The known function f (x) = asin (ω x + φ) (a > 0, ω > 0, - π / 2)

The known function f (x) = asin (ω x + φ) (a > 0, ω > 0, - π / 2)

The known function f (x) = asin (ω x + φ) (a > 0, ω > 0, - π / 2Sin α = 3 / 5)
Or cos α = 4 / 5 (α is the first quadrant angle) = = > sin α = 3 / 5
Ψ sin α + cos α = - 1 / 5 or sin α + cos α = 7 / 5
When Cos2 α = - 7 / 25, (2 α is two or three quadrant angle)
From 2 (COS α) ^ 2-1 = - 7 / 25 = >
Cos α = - 3 / 5 (α is the second quadrant angle) = = > sin α = 4 / 5
Or cos α = 3 / 5 (α is the first quadrant angle) = = > sin α = 4 / 5
Ψ sin α + cos α = 1 / 5 or sin α + cos α = 7 / 5
In conclusion, sin α + cos α = - 1 / 5 or sin α + cos α = 1 / 5 or sin α + cos α = 7 / 5
If the partial image of the function f (x) = asin (Wx + FAI) (a > 0, w > 0) is shown in the figure, then f (x)=_______ [image over (0,0), (2,2), (4,0),],
(6, - 2) point, when x = 2, there is a maximum of 2, when x = 6, there is a minimum of - 2]
A=2
T=(6-2)*2=8
w=2PI/T=PI/4
Over (0,0)
Substituting
sin(fai)=0
fai=kPI
Given 10 + 3 = x + y, where x is a positive integer and 0 < y < 1, find the opposite number of X-Y
10 + 3 = x + y, where x is a positive integer and 0 < y < 1, x = 6, y = 10 + 3-6 = 10-3, X-Y = 6 - (10-3) = 9-10, and the opposite number s of X-Y is Y-X = 10-9
Let the positive proportion function y = KX pass through the point (1, - 2), and find the value of the coefficient K
Over point (1, - 2)
When x = 1, y = - 2
So - 2 = k × 1
k=-2
Substituting x = 1, y = - 2 into the function, we get k = - 2
Given y = the square root of x-4 + the square root of 4-x + 2, find the square root of X of Y
Greater than or equal to 0 under root sign
So x-4 > = 0,4-x > = 0
X-4 and 4-x are opposite numbers
If all are greater than or equal to 0, then only all are equal to 0
So x-4 = 0
X=4
Root x-4 = 0, root 4-x = 0
So y = 0 + 0 + 2 = 2
So y ^ x = 2 ^ 4 = 16
So the square root of x ^ y = ± 4
We know that y is the inverse scale function of X and X is the positive scale function of Z
y=k1/x ,x=k2z
Take x = k2z into y = K1 / X and transform it into y = K1 / k2z
Ψ y = K1 / K2 divided by Z
Y is the inverse scale function of Z
Given the square root of X + 1 plus the square root of Y-X = 0, find the value of 2XY + 14
The process should be detailed
Because the square roots are nonnegative, if the sum of the two square roots is zero, the two square roots are zero
So x = - 1, y = - 1
So 2XY + 14 = 16
We know that the positive scale function y = 4x and the inverse scale function y = KX. (1) what is the value of K? When k is a value, there is no intersection between the two functions? (2) Can there be only one intersection of the two functions? If yes, find out the coordinates of the intersection point; if not, explain the reason
(1) The simultaneous analytic formula: y = 4xy = KX, we can get: 4x = KX, ∵ x ≠ 0, ∵ x2 = K4, if the image of two functions has two intersections, then K4 ＞ 0, the solution is: K ＞ 0; if the image of two functions has no intersection, then K4 ＜ 0, the solution is: K ＜ 0. (2) ∵ K ≠ 0, the image of two functions cannot have only one intersection
Given that the square root of X-2 is ± 2 and the cube root of Y + 3 is 3, how much is x times x-2xy + y times y?
The system of equations can be obtained from the meaning of the problem
X-2 = the square of plus or minus 2 = 4
y+3=3^3=27
So x = 6
y=24
Take x = 6, y = 24 Generation X * (x-2xy + y) * y = 6 * (2-2 * 6 * 24 + 24) * 24 = - 37152
X = 6, y = 24, so substitute = 6 * (- 258) * 24 = - 37152
If x ∈ (- ∞, 1), then the function y = x & # 178; - 2x + 2 / 2x-2
If x ∈ (- ∞, 1), then the function y = x & # 178; - 2x + 2 / 2x-2 = [(x-1) &# 178; + 1] / 2 (x-1) = (x-1) / 2 + 1 / 2 (x-1) ∵ x ∈ (- ∞, 1) ∵ 1-x > 0; ∵ (x-1) / 2 + 1 / 2 (x-1) ≥ 2 √ (x-1) / 2 × 1 / 2 (x-1) = 2 × 1 / 2 = 1; so the range is [1, + ∞). I'm glad to answer for you, skyhunter 002 will answer for you