2(x+1)

2(x+1)

2(x+1)
2（x+1）
To solve the inequality (3x-6) × (x + 3) > 0·
(3X-6)×(X+3)＞0
(3X-6)×(X+3)＞0
Equivalent to:
3*(x-2)*(x+3)>0
That is:
(x-2)(x+3)>0
To make this inequality hold, two factors are the same positive or negative, that is:
1) The solution of X-2 > 0 and X + 3 > 0 is x > 2
2) x-2
6 * (3x-2) - 4 * (4x-3) = 1-8x, x = what?
6*(3x-2)-4*(4x-3)=1-8x
18x-12-16x+12=1-8x
2x=1-8x
10x=1
x=1/10
1)4x^3-8x^2+4x:2) (x-1)(x+4)-3x
1）4x^3-8x^2+4x
=4x(x^2-2x+1)
4x(x-1)^2
2) (x-1)(x+4)-3x
=x^2+3x-4-3x
=x^2-4
=(x-2)(x+2)
Given that the value of the algebraic formula 3x ^ 2-4x + 6 is 9, then x ^ 2-4 / 5 + 6 =? 10-6x ^ 2 + 8x =?
3x^2-4x+6=9
3x^2-4x=3
So x ^ 2-4x / 3 + 6 = (3x ^ 2-4x) / 3 + 6 = 3 / 3 + 6 = 7
10-6x^2+8x=10-2(3x^2+4x)=10-2*3=4
2 (3x ^ 2 + 4x + 7) = 1 (6x ^ 2 + 8x-1)
The final answer is 1, because 2 (3x ^ 2 + 4x + 7) = 2 / 8, 3x ^ 2 + 4x + 7 = 8, 3x ^ 2 + 4x-1 = 0, 6x ^ 2 + 8x-2 = 0
So 6x ^ 2 + 8x-1 = 1
Given 3x + 2x + 1 = 9, find the value of 1 / 5 {12x + 8x + 24} - 1 / 3 {6x + 4x + 8}
3x square + 2x + 1 = 93x square + 2x = 8,1 {12x square + 8x + 24} - 1 {6x square + 4x + 8} = 1 {4 (3x square + 2x) + 24} - 1 {2 (3x square + 2x) + 8} = 1 {4 (8) + 24} - 1 {2 (8) + 8} = 1 {32 + 24} - 1 {16 + 8} = 1 {66} - 1 {24} - 1 {6 + 8} = 1 {66} - 3 {5} - 1 {24} = 66-8 = 26} 5
Give it to me, ha ha
Factorization of x ^ 4 + 4x ^ 2 + 3x + 4
x^4+4x^2+3x+4
=x^4+x^3+x^2-x^3-x^2-x+4x^2+4x+4
=x^2(x^2+x+1)-x(x^2+x+1)+4(x^2+x+1)
=(x^2+x+1)(x^2-x+4)
Factorization factor X ^ 3-4x ^ 2 + 3x=
x^3-4x^2+3x
=x(x^2-4x+3)
=x(x-1)(x-3)
x^3-4x^2+3x
=x(x^2-4x+3)
=x(x-3)(x-1)
x^3-4x^2+3x
=x（x^2-4X+3）
=x（x-1）（x-3）
Hope to help you
3x-1 / 2 equals [[4x + 2] / 5] - 1
x=-1/22