) to find the value of a + B
(- Sina) (- CoSb) + (- COSA) (- SINB) = - 1 / 2, that is, sinacosb + cosasinb = - 1 / 2, sin (a + b) = - 1 / 2, a + B = 2K π - π / 6 or 2K π - 5 π / 6, K ∈ Z and a ∈ (π / 2, π), B ∈ (π, 2 π), then a + B ∈ (3 π / 2,3 π), that is, a + B = 2 π - π / 6 = 11 π / 6
Given that the image of inverse scale function y = K / X passes through point a (- 4,3), try to judge whether points B (- 1,12), C (- 2, - 6) are on the image of this function
The value of K is - 12
The function is y = - 12 / X
B. C point test
When x = - 1, y = 12, so B is on the image
When x = - 2, y = 6, so C is not on the image