Solve the following equation: X / 5 = 20 / 4 4x = 6 * 4

Solve the following equation: X / 5 = 20 / 4 4x = 6 * 4

x/5=20/4
x/5 = 5
x =5×5
x =25
4x=6*4
Divide both sides by 4: x = 6
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3x0.8 + 4x = 3.6, how to solve this equation
2.4+4x=3.6
4x=1.2
x=0.3
2.4+4X=3.6
4X=3.6-2.4=1.2
X=1.2÷4
X=0.3
3x0.8+4X=3.6
2.4+4X=3.6
4X=3.6-2.4
4X=1.2
X=1.2÷4
X=0.3
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4x=3.6-2.4=1.2
x=0.3
2.4+4x=3.6
4x=1.2
x=0.3
If the value of 2x2 + 3x + 7 is 8, then the value of 4x2 + 6x-9 is 8______ .
∵ 2x2 + 3x + 7 = 8, ∵ 2x2 + 3x = 1, ∵ 4x2 + 6x-9 = 2 (2x2 + 3x) - 9 = 2-9 = - 7, so the answer to this question is: - 7
Finding general term formula from recurrence formula
a(n+1)=qa(n)+pn+m
a1=1
Formula for finding general term
1) When q = 1, a (n + 1) - an = PN + man-a (n-1) = P (n-1) + m.. A2-a1 = P + man-a1 = PN (n-1) / 2 + m (n-1) an = 1 + PN (n-1) / 2 + m (n-1) 2) when Q ≠ 1, let a (n + 1) + X (n + 1) + y = Q [an + xn + y] expand the proportional sequence, and compare the coefficients, we get x = P / (Q-1), y = (P + mq-m) / (Q
If x2 + 3x-2 = 0, then the value of 2x3 + 6x2-4x is 0______ .
∵ x2 + 3x-2 = 0, ∵ x2 + 3x = 2, ∵ 2x3 + 6x2-4x = 2x (x2 + 3x-2) = 2x (2-2) = 0, so the answer is: 0
Three points a (1,2), B (3, - 2) and C (9,7) on the rectangular coordinate plane, if e and F are the three equal points of line BC, then AE · AF=______ .
According to the coordinate formula of the trisection point, e (5,1), f (7,4); AE = (4, - 1), AF = (6,2) AE · AF = 4 × 6-2 = 22, so the answer is: 22
Given x ^ 2-3x = 2x + 14, find the value of (4x ^ 3-6x ^ 2 + 2x) / (2x) - (x + 1) ^ 2 + 1
x²－3x＝2x＋14
x²－5x＝14
∴﹙4x³－6x²＋2x﹚/2x－﹙x＋1﹚²＋1
＝2x²－3x＋1－x²－2x－1＋1
＝x²－5x＋1
＝14＋1
＝15.
Don't do it with vectors
It is known that the three vertices of the parallelogram ABCD are a (- 1, - 1), B (2,0), C (3,2) to find the coordinates of vertex D
This is a junior high school math problem
C is obtained by translating B 1 to the right and 2 to the top
Then d (0,1) is the same as D (0,1)
1 / 2x (- 3x ^ 2 + 4x + 3) - 1 / 3x ^ 2 (2x-6x ^ 2), get the result
1/2x(-3x^2+4x+3)-1/3x^2(2x-6x^2)
=-3/2x³+2x²+3/2x-2/3x³+2x⁴
=2x⁴+2x²+3/2x
The center of vector ABCD is known to be o
Proof: for any point P in the plane, there is a vector PA + vector Pb + vector PC + vector PD = 4 * vector Po
It is proved that: vector PA = vector Po + vector OA, vector Pb = vector Po + vector ob, vector PC = vector Po + vector OC, vector PD = vector Po + vector OD, so vector PA + vector Pb + vector PC + vector PD = 4, vector OP + vector OA + vector ob + vector OC + vector OD, vector 0A is equivalent to vector OC, vector ob is equivalent to vector OD