0, 4x, x = 5, 6 are solved by equation

0, 4x, x = 5, 6 are solved by equation

1.4X=5.6/x=4
How to solve the equation 5 / 4x-12.6 = 40% x?
5/4x-12.6=40%x
1.25x-0.4x=12.6
0.85x=12.6
x=12.6÷0.85
Solve the equation: 4x square + 12x + 9 = 0 and x square - 7x-1 = 0
4X squared + 12x + 9 = 0 and X squared - 7x-1 = 0
Thank you Teacher I Speechless
4x^2+12x+9=0
(2x + 3) ^ 2 = 0, x = - 3 / 2
x^2-7x-1=0
(x-7/2)^2-1-49/4=0
(x-7/2)^2=53/4
x-7=±√53/2
x=7±√53/2
4X squared + 12x + 9 = 0
（2x+3）^2=0
x=-3/2
The square of x-7x-1 = 0
x=(7+±√51)/2
Find the recurrence formula: when n = 1, M = 1, n = 2, M = 3, n = 3, M = 5, n = 4, M = 8, n = 5, M = 11, n = 6, M = 15, n = 7, M = 19
m = Pn + c
P = (m2 - m1)/(n2 - n1)
= (3 - 1)/(2 - 1)
= 2
m = 2n + c
n = 3,m = 5
5 = 2(3) + c
c = -1
m = 2n - 1
4x square-45 = 31x to solve the equation,
4x square-45 = 31x
4x²-31x-45=0
(4x+5)(x-9)=0
So x = - 5 / 4 or 9
4x^2-31x-45=0
(4x+5)(x-9)=0
4X + 5 = 0 or X-9 = 0
X = - 5 / 4 or x = 9
4x-31x-45 = 0
(X—9）（4X—5）=0
∵X-9=0
∴X=9
∵4X-5=0
∴X=5/4
4x²-45=31x
4x²-31x-45=0
(x-9)(4x+5)=0
X-9 = 0 or 4x + 5 = 0
The solution is x = 9 or x = - 5 / 4
Recursive formula for general term formula
a(0)=0
The recurrence formula is: a (n) = a (n-1) + 8 ^ (n-1)
How to find the general term formula? I'm self-learning in this place. When I encounter this problem, I hope you don't just tell me the result. Thank you first
an-a(n-1)=8^(n-1)
So a (n-1) - A ^ (n-2) = 8 ^ (n-2)
a(n-2)-a^(n-3)=8^(n-3)
……
a3-a2=8^2
a2-a1=8^1
a1-a0=8^0
Add, same offset
an-a0=8^0+8^1+8^2+…… +8^(n-1)
On the right is an equal ratio sequence, q = 8, with n terms
So an-a1 = 8 ^ 0 * (1-8 ^ n) / (1-8) = (8 ^ n-1) / 7
a0=0
So an = (8 ^ n-1) / 7
a(n)=8^(n-1)+8^(n-2)+...+8^(0)=(8^n)-8
15x（3x-8）-4X(2X+3)=6X(4X-4)-4
X=8
X is 8
X is 8
Why don't you separate X and * from each other
I can't understand your question
Is 15x 15 times or 15x
How to get general term formula from recurrence formula
There are difference summation, parameter summation, etc
If the value of 2x2 + 3x + 7 is 8, then the value of 9-4x2-6x is 8______ .
∵ 2x2 + 3x + 7 = 8, ∵ 2x2 + 3x = 1, ∵ 9-4x2-6x = 9-2 (2x2 + 3x) = 9-2 = 7
Recursive formula for general term?
As follows:
a(n+1)=0.6an+0.2
I'm a little white
a(n+1)=0.6an+0.2
a(n+1)-0.5=0.6an-0.3=0.6(an-0.5)
So {an-0.5} is an equal ratio sequence, the first term a1-0.5, and the common ratio is 0.6
That is an-0.5 = (a1-0.5) * 0.6 ^ (n-1)
an=(a1-0.5)*0.6^(n-1)+0.5
There should be A1 =... In the title