Given the set a = {X / X less than 1} B = {X / x greater than a} a intersection B = empty set, then the value range of real number a

Given the set a = {X / X less than 1} B = {X / x greater than a} a intersection B = empty set, then the value range of real number a

Given the set a = {X / X less than 1} B = {X / x greater than a} a intersection B = empty set, then the value range of real number a
A>1
Let set a = [x  1
When x is - 4, a = 1 or 7, but why don't you verify it? I really can't understand your set B! I can only say that you can get the value of a by substituting x = - 4 into B, but you have to
A
The set M = {x | x2 + 2x-a = 0}, if Φ⊂≠ m, then the range of real number a is______ .
From Φ⊂≠ m, we can get that a ≠ ∈ x2 + 2x-a = 0 has real root ⊂ = 4 + 4A ≥ 0 ⊂ a ≥ - 1, so the answer is: a ≥ - 1
Let the image of the function y = f (x) and the image of y = x ^ 2 + 4x + 5 be symmetric about the Y axis, and f (x) has a maximum value of 10 in the interval [- 1, b] (b > - 1)
Find the value range of B
The image of the function y = f (x) and the image of y = x ^ 2 + 4x + 5 are symmetric about the Y axis,
Then f (x) = x ^ 2-4x + 5 = (X-2) ^ 2 + 1,
F (x) has a maximum value of 10 in the interval [- 1, b] (b > - 1),
Since f (- 1) = 10, f (5) = 10,
Then - 1 < B ≤ 5
1. Find the function f (x) = log2 (x ^ 2-2x + 4), when x belongs to the range of [- 2,4]. 2. The equation x ^ 2-2ax + 4 = 0, both of which are greater than 1, find the value range of A. 3. Find the function
Let g (x) = (x ^ 2-2x + 4). When x belongs to [- 2,4], G (x) is symmetric with respect to x = 1. When x = 1, G (x) has a minimum value of 3, and when x = 4 (or - 2), G (x) has a maximum value of 12, so the value range of G (x) is [3,12], and the value range of F (x) is [log3, log12] (base number is 2,). The small root is greater than 1, Δ = 4A ^ 2-16 ≥ 0, a ≤ - 2, or a ≥
If a, B and C are in equal proportion sequence, then the number of intersections between the image of function y = ax + BX + C and x-axis
a. If B and C are equal ratio sequence, then B ^ 2 = AC
The function y = ax + BX + C = 0, the discriminant of the root of the equation = B ^ 2-4ac = ac-4ac = - 3aC = - 3B ^ 2
∵ a, B, C are in equal proportion sequence,
｛ B & ｛ 178; = AC ≥ 0, and a, B, C are not 0,
∴b²-4ac＜0，
The number of intersections between the image of function y = ax + BX + C and X axis is 0
a. B ^ 2 = AC if B and C are equal ratio sequence
y=ax+bx+c
B ^ 2-4ac = B ^ 2-4b ^ 2 = - 3B ^ 2 less than 0
Focus is 0
Have you made any mistakes in this question? The function should be y = ax & # 178; + BX + C?
That's much better
From a, B, C into an equal ratio sequence, we get B & # 178; = AC, and AC > 0,
Then B & # 178; - 4ac = ac-4ac = - 3aC < 0,
So the number of intersections between the image of function f (x) = ax & # 178; + BX + C and X axis is 0
So the answer is: 0
solution
From the question set, we can see: B & # 178; = AC > 0, (AC > 0 is obvious.)
Function: y = ax & # 178; + BX + C
The discriminant is Δ = B & # 178; - 4ac = ac-4ac = - 3aC < 0
The equation AX & # 178; + BX + C = 0 about X has no real solution.
The image of the function has no intersection with the x-axis.
Finding the maximum value of the function f (x) = x2-2ax-1 in the interval [0,2]
Can a be 1 here
This topic should be discussed in categories: the value of a affects the maximum value of the function. A = 1 is only a case
The symmetry axis of the parabola is x = A. when the opening is upward, the value of a affects the left and right positions of the parabola, but does not affect the upper and lower positions of the image
The parabola can move left and right along the x-axis
A ≤ 0, maximum f (2), minimum f (0)
Zero
f（x)=(x-a)^2-1-a^2
It can be seen that it is a curve with the axis of symmetry x = A and the opening upward,
It is necessary to discuss the value range of a in three cases of A2,
In the first case, A2, [... Is expanded
f（x)=(x-a)^2-1-a^2
It can be seen that it is a curve with the axis of symmetry x = A and the opening upward,
It is necessary to discuss the value range of a in three cases of A2,
In the first case, A2, [0,2] function minus function, f (0) is the largest, f (2) is the smallest, and f (2) is the smallest
If a, B and C are in the same ratio sequence, then the function y = ax ^ 2 + BX + C is related to the x-axis______ Intersection points
Because if a, B and C are equal ratio sequence
Suppose a = 1, B = 2, C = 4
Y = x ^ 2 + 2x + 4 = (x + 2) = 0, that is, x = - 2
So there's only one intersection
Given the function f (x) = ax ^ 2 + 2ax-3 / x ^ 2 + 2x + 2, if a = 1, what is the range of F (x)?
(2) If f (x) < 0 holds for any real number x, find the value range of real number a.
First question: F (x) = (x ^ 2 + 2x-3) / (x ^ 2 + 2x + 2) = 1-5 / x ^ 2 + 2x + 2
And x ^ 2 + 2x + 2 = (x + 1) ^ 2 + 1 > = 1
So 0
If a, B and C are in an equal ratio sequence, then the number of intersections between the image of the function y = ax & # 178; + BX + C and the x-axis is?
If a, B and C are in equal proportion sequence, then B ^ 2 = AC > 0, and the root discriminant B ^ 2-4ac = - 3aC < 0
No intersection
b²=ac
Then the function discriminant is B & # 178; - 4ac = - 3B & # 178;