-3X^2+14X-16=0 3X^2-14X+16=0 -3X^2+14X-16=0 3X^2-14X+16=0 How to simplify

-3X^2+14X-16=0 3X^2-14X+16=0 -3X^2+14X-16=0 3X^2-14X+16=0 How to simplify

The one above is two sides multiplied by - 1
Next, multiply by a cross
1 -2
3 -8
(x-2)(3x-8)=0
x1=2
x2=8/3
How to solve the equation 6x-2 / 1 = 2 / 1-1-3x / 2
6x-2/1=2/1-1-3x/2
6x-2=2-1-3x/2
15x/2=3
x=0.4
Right? I don't understand what you mean!
If the solution of the equation 1 / 2x + a = 2x-5 and 4x + 1 = 9 about X are the same, then a =?
1/2x+a=2x-5
1/2x-2x=-5-a
-3x/2=-5-a
x=(10+2a)/3
4x+1=9
4x=8
X=2
∵ the equation 1 / 2x + a = 2x-5 and 4x + 1 = 9 have the same solution
∴(10+2a)/6=2
10+2a=12
2a=2
∴a=1
Complete inelastic collision formula
It's better to ask for yourself than for others. I've worked out △ e = 1 / 2 [(m1m2v1 ^ 2) / (M1 + m2)] and don't have to answer
Completely inelastic collision means that the momentum is conserved and the loss of mechanical energy is the largest
If both of them are stationary at this time, the mechanical energy is converted into internal energy~
How to solve the equation of (3 / 4x-4.2) x = 8 △ 5,
3/4X+4.2X=5/8
9.25X=5/8
X=0.065657
Isn't this a quadratic equation of one variable?! Follow up: yiyuanyici
The derivation of several acceleration formulas in physics and the relationship between them?
How to push x = v0t + 1 / 2at2, v = V0 + at, v2-v02 = 2aX and their relationship? It's best to combine them with the diagram
Only two of the three formulas are independent, and the third formula can be derived from any two formulas
For example: use x = V0 * t + (a * T ^ 2 / 2), v = V0 + A * t to deduce V ^ 2-v0 ^ 2 = 2aX
T = (v-v0) / A is obtained from v = V0 + A * t
Substituting x = V0 * t + (a * T ^ 2 / 2), we get
X＝V0*[ （V－V0）/ a ]＋｛a* [ （V－V0）/ a ]^2 / 2 }
＝[ （V *V0－V0^2）/ a ]＋[ ( V^2－2*V *V0＋V0^2 ) / ( 2a ) ]
＝[ 2*（V *V0－V0^2）/ ( 2a ) ]＋[ ( V^2－2*V *V0＋V0^2 ) / ( 2a ) ]
＝（V ^2－V0^2）/ ( 2a )
That is v ^ 2-v0 ^ 2 = 2aX
1. The second formula v = V0 + at is independent,
It is derived from the definition of uniform velocity linear motion: a = DV / dt
According to the derivative function, the velocity change from 0 to t is deduced, a * DT = DV ∫ a * DT = ∫ V, then v = V0 + at
2. According to the second formula, we can deduce the first one
According to the distance = time * average speed, and the motion is uniform linear motion
V flat = 1 / 2 (V0 + V) = 1 / 2 (V0 + V0 + at) = V0 + 1 / 2A... Expansion
1. The second formula v = V0 + at is independent,
It is derived from the definition of uniform velocity linear motion: a = DV / dt
According to the derivative function, the velocity change from 0 to t is deduced, a * DT = DV ∫ a * DT = ∫ V, then v = V0 + at
2. According to the second formula, we can deduce the first one
According to the distance = time * average speed, and the motion is uniform linear motion
Vplane = 1 / 2 (V0 + V) = 1 / 2 (V0 + V0 + at) = V0 + 1 / 2at
So x = v0t + 1 / 2at2
3. The third formula is derived from the first and second formulas
v²=（v0+at）²=v0²+2atv0+a²t²
We get V & # 178; - V0 & # 178; = 2atv0 + A & # 178; T & # 178; = 2A * (v0t + 1 / 2at2) = 2aX
dv/dt=a;ds/dt=v;
1. DV = ADT, integral v-v0 = a (t-t0), default t0 = 0, v = V0 + at;
2. DV / dt = (DV / DS) * (DS / DT) = (VDV / DS) = a; VDV = ads, the integral is v ^ 2-v0 ^ 2 = 2As;
3. DS = VDT = (V0 + at) DT, integral s-s0 = v0t + 0.5at ^ 2, default S0 = 0, s = v0t + 1 / 2at ^ 2
The solution of the equation, 4x + 0.5x = 4.5x0.8, a number of 6 times more than 2 times the number of 3.2, find this number!
Also, how does trapezoid represent area?
4X + 0.5x = 4.5 × 0.8 (4 + 0.5) x = 4.5 × 0.84.5x = 4.5 × 0.8x = 0.8 let this number be x, then 6x - 2x = 3.2 (6 - 2) x = 3.24x = 3.2X = 3.2 △ 4x = 0.8 trapezoid area = (upper bottom + lower bottom) × height △ 2 = median line × height
4x+0.5x=4.5X0.8
4.5x=3.6
x=0.8
6x=2x+3.2
6x-2x=3.2
4x=3.2
x=0.8
4x+0.5x=4.5X0.8
4.5x=4.5*0.8
x=(4.5*0.8)/4.5
x=0.8
Let this number be X
6X-2X=3.2
4X=3.2
X=3.2/4
X=0.8
Trapezoid area = (upper bottom + lower bottom) * height / 2
4x+0.5x=4.5×0.8
4.5x=3.6
x=3.6÷4.5
x=0.8
Let this number be X
6X-2X=3.2
4X=3.2
X=3.2÷4
X=0.8
This number is 0.8
Area of trapezoid = (upper bottom + lower bottom) × height △ 2
Question 1: 4.5X = 4.5 * 0.8 x = 0.8
Question 2: 6x-2x = 3.2, x = 0.8
In the law of conservation of momentum, the velocity V1 ', V2' of complete elastic collision is derived
M1v1 + m2v2 = m1v1 '+ m2v2'1 / 2m1v1 ^ 2 + 1 / 2m2v2 ^ 2 = 1 / 2m1v1' ^ 2 + 1 / 2m2v2 '^ 2 is obtained from the formula M1 (v1-v1') = M2 (V2 '- V2). A is obtained from the formula M1 (V1 + V1') (v1-v1 ') = M2 (V2' + V2) (V2 '- V2) by comparing with the formula M1 (V1 + V1') = V2 + V2 '. B is obtained from a and B
How to solve the equation 4x-11 / 32 = 21 / 32?
It should be simple and detailed
4X=11/32+21/32
4X=1
X=1/4
11 / 32 move over
4x=1
x=0.25
4x=21/32+11/32
4x=32/32
4x=1
x=1/4
4x-11 / 32 = 21 / 32 -------- because the denominator is the same and the two fractions are equal, the molecules must be equal.
4x-11=21
4x=32
X=8
The original question is (4x-11) / 32 = 21 / 32
Or (4x) - (11 / 32) = 21 / 32
It's a little different
Velocity and invariance? Conservation of momentum energy
Just in order to find the speed, the momentum conservation formula and the energy conservation company have been working together for a long time, which is becoming more and more complicated. Finally, we have to use the root formula. Suddenly, we find that after the term is shifted, the division is very simple, and we get an intermediate equivalent relationship
V1 + V1 "= V2 + V2", that is, the sum of the velocities of two objects before and after collision is equal. What a coincidence. Does this formula have any physical meaning? What a coincidence
It's the conservation of momentum