-X+2x-3x+4x+… -2007x+2008x I'm in a hurry

-X+2x-3x+4x+… -2007x+2008x I'm in a hurry

The original formula = - (x 3x 5x 2007x) (2x 4x 6x … 2008x)
=-(1 2007)·1004x/2 (2 2008)·1004x/2
=1004x
x-2x+3x-4x+5x+.+2007x-2008x
-1004x
x-2x+3x-4x+5x+........+2007x-2008x
=x(1-2+3-4+5`````+2007-2008)
=x[(1-2)+(3-4+(5-6)+``````(2007-2008)]
=x(-1*1004)
=-1004x
x-2x+3x-4x+5x+........+2007x-2008x
=x(1-2+3-4+5`````+2007-2008)
=x[(1-2)+(3-4+(5-6)+``````(2007-2008)]
=x(-1*1004)
=-1004x
(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)
(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)
=(1+3+5+7…… +2009)x-(2+4+6…… +2010)x
=(1+2009)×1005x÷2-x(2+2010)×1005x÷2
=1005x÷2×(2010-2012)
=－1005x÷2×2
=-1005x
-1005x, the original formula = (x-2x) + (3x-4x) + (5x-6x) + (7x-8x) + +(2007x-2008x) + (2009x-2010x) = - 1005x, 1005 items in total,
If the algebraic formula 2x ^ 2 + 3x + 1 = 6, then the value of the algebraic formula 4x ^ 2 + 6x-10 is
If (x + m) ^ 2 = x ^ 2 + NX + 9, then M and N are
4x^2+6x-10
=2(2x^2+3x+1)-12
=2×6-12
=0
(x+m)^2=x^2+nx+9
x^2+2m+m^2=x^2+nx+9
(2m-n)x+m^2-9=0
therefore
2m-n = 0 and m ^ 2-9 = 0
The solution is m = 3, n = 6 or M = - 3, n = - 6
(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2)
There is another way: (1-4x) ^ 2 / 2x + 3 * (4x ^ 2 + 12x + 9) / (4x-1)
(1-4x)^2/（2x+3）*(4x^2+12x+9)/(4x-1)
The second question should be like this, sorry, there should be a process!
(x-1)/(x^2-5x+6)+(x-2)/(x^2-4x+3)+(x-3)/(x^2-3x+2) = (x-1)/{(x-2)(x-3)} + (x-2)/{x-1)(x-3)} + (x-3)/{(x-1)(x-2)}= { (x-1)^2 + (x-2)^2 + (x-3)^2 } / { (x-1)(x-2)(x-3) }= (x^2-2x+1+x^2-4x+4+x^2-6x+9) / ...
1、 (x-1) / (x ^ 2-5x + 6) + (X-2) / (x ^ 2-4x + 3) + (x-3) / (x ^ 2-3x + 2) = (x-1) / [(X-2) (x-3)] + (X-2) / [(x-1) (x-3)] + (x-3) / [(x-1) (X-2)] = [(x-1) ^ 2 + (X-2) ^ 2 + (x-3) / [(x-1) (X-2) (x-3)] = [(x-1) ^ 2 + (X-2) (x-3)] = (3x expand)
1、 (x-1) / / (x-2-5x-2-5x + 6 (x-2-2x-2-5x-2-4x + 3 (x-2-4x-2-3x-3) / (x-2-2-2x-2-2x-3) / / (x-2-2-5x-2-2x-2-4x-2 (x-2-4x-2-4x + 3) + (x-2-2-2-2-4x-3 (x-3-3) / / [[(x-1-2-2-2-2-2-2) (as-2-2) (x-2-2-2-3) (as (x-2-2) (x-2-2) (x-2-2-2-2) (x-2-2) (X-2) (x-2-2) (x-2-2) (X-2) (x-2-2) (x-2-2) (x-2-2) (X-2 14) / [(x-1) (X-2) (x-3)]
2、 (1-4x) ^ 2 / (2x + 3) * (4x ^ 2 + 12x + 9) / (4x-1) = - (1-4x) * (2x + 3) close
It is known that the solutions of the equations 3x-2m-1 = 0 and 3-m = 2x about X are the same. Try to find the solutions of these two equations and the value of M
3x-2m-1=0
3x=2m+1
x=(2m+1)/3
3-m=2x
x=(3-m)/2
（2m+1）/3=(3-m)/2
2(2m+1)=3(3-m)
4m+2=9-3m
M=1
x=(3-m)/2=(3-1)/2=1
x=1,m=1
x+3x++2+4x-1=33 x=?
x+3x+2+4x-1=33
8X+1=33
8X=32
X=4
Four
The solutions of the equations x-2m = - 3x + 4 and 2-m = x are opposite to each other. (1) find the value of M; (2) find the solutions of the two equations
(1) From x-2m = - 3x + 4, we get: x = 12m + 1 (2 points) according to the meaning of the question: 12m + 1 + 2-m = 0, the solution is: M = 6; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp (6 points) (2) from M = 6, the solution of the equation x-2m = - 3x + 4 is x = 12 × 6 + 1 = 3 + 1 = 4 （8...
When student a calculates an algebraic formula minus 3x-2y, he mistook it for addition, and the wrong result is 5x-3y. Please find out the correct result
The algebraic formula plus (3x-2y) equals (5x-3y). So the algebraic formula equals (5x-3y) - (3x-2y) = 5x-3y-3x + 2Y = 2x-y
The correct result is (2x-y) - (3x-2y) = 2x-y-3x + 2Y = - X-Y
What's up? Will it?
If the equation 3x + 5 = m and x-2m = 5 have the same solution, then the value of X is______ .
Solving equation 3x + 5 = m: x = m − 53; solving equation x-2m = 5: x = 2m + 5, then m − 53 = 2m + 5, then M = - 4, then x = - 3. So the answer is: - 3