Mathematical master ~ formula method to help you, thank you! Thank you for your help! I'm very tired recently. I feel like I'm running out of math Mathematical formula method The title is to complete the missing items in the following complete square formula and express them in the form of square (1) The square of x minus 9x+______ Equal to________ (2) The fourth power of a + the square of 10A+______ =____________ (3) 1 minus_________ +Square of 4N=____________ (4) The square of 4x+_______ +The square of 25y=________ (5) The square of 9a, the square of B + 15ab+________ =__________ (6) The fourth power of X + the square of X+______ =______

Mathematical master ~ formula method to help you, thank you! Thank you for your help! I'm very tired recently. I feel like I'm running out of math Mathematical formula method The title is to complete the missing items in the following complete square formula and express them in the form of square (1) The square of x minus 9x+______ Equal to________ (2) The fourth power of a + the square of 10A+______ =____________ (3) 1 minus_________ +Square of 4N=____________ (4) The square of 4x+_______ +The square of 25y=________ (5) The square of 9a, the square of B + 15ab+________ =__________ (6) The fourth power of X + the square of X+______ =______

1) x²-9x+81/4=(x-9/2)²2) a^4+10a²+25=(a²+5)²3) 1-4n+4n²=(1-2n)²4) 4x²+20xy+25y²=(2x+5y)²5) 9a²b²+15ab+25/4=(3ab+5/2)²6) x^4+x²+1/4...
(1) (9 / 2) &# 178; = 81 / 4, so x & # 178; - 9x + 81 / 4 = (X-9 / 2) &# 178;
(2) (10 △ 2) &# 178; = 25, so a & # 8308; + 10A & # 178; + 25 = (A & # 178; + 5) &# 178;
(3) (4 △ 2) &# 178; = 4, so 1-4n + 4N & # 178; = (1-2n) &# 178;
(4) So 4x & # 178; + 20XY + 25... Expand
(1) (9 / 2) &# 178; = 81 / 4, so x & # 178; - 9x + 81 / 4 = (X-9 / 2) &# 178;
(2) (10 △ 2) &# 178; = 25, so a & # 8308; + 10A & # 178; + 25 = (A & # 178; + 5) &# 178;
(3) (4 △ 2) &# 178; = 4, so 1-4n + 4N & # 178; = (1-2n) &# 178;
(4) Therefore, 4x & # 178; + 20XY + 25y & # 178; = (2x + 5Y) &# 178;
(5) (15 △ 9 △ 2) &# 178; = 25 / 4, so 9A & # 178; B & # 178; + 15ab + 25 / 4 = (3AB + 5 / 2)
(6) (1 / 2) & # 178; = 1 / 4, so x & # 8308; + X & # 178; + 1 / 4 = (X & # 178; + 1 / 2) & # 178; put away
(1) x^2 - 9x +20.25 = (x - 4.5)^2
(2) a^4 +10a^2 + 25 = (a^2 + 5)^2
(3) 1 - 4n + 4n^2 = (1 - 2n)^2
(4) 4x^2 + 20xy + 25y^2 = (2x + 5y)^2
(5) 9a^2b^2 + 15ab + 6.25 = (3ab + 2.5)^2
(6) x^4 + x^2 + 0.25= (x^2 + 0.5)^2
Note: ^ is a power sign
Example: x ^ 2 is the square of X
Uncle Meixi
(1) Square of x minus 9x + (9 / 2) ^ 2__ Equal to_ (x-9/2)^2_______
(2) The fourth power of a + the square of 10A + 25=_ (a^2+5)^2___________
(3) 1 minus__ 2n___ +Square of 4N=__ (1-2n)^2__________
(4) The square of 4x+_ The square of 10xy + 25y=_ (2x+5y)^2_______
(5) The square of 9a, the square of B + 15ab + (... Expansion)
(1) Square of x minus 9x + (9 / 2) ^ 2__ Equal to_ (x-9/2)^2_______
(2) The fourth power of a + the square of 10A + 25=_ (a^2+5)^2___________
(3) 1 minus__ 2n___ +Square of 4N=__ (1-2n)^2__________
(4) The square of 4x+_ The square of 10xy + 25y=_ (2x+5y)^2_______
(5) Square of 9a, square of B + 15ab + (5 / 2) ^ 2_ =(3ab+5/2)^2
(6) The fourth power of X + the square of X+__ 1/4____ = (x^2+1/2)^2_____ Put it away
Square of sum
1) x²-9x+81/4=(x-9/2)²
2) a⁴+10a²+25=(a²+5)²
3) 1-4n+4n²=(1-2n)²
4) 4x²+20xy+25y²=(2x+5y)²
5) 9a²b²+15ab+25/4=(3ab+5/2)²
6) x⁴+x²+1/4=(x²+1/2)²
The formula and simple algorithm of equal ratio sequence in senior one mathematics
(1) A (n + 1) / an = q (n ∈ n)
(2) The general formula is: an = A1 × Q ^ (n-1);
The generalized formula is: an = am × Q ^ (n-m);
(3) Sum formula: SN = n × A1 (q = 1)
Sn = A1 (1-Q ^ n) / (1-Q) = (a1-an × q) / (1-Q) (Q ≠ 1) (q is the ratio, n is the number of terms)
(4) Nature:
① If m, N, P, Q ∈ N and M + n = P + Q, then am × an = AP × aq;
② In the equal ratio sequence, the sum of every k items in turn is still equal ratio sequence
③ If m, N, Q ∈ N and M + n = 2q, then am × an = AQ ^ 2
(5) "G is the equal proportion of a and B", "G ^ 2 = AB (g ≠ 0)"
(6) In the equal ratio sequence, the first term A1 and the common ratio Q are not zero
Note: in the above formula, an represents the nth term of the equal ratio sequence
Derivation of summation formula of equal ratio sequence: SN = a1 + A2 + a3 +... + an (common ratio is q) Q * Sn = A1 * q + A2 * q + a3 * q +... + an * q = A2 + a3 + A4 +... + a (n + 1)
Sn-q*Sn=a1-a(n+1)
(1-q)Sn=a1-a1*q^n
Sn=(a1-a1*q^n)/(1-q)
Sn=a1(1-q^n)/(1-q)
The problem of mathematical permutation and combination
In C (x, y), X is the superscript and Y is the subscript
C（1,n）+2C（2,n）+3C（3,n）+…… +nC（n,n）=n/2 × 【C0,n+C(1,n)+^+C(n
,n) 】
、、、、、、、thanks……
2*[C（1,n）+2C（2,n）+3C（3,n）+…… +nC（n,n）]=0*C(0,n)+1*C（1,n）+2C（2,n）+3C（3,n）+…… +nC（n,n）+C（1,n）+2C（2,n）+3C（3,n）+…… +nC（n,n）=[0*C(0,n)+nC（n,n）]+[1*C（1,n）+(n-1)C(n-1,n)]+.+[nC...
C（1，n）+2C（2，n）+3C（3，n）+…… +nC（n，n）
=0C(0,n)+C（1，n）+2C（2，n）+3C（3，n）+…… +nC（n，n）
Because C (0, n) = C (n, n) C (1, n) = C (n-1, n)
So = n / 2 × [C0, N + C (1, n) + ^ + C (n, n)]
It should be about 300 words. There must be stories and answers
In the evening, I saw a problem in the Olympic book: the apple trees in the orchard are three times as many as the pear trees. Master Wang fertilizes 50 apple trees and 20 pear trees every day. A few days later, all the pear trees are fertilized, but there are still 80 apple trees left without fertilization. Excuse me: how many apple trees and pear trees are there in the orchard? I am not frightened by this problem
Every day, every day, every day, every day, every day, every day, every day, every day, every day, every day, every day
Every day every day every day shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant shop assistant Dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark, dark Dark dark dark dark dark dark hungry hungry hungry hungry hungry hungry, the amount of dense, dense mother bet on the host, bet on the host, bet on the host, put away
How to express leap in four years with formula
The number of years is a multiple of 4, which is a leap year, such as 2012, 2004, 2000
So it can be expressed as 4N, where you are a natural number (0, 1, 2, 3.)
N = 500 is the year 2000
N = 502 is 2008
23 hours 56 minutes 4 seconds × 365 + 24 = 365 × 24
I don't know much about this, but it seems that the year divided by four is an integer, which is a leap year
hear nothing of
365.25-365 = 0.25 (days)
0.25x4 = 1 (day)
365 + 1 = 366 (days)
25 days more per year, 4 years is one day. So every four years there is one more day in that year, so it forms a leap year.
It must be a multiple of 400 in the whole century, not a multiple of four in the whole century
365.25 times 4 equals 1461 days
365.25 minus 365 equals 0.25 days
0.25 days multiplied by 4 equals one day
1. A rectangular farmland is 1600 meters long and 1100 meters wide. How many hectares of this farmland? The average rice yield per hectare is 12.5 kg. How many tons of rice can be harvested in this farmland?
If you know the unit conversion, this problem is very simple
1 hectare = 10000 square meters
1 ton = 1000 kg
Is it easy?
2 tons
One hectare = 10000 square meters, one ton = 1000 kg
Area = l × w = 1600 × 1100 = 1760000 M2 = 176 ha
176 × 12.5 = 2200kg = 2.2t
1600*1100/10000=16*11=176
12.5 * 176 / 1000 = 2.2 tons: your answers are all right. I asked a teacher, and he said they are all right. Your answers are all right. Who should I choose??
How many people are there in each row? How many rows are there for boys and girls
The common factor of 48 and 36 is 12
So there's a maximum of 12 people in each row
Male: 48 △ 12 = 4 (row)
Female: 36 △ 12 = 3 (row)
The greatest common factor of 48 and 36 is 12
Up to 12 people per row
At this point,
Male: 48 △ 12 = 4 rows
Female: 36 △ 12 = 3 rows
Take their common divisor 12, so there are 12 people in each row, a total of 7 rows.
Find the greatest common divisor of 48 and 36: 12
So boys 4 rows, girls 3 rows!
Five judges give a singer a score of 9.58 points on average, 9.46 points on average, and 9.66 points on average. There is a difference between the highest score and the lowest score of the singer______ Points
The lowest score: 9.46 × 4-9.58 × 3 = 9.10 (points), the highest score: 9.66 × 4-9.58 × 3 = 9.90 (points), the difference between the highest score and the lowest score: 9.90-9.10 = 0.8 (points); a: the difference between the highest score and the lowest score of this athlete is 0.8 (points). So the answer is: 0.8
All commonly used graphic formulas in Mathematics
I want the common figures in mathematics, such as the area, volume, perimeter, cylinder, triangle, quadrilateral of all figures. In a word, let me write the area, volume, perimeter formula of all figures
Triangle area = bottom × height △ 2 s = ah △ 2 rectangle area = length × width s = AB square area = side length × side length s = a ^ 2 parallelogram area = bottom × height s = ah trapezoid area = (upper bottom + lower bottom) × height △ 2 s = (a + B) × h △ 2 circle area = circumference × square of radius s = π R ^ 2 sector area = circle
All formulas of mathematical graph
Every one! The surface area, the volume
Triangle area = bottom × height △ 2 s = ah △ 2 rectangle area = length × width s = AB square area = side length × side length s = a ^ 2 parallelogram area = bottom × height s = ah trapezoid area = (upper bottom + lower bottom) × height △ 2 s = (a + B) × h △ 2 circle area = circumference × square of radius s = π R ^ 2 sector area = circle
Triangle area = bottom × height △ 2 s = ah △ 2
Rectangle area = length × width s = ab
Square area = side length × side length s = a ^ 2
Parallelogram area = bottom × height s = ah
Trapezoid area = (upper bottom + lower bottom) × height △ 2 s = (a + b) × h △ 2
Area of circle = circumference × square of radius s = π R ^ 2
Sector area = circumference × square of radius × degree of center angle △ degree of circumference s = π R ^ 2 × n △ 360
The surface of a cuboid... Unfolds
Triangle area = bottom × height △ 2 s = ah △ 2
Rectangle area = length × width s = ab
Square area = side length × side length s = a ^ 2
Parallelogram area = bottom × height s = ah
Trapezoid area = (upper bottom + lower bottom) × height △ 2 s = (a + b) × h △ 2
Area of circle = circumference × square of radius s = π R ^ 2
Sector area = circumference × square of radius × degree of center angle △ degree of circumference s = π R ^ 2 × n △ 360
Surface area of cuboid = (L × W + L × H + W × h) × 2 s = (AB + ah + BH) × 2
Surface area of cube = square of edge length × 6 s = 6A ^ 2
Cuboid volume = length × width × height v = ABH
Cube volume = cube of edge length v = a ^ 3
Side area of cylinder = perimeter of bottom surface × height s = ch = π DH = 2 π RH
Surface area of cylinder = side area + bottom area × 2 s = 2 π RH + 2 π R ^ 2
Cylinder volume = bottom area × height v = sh = π R ^ 2H
Cone volume = bottom area × height △ 3 V = sh △ 3 = π R ^ 2H △ 3 triangle area = bottom × height △ 2 s = ah △ 2
Rectangle area = length × width s = ab
Square area = side length × side length s = a ^ 2
Parallelogram area = bottom × height s = ah
Trapezoid area = (upper bottom + lower bottom) × height △ 2 s = (a + b) × h △ 2
Area of circle = circumference × square of radius s = π R ^ 2
Sector area = circumference × square of radius × degree of center angle △ degree of circumference s = π R ^ 2 × n △ 360
Cuboid